In Problems 53 - 56 , (A) Graph f and g in the same coordinate system . (B) Solve f x = g x algebraically to two decimal places. (C) Solve f x > g x using parts A and B (D) Solve f x < g x using parts A and B f x = − 0.9 x 2 + 7.2 x g x = 1.2 x + 5.5 0 ≤ x ≤ 8
In Problems 53 - 56 , (A) Graph f and g in the same coordinate system . (B) Solve f x = g x algebraically to two decimal places. (C) Solve f x > g x using parts A and B (D) Solve f x < g x using parts A and B f x = − 0.9 x 2 + 7.2 x g x = 1.2 x + 5.5 0 ≤ x ≤ 8
Solution Summary: The author compares the functions f(x)=-0.9x 2+7.2x and
(B) Solve
f
x
=
g
x
algebraically to two decimal places.
(C) Solve
f
x
>
g
x
using parts
A
and
B
(D) Solve
f
x
<
g
x
using parts
A
and
B
f
x
=
−
0.9
x
2
+
7.2
x
g
x
=
1.2
x
+
5.5
0
≤
x
≤
8
Formula Formula A polynomial with degree 2 is called a quadratic polynomial. A quadratic equation can be simplified to the standard form: ax² + bx + c = 0 Where, a ≠ 0. A, b, c are coefficients. c is also called "constant". 'x' is the unknown quantity
Direction: Strictly write in 4 bond paper, because my activity
sheet is have 4 spaces. This is actually for maritime.
industry course, but I think geometry can do this.
use nautical almanac.
Sample Calculation (Amplitude- Sun):
On 07th May 2006 at Sunset, a vesel in position 10°00'N
0 10°00' W observed the sun bearing 288° by compass. Find
the
compass error.
LMT Sunset
07d
18h
13m
(+)00d
00h
40 м
LIT:
UTC Sunset:
07d
18h
53 m
added - since
longitude is
westerly
Declination Co7d 18h): N016° 55.5'
d(0.7):
(+)
00-6
N016 56.1'
Declination Sun:
Sin Amplitude Sin Declination (Los Latitude
- Sin 016° 56.1'/Cos 10°00'
= 0.295780189
Amplitude = WI. 2N (The prefix of amplitude is
named easterly if body is rising.
and westerly of body is setting.
The suffix is named came as
declination.)
True Bearing: 287.20
Compass Bearing
288.0°
Compass Error: 0.8' West
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Chapter 2 Solutions
Finite Mathematics for Business, Economics, Life Sciences, and Social Sciences (13th Edition)
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