Explanation Given: The given condition is that all the non constant solutions approach the horizontal asymptote y = 4 as x → ∞ . Consider y = 4 as a critical point which is unstable. Thus, a solution curve with an initial point either below or above the graph of the equilibrium solution y = 4 pushes away from this horizontal asymptote as x → ∞

11th Edition

ISBN: 9781337652469

Author: ZILL

Publisher: CENGAGE L

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Differential Equations

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Chapter 2.3, Problem 49E

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A linear first-order differential equation for which all nonconstant solutions approach the horizontal asymptote y=4 as x→∞.

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Chapter 2.3, Problem 48E

Chapter 2.3, Problem 50E

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FIRST CRSE.IN DIFF.EQUAT..-ACCESS

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A linear first-order differential equation for which all nonconstant solutions approach the horizontal asymptote y = 4 as x → ∞ .

Solution Summary: The author describes a linear first-order differential equation for which all non-constant solutions approach the horizontal asymptote y=4 as xto infty .

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A linear first-order differential equation for which all nonconstant solutions approach the horizontal asymptote y=4 as x→∞.

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