Physics
Physics
7th Edition
ISBN: 9780321733627
Author: Douglas C. Giancoli
Publisher: PEARSON
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Chapter 23, Problem 41P
To determine

(a) To Determine:

Object distance using a ray diagram.

To determine

(b) To Determine:

Object distance by calculation.

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A proton moves at 5.20 × 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 8.40 × 103 N/C. Ignore any gravitational effects. (a) Find the time interval required for the proton to travel 6.00 cm horizontally. 83.33 ☑ Your response differs from the correct answer by more than 10%. Double check your calculations. ns (b) Find its vertical displacement during the time interval in which it travels 6.00 cm horizontally. (Indicate direction with the sign of your answer.) 2.77 Your response differs from the correct answer by more than 10%. Double check your calculations. mm (c) Find the horizontal and vertical components of its velocity after it has traveled 6.00 cm horizontally. 5.4e5 V × Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. I + [6.68e4 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each…
(1) Fm Fmn mn Fm B W₁ e Fmt W 0 Fit Wt 0 W Fit Fin n Fmt n As illustrated in Fig. consider the person performing extension/flexion movements of the lower leg about the knee joint (point O) to investigate the forces and torques produced by muscles crossing the knee joint. The setup of the experiment is described in Example above. The geometric parameters of the model under investigation, some of the forces acting on the lower leg and its free-body diagrams are shown in Figs. and For this system, the angular displacement, angular velocity, and angular accelera- tion of the lower leg were computed using data obtained during the experiment such that at an instant when 0 = 65°, @ = 4.5 rad/s, and a = 180 rad/s². Furthermore, for this sys- tem assume that a = 4.0 cm, b = 23 cm, ß = 25°, and the net torque generated about the knee joint is M₁ = 55 Nm. If the torque generated about the knee joint by the weight of the lower leg is Mw 11.5 Nm, determine: = The moment arm a of Fm relative to the…
The figure shows a particle that carries a charge of 90 = -2.50 × 106 C. It is moving along the +y -> axis at a speed of v = 4.79 × 106 m/s. A magnetic field B of magnitude 3.24 × 10-5 T is directed along the +z axis, and an electric field E of magnitude 127 N/C points along the -x axis. Determine (a) the magnitude and (b) direction (as an angle within x-y plane with respect to +x- axis in the range (-180°, 180°]) of the net force that acts on the particle. +x +z AB 90 +y

Chapter 23 Solutions

Physics

Ch. 23 - Prob. 9QCh. 23 - Prob. 10QCh. 23 - Prob. 11QCh. 23 - You look into an aquarium and view a fish inside....Ch. 23 - Prob. 13QCh. 23 - Prob. 14QCh. 23 - A child looks into a pool to see how deep it is....Ch. 23 - Prob. 16QCh. 23 - Prob. 17QCh. 23 - Prob. 18QCh. 23 - Prob. 19QCh. 23 - Prob. 20QCh. 23 - Prob. 21QCh. 23 - Prob. 22QCh. 23 - Prob. 23QCh. 23 - Prob. 24QCh. 23 - Prob. 25QCh. 23 - Prob. 26QCh. 23 - Prob. 27QCh. 23 - Prob. 28QCh. 23 - Prob. 29QCh. 23 - Prob. 30QCh. 23 - Prob. 31QCh. 23 - Prob. 32QCh. 23 - Prob. 1MCQCh. 23 - Prob. 2MCQCh. 23 - Prob. 3MCQCh. 23 - Prob. 4MCQCh. 23 - Prob. 5MCQCh. 23 - Prob. 6MCQCh. 23 - Prob. 7MCQCh. 23 - Prob. 8MCQCh. 23 - Prob. 9MCQCh. 23 - Prob. 10MCQCh. 23 - Prob. 11MCQCh. 23 - Prob. 12MCQCh. 23 - Prob. 13MCQCh. 23 - Prob. 14MCQCh. 23 - Prob. 1PCh. 23 - Prob. 2PCh. 23 - Two plane mirrors meet at a 1350 angle, Fig....Ch. 23 - Prob. 4PCh. 23 - Prob. 5PCh. 23 - Prob. 6PCh. 23 - Suppose you are 94 cm from a plane mirror. What...Ch. 23 - A solar cooker, really a concave mirror pointed at...Ch. 23 - How far from a concave mirror (radius 21.0 cm)...Ch. 23 - A small candle is 38 cm from a concave mirror...Ch. 23 - An object 3.0 mm high is placed 16 cm from a...Ch. 23 - A dentist wants a small mirror that, when 2.00 cm...Ch. 23 - You are standing 3.4 m from a convex security...Ch. 23 - The image of a distant tree is virtual and very...Ch. 23 - Prob. 15PCh. 23 - Prob. 16PCh. 23 - Prob. 17PCh. 23 - Some rearview mirrors produce images of cars to...Ch. 23 - Prob. 19PCh. 23 - Prob. 20PCh. 23 - Prob. 21PCh. 23 - Prob. 22PCh. 23 - Prob. 23PCh. 23 - Prob. 24PCh. 23 - Prob. 25PCh. 23 - Prob. 26PCh. 23 - Prob. 27PCh. 23 - Prob. 28PCh. 23 - Prob. 29PCh. 23 - Prob. 30PCh. 23 - Rays of the Sunare seen to make a 36.0° angle to...Ch. 23 - Prob. 32PCh. 23 - A beam of light in air strikes a slab of glass (n...Ch. 23 - Prob. 34PCh. 23 - Prob. 35PCh. 23 - Prob. 36PCh. 23 - Prob. 37PCh. 23 - Prob. 38PCh. 23 - 39. (Ill) (a) What is the minimum index of...Ch. 23 - 40. (Ill) A beam of light enters the end of an...Ch. 23 - Prob. 41PCh. 23 - Prob. 42PCh. 23 - Prob. 43PCh. 23 - Prob. 44PCh. 23 - Prob. 45PCh. 23 - Prob. 46PCh. 23 - A stamp collector uses a converging lens with...Ch. 23 - Prob. 48PCh. 23 - Prob. 49PCh. 23 - Prob. 50PCh. 23 - Prob. 51PCh. 23 - Prob. 52PCh. 23 - Prob. 53PCh. 23 - Prob. 54PCh. 23 - Prob. 55PCh. 23 - Prob. 56PCh. 23 - Prob. 57PCh. 23 - A diverging lens with f= -36.5 cm is placed 14.0...Ch. 23 - Prob. 59PCh. 23 - Prob. 60PCh. 23 - Two lenses, one converging with focal length 20.0...Ch. 23 - Prob. 62PCh. 23 - A double concave lens has surface radii of 33.4 cm...Ch. 23 - Prob. 64PCh. 23 - Prob. 65PCh. 23 - Prob. 66PCh. 23 - Prob. 67PCh. 23 - Prob. 68PCh. 23 - Prob. 69GPCh. 23 - Prob. 70GPCh. 23 - Prob. 71GPCh. 23 - The critical angle of a certain piece of plastic...Ch. 23 - Prob. 73GPCh. 23 - Prob. 74GPCh. 23 - Prob. 75GPCh. 23 - Prob. 76GPCh. 23 - 77 77. If the apex of a prism is ? = 75o (see...Ch. 23 - Prob. 78GPCh. 23 - Prob. 79GPCh. 23 - Prob. 80GPCh. 23 - Prob. 81GPCh. 23 - Prob. 82GPCh. 23 - Prob. 83GPCh. 23 - Figure 23-65is a photograph of an eyeball with the...Ch. 23 - Prob. 85GPCh. 23 - Prob. 86GPCh. 23 - 87 ‘(a) Show that if two thin lenses of focal...Ch. 23 - Prob. 88GPCh. 23 - Prob. 89GPCh. 23 - Prob. 90GP
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Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY