Explanation Given information: The given values are, θ = 60 ∘ A = 0.2 m 2 B = 1.5 × 10 − 3 T Formula used: Magnetic flux Φ , is given by, Φ = BA cos θ Where B is the magnetic field strength over an area A at an angle θ . Unit of magnetic flux F is given by Tm 2 . It is known that magnetic flux is given by, Magnetic flux Φ = BA cos θ Substitute all the values θ = 60 ∘ ,A = 0.2 m 2 ,B = 1.5 × 10 − 3 T in the above equation Φ = 1

2nd Edition

ISBN: 9781711470832

Author: OpenStax

Publisher: XANEDU

See similar textbooks

Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequen…

Videos

Question

Chapter 23, Problem 2TP

To determine

Themagnetic flux of a coil and the angle at which the flux will be maximum.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 23, Problem 1TP

Chapter 23, Problem 3TP

Students have asked these similar questions

Given two particles with Q = 4.40-µC charges as shown in the figure below and a particle with charge q = 1.40 ✕ 10−18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞.) Three positively charged particles lie along the x-axis of the x y coordinate plane.Charge q is at the origin.Charge Q is at (0.800 m, 0).Another charge Q is at (−0.800 m, 0).(a)What is the net force (in N) exerted by the two 4.40-µC charges on the charge q? (Enter the magnitude.) N(b)What is the electric field (in N/C) at the origin due to the two 4.40-µC particles? (Enter the magnitude.) N/C(c)What is the electrical potential (in kV) at the origin due to the two 4.40-µC particles? kV(d)What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 4.40-µC particles?

(a) Where does an object need to be placed relative to a microscope in cm from the objective lens for its 0.500 cm focal length objective to produce a magnification of -25? (Give your answer to at least three decimal places.) 0.42 × cm (b) Where should the 5.00 cm focal length eyepiece be placed in cm behind the objective lens to produce a further fourfold (4.00) magnification? 15 × cm

In a LASIK vision correction, the power of a patient's eye is increased by 3.10 D. Assuming this produces normal close vision, what was the patient's near point in m before the procedure? (The power for normal close vision is 54.0 D, and the lens-to-retina distance is 2.00 cm.) 0.98 x m

Chapter 23 Solutions

COLLEGE PHYSICS

Ch. 23 - How do the multiple-loop coils and iron ring in...Ch. 23 - When a magnet is thrust into a coil as in Figure...Ch. 23 - Explain how magnetic flux can be zero when the...Ch. 23 - Is an emf induced in the coil in Figure 23.54 when...Ch. 23 - A person who works with large magnets sometimes...Ch. 23 - A particle accelerator sends highvelocity charged...Ch. 23 - Why must pan of the circuit be moving relative to...Ch. 23 - A powerful induction cannon can be made by placing...Ch. 23 - An induction slave heats a pot with a coil...Ch. 23 - Explain how you could thaw out a frozen water pipe...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Themagnetic flux of a coil and the angle at which the flux will be maximum.

Solution Summary: The author explains the topicgnetic flux of a coil and the angle at which the flux will be maximum.

Concept explainers

Videos

Themagnetic flux of a coil and the angle at which the flux will be maximum.

Want to see the full answer?

Chapter 23 Solutions