CHEM:ATOM FOC 2E CL (TEXT)
CHEM:ATOM FOC 2E CL (TEXT)
2nd Edition
ISBN: 9780393284218
Author: Stacey Lowery Bretz, Natalie Foster, Thomas R. Gilbert, Rein V. Kirss
Publisher: WW Norton & Co
Question
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Chapter 23, Problem 23.82QA
Interpretation Introduction

To calculate:

The equilibrium constant of the reaction

Hgcysteine+2+glycine  Hgglycine+2+cysteine

Expert Solution & Answer
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Answer to Problem 23.82QA

Solution:

The equilibrium constant of the reaction is 1.26 ×10-4.

Explanation of Solution

1) Concept:

The logarithm of formation constant of Hgcysteine+2 is given, and the logarithm of formation constant of Hgglycine+2 is also given. If we reverse the first reaction and add to the second reaction, we get the desired reaction:

Hgcysteine+2+glycine  Hgglycine+2+cysteine

When we reverse any reaction, the equilibrium constant for the reverse reaction is the reciprocal of the equilibrium constant for the forward reaction.

If we add two reactions, then the equilibrium constant for the resultant reaction is the product of the equilibrium constants of those two reactions.

2) Given:

i) logKfHgcysteine+2=14.2

ii) logKfHgglycine+2=10.3

3) Calculations:

The formation constants are given in logarithm form. Therefore, we have to remove the logarithm to calculate the equilibrium constant.

For Hgcysteine+2, the formation constant is

 KfHgcysteine+2=1014.2

 KfHgcysteine+2=1.58489 ×1014

For Hgglycine+2, the formation constant is

 KfHgglycine+2= 1010.3

 KfHgglycine+2=1.9952 ×1010

Reversing the first reaction, we get

Hgcysteine+2 Hg+2+cysteine

Kreverse= 1KfHgcysteine+2= 11.58489 ×1014=6.3095×10-15

Adding this to the second reaction, we get

Hgcysteine+2 Hg+2+cysteine               K= 6.3095×10-15            

Hg+2+glycine Hgglycine+2                  K=  1.995 2×1010

----------------------------------------------------------------------------------------------

Hgcysteine+2+glycine  Hgglycine+2+cysteine     

The equilibrium constant of the resultant reaction is the product of the two equilibrium constants:

Keq=6.3095×10-15 ×1.995 ×1010

Keq=1.2588×10-4

Thus, the equilibrium constant of the resultant reaction is  1.26×10-4.

Conclusion:

The equilibrium constant of the resultant reaction is determined by using the Kf values for the given reactions.

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Chapter 23 Solutions

CHEM:ATOM FOC 2E CL (TEXT)

Ch. 23 - Prob. 23.11VPCh. 23 - Prob. 23.12VPCh. 23 - Prob. 23.13QACh. 23 - Prob. 23.14QACh. 23 - Prob. 23.15QACh. 23 - Prob. 23.16QACh. 23 - Prob. 23.17QACh. 23 - Prob. 23.18QACh. 23 - Prob. 23.19QACh. 23 - Prob. 23.20QACh. 23 - Prob. 23.21QACh. 23 - Prob. 23.22QACh. 23 - Prob. 23.23QACh. 23 - Prob. 23.24QACh. 23 - Prob. 23.25QACh. 23 - Prob. 23.26QACh. 23 - Prob. 23.27QACh. 23 - Prob. 23.28QACh. 23 - Prob. 23.29QACh. 23 - Prob. 23.30QACh. 23 - Prob. 23.31QACh. 23 - Prob. 23.32QACh. 23 - Prob. 23.33QACh. 23 - Prob. 23.34QACh. 23 - Prob. 23.35QACh. 23 - Prob. 23.36QACh. 23 - Prob. 23.37QACh. 23 - Prob. 23.38QACh. 23 - Prob. 23.39QACh. 23 - Prob. 23.40QACh. 23 - Prob. 23.41QACh. 23 - Prob. 23.42QACh. 23 - Prob. 23.43QACh. 23 - Prob. 23.44QACh. 23 - Prob. 23.45QACh. 23 - Prob. 23.46QACh. 23 - Prob. 23.47QACh. 23 - Prob. 23.48QACh. 23 - Prob. 23.49QACh. 23 - Prob. 23.50QACh. 23 - Prob. 23.51QACh. 23 - Prob. 23.52QACh. 23 - Prob. 23.53QACh. 23 - Prob. 23.54QACh. 23 - Prob. 23.55QACh. 23 - Prob. 23.56QACh. 23 - Prob. 23.57QACh. 23 - Prob. 23.58QACh. 23 - Prob. 23.59QACh. 23 - Prob. 23.60QACh. 23 - Prob. 23.61QACh. 23 - Prob. 23.62QACh. 23 - Prob. 23.63QACh. 23 - Prob. 23.64QACh. 23 - Prob. 23.65QACh. 23 - Prob. 23.66QACh. 23 - Prob. 23.67QACh. 23 - Prob. 23.68QACh. 23 - Prob. 23.69QACh. 23 - Prob. 23.70QACh. 23 - Prob. 23.71QACh. 23 - Prob. 23.72QACh. 23 - Prob. 23.73QACh. 23 - Prob. 23.74QACh. 23 - Prob. 23.75QACh. 23 - Prob. 23.76QACh. 23 - Prob. 23.77QACh. 23 - Prob. 23.78QACh. 23 - Prob. 23.79QACh. 23 - Prob. 23.80QACh. 23 - Prob. 23.81QACh. 23 - Prob. 23.82QACh. 23 - Prob. 23.83QACh. 23 - Prob. 23.84QACh. 23 - Prob. 23.85QACh. 23 - Prob. 23.86QACh. 23 - Prob. 23.87QACh. 23 - Prob. 23.88QACh. 23 - Prob. 23.89QACh. 23 - Prob. 23.90QACh. 23 - Prob. 23.91QACh. 23 - Prob. 23.92QACh. 23 - Prob. 23.93QACh. 23 - Prob. 23.94QACh. 23 - Prob. 23.95QACh. 23 - Prob. 23.96QA
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