Chemistry: An Atoms-Focused Approach (Second Edition)
Chemistry: An Atoms-Focused Approach (Second Edition)
2nd Edition
ISBN: 9780393614053
Author: Thomas R. Gilbert, Rein V. Kirss, Stacey Lowery Bretz, Natalie Foster
Publisher: W. W. Norton & Company
Question
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Chapter 23, Problem 23.81QA
Interpretation Introduction

To calculate:

The equilibrium constant of the reaction

Hgmethionine+2+penicillamine  Hgpenicillamine+2+methionine  

Expert Solution & Answer
Check Mark

Answer to Problem 23.81QA

Solution:

The equilibrium constant of the reaction is 126.

Explanation of Solution

1) Concept:

The logarithm of formation constant of Hgmethionine+2 is given, and the logarithm of formation constant of Hgpenicillamine+2 is also given. If we reverse the first reaction and add to the second reaction, we get the desired reaction:

 Hgmethionine+2+penicillamine  Hgpenicillamine+2+methionine     

When we reverse any reaction, the equilibrium constant for the reverse reaction is the reciprocal of the equilibrium constant for the forward reaction.

If we add two reactions, then the equilibrium constant for the resultant reaction is the product of the equilibrium constants of those two reactions.

 

2) Given:

i) logKfHgmethionine+2=14.2

ii) logKfHgpenicillamine+2=16.3

3) Calculations:

The formation constants are given in logarithm form. Therefore, we have to remove the logarithm to calculate the equilibrium constant.

For Hgmethionine+2, the formation constant is

 KfHgmethionine+2=1014.2

 KfHgmethionine+2=1.58489 ×1014

For Hgpenicillamine+2, the formation constant is

 KfHgpenicillamine+2= 1016.3

 KfHgpenicillamine+2=1.995 ×1016

Reversing the first reaction, we get

Hgmethionine+2 Hg+2+methionine 

Kreverse= 1KfHgmethionine+2= 11.58489 ×1014=6.3095×10-15

Adding this to the second reaction, we get

Hgmethionine+2 Hg+2+methionine               K= 6.3095×10-15            

Hg+2+penicillamine Hgpenicillamine+2       K=  1.995 ×1016           

----------------------------------------------------------------------------------------------

Hgmethionine+2+penicillamine  Hgpenicillamine+2+methionine     

The equilibrium constant of the resultant reaction is the product of the two equilibrium constants:

Keq=6.3095×10-15 ×1.995 ×1016

Keq=125.87

Thus, the equilibrium constant of the resultant reaction is  126.

Conclusion:

The equilibrium constant of the resultant reaction is determined by using the Kf values for the given reactions.

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Chapter 23 Solutions

Chemistry: An Atoms-Focused Approach (Second Edition)

Ch. 23 - Prob. 23.11VPCh. 23 - Prob. 23.12VPCh. 23 - Prob. 23.13QACh. 23 - Prob. 23.14QACh. 23 - Prob. 23.15QACh. 23 - Prob. 23.16QACh. 23 - Prob. 23.17QACh. 23 - Prob. 23.18QACh. 23 - Prob. 23.19QACh. 23 - Prob. 23.20QACh. 23 - Prob. 23.21QACh. 23 - Prob. 23.22QACh. 23 - Prob. 23.23QACh. 23 - Prob. 23.24QACh. 23 - Prob. 23.25QACh. 23 - Prob. 23.26QACh. 23 - Prob. 23.27QACh. 23 - Prob. 23.28QACh. 23 - Prob. 23.29QACh. 23 - Prob. 23.30QACh. 23 - Prob. 23.31QACh. 23 - Prob. 23.32QACh. 23 - Prob. 23.33QACh. 23 - Prob. 23.34QACh. 23 - Prob. 23.35QACh. 23 - Prob. 23.36QACh. 23 - Prob. 23.37QACh. 23 - Prob. 23.38QACh. 23 - Prob. 23.39QACh. 23 - Prob. 23.40QACh. 23 - Prob. 23.41QACh. 23 - Prob. 23.42QACh. 23 - Prob. 23.43QACh. 23 - Prob. 23.44QACh. 23 - Prob. 23.45QACh. 23 - Prob. 23.46QACh. 23 - Prob. 23.47QACh. 23 - Prob. 23.48QACh. 23 - Prob. 23.49QACh. 23 - Prob. 23.50QACh. 23 - Prob. 23.51QACh. 23 - Prob. 23.52QACh. 23 - Prob. 23.53QACh. 23 - Prob. 23.54QACh. 23 - Prob. 23.55QACh. 23 - Prob. 23.56QACh. 23 - Prob. 23.57QACh. 23 - Prob. 23.58QACh. 23 - Prob. 23.59QACh. 23 - Prob. 23.60QACh. 23 - Prob. 23.61QACh. 23 - Prob. 23.62QACh. 23 - Prob. 23.63QACh. 23 - Prob. 23.64QACh. 23 - Prob. 23.65QACh. 23 - Prob. 23.66QACh. 23 - Prob. 23.67QACh. 23 - Prob. 23.68QACh. 23 - Prob. 23.69QACh. 23 - Prob. 23.70QACh. 23 - Prob. 23.71QACh. 23 - Prob. 23.72QACh. 23 - Prob. 23.73QACh. 23 - Prob. 23.74QACh. 23 - Prob. 23.75QACh. 23 - Prob. 23.76QACh. 23 - Prob. 23.77QACh. 23 - Prob. 23.78QACh. 23 - Prob. 23.79QACh. 23 - Prob. 23.80QACh. 23 - Prob. 23.81QACh. 23 - Prob. 23.82QACh. 23 - Prob. 23.83QACh. 23 - Prob. 23.84QACh. 23 - Prob. 23.85QACh. 23 - Prob. 23.86QACh. 23 - Prob. 23.87QACh. 23 - Prob. 23.88QACh. 23 - Prob. 23.89QACh. 23 - Prob. 23.90QACh. 23 - Prob. 23.91QACh. 23 - Prob. 23.92QACh. 23 - Prob. 23.93QACh. 23 - Prob. 23.94QACh. 23 - Prob. 23.95QACh. 23 - Prob. 23.96QA
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