The formulae for each of the given systematic names to be predicted. Concept Introduction: The cation is named before the anion. Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception). When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number. The oxidation number of the metal is represented in roman numerals immediately following the metal ion name. If the complex ion is an anion, the metal name should end with –ate. To Identify: The formulae for each of the given systematic names to be predicted.

Question

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Answer 1

Question

Chapter 23, Problem 23.17QP

(a)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(a)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Zn(OH)4]2−$

Explanation of Solution

Predict the formula of $tetrahydroxozincate(II).$

$1) The ligands ; 2)oxidation state of Zn is : +2 .tetrahydroxo→represented as (OH)4.Zincate→ represented as Zn3)consider,[Zn(OH)4]xoverall charge of complex ion = x ; oxidation number of Zn =+2charge of (OH)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Zn(OH)4]2−.$

The formula is $[Zn(OH)4]2−$ . The overall charge of the complex ion is $(−2)$ ,because the Ligand $hydroxo$ has a charge of $(−1)$ .

(b)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

a) The cation is named before the anion.

b) Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

c) When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

d) The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

e) If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(b)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cr(H2O)5Cl] Cl2$

Explanation of Solution

Predict the formula of $penta-aquachlorochromium(III) chloride.$

$1) The ligands ; 2)oxidation state of Cr is : +3.penta-aqua→represented as (H2O)5chloro→ represented as Cl.3)Consider,[Cr(H2O)5Cl]x Clxoverall charge of complex ion = x ; oxidation number of Cr =+3charge of (H2O)ligand = (0) ; charge of (Cl)ligand = (-1)3 + (-1) = 22 = xThus , the formula is [Cr(H2O)5Cl] Cl2.$

The formula is $[Cr(H2O)5Cl] Cl2$ . The overall charge of the complex ion is $(+2)$ ,because the Ligand $chloro$ has a charge of $(−1)$ .

(c)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(c)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cu(Br)4]2−$

Explanation of Solution

Predict the formula of $tetrabromo-cuprate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.tetra-bromo→ represented as Br4.cuprate (metal anion)→represented as Cu.3)Consider,[CuBr4]xoverall charge of complex ion = x ; oxidation number of Cu =+2charge of (Br)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Cu(Br)4] 2−.$

The formula is $[Cu(Br)4]2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $Bromo$ has a charge of $(−1)$ .

(d)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(d)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Fe(EDTA)] 2−$

Explanation of Solution

Find the formula for $ethylenediaminetetraacetatoferrate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.ethylenediaminetetraacetato→ represented as EDTA.ferrate (metal anion)→represented as Fe.3)Consider,[Fe(EDTA)]xoverall charge of complex ion = x ; oxidation number of Fe =+2charge of (EDTA)ligand = (-4)2 + (-4) = x-2 = xThus , the formula is [Fe(EDTA)] 2−.$

The formula is $[Fe(EDTA)] 2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $EDTA$ has a charge of $(−4)$

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Answer 2

Question

Chapter 23, Problem 23.17QP

(a)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(a)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Zn(OH)4]2−$

Explanation of Solution

Predict the formula of $tetrahydroxozincate(II).$

$1) The ligands ; 2)oxidation state of Zn is : +2 .tetrahydroxo→represented as (OH)4.Zincate→ represented as Zn3)consider,[Zn(OH)4]xoverall charge of complex ion = x ; oxidation number of Zn =+2charge of (OH)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Zn(OH)4]2−.$

The formula is $[Zn(OH)4]2−$ . The overall charge of the complex ion is $(−2)$ ,because the Ligand $hydroxo$ has a charge of $(−1)$ .

(b)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

a) The cation is named before the anion.

b) Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

c) When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

d) The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

e) If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(b)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cr(H2O)5Cl] Cl2$

Explanation of Solution

Predict the formula of $penta-aquachlorochromium(III) chloride.$

$1) The ligands ; 2)oxidation state of Cr is : +3.penta-aqua→represented as (H2O)5chloro→ represented as Cl.3)Consider,[Cr(H2O)5Cl]x Clxoverall charge of complex ion = x ; oxidation number of Cr =+3charge of (H2O)ligand = (0) ; charge of (Cl)ligand = (-1)3 + (-1) = 22 = xThus , the formula is [Cr(H2O)5Cl] Cl2.$

The formula is $[Cr(H2O)5Cl] Cl2$ . The overall charge of the complex ion is $(+2)$ ,because the Ligand $chloro$ has a charge of $(−1)$ .

(c)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(c)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cu(Br)4]2−$

Explanation of Solution

Predict the formula of $tetrabromo-cuprate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.tetra-bromo→ represented as Br4.cuprate (metal anion)→represented as Cu.3)Consider,[CuBr4]xoverall charge of complex ion = x ; oxidation number of Cu =+2charge of (Br)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Cu(Br)4] 2−.$

The formula is $[Cu(Br)4]2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $Bromo$ has a charge of $(−1)$ .

(d)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(d)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Fe(EDTA)] 2−$

Explanation of Solution

Find the formula for $ethylenediaminetetraacetatoferrate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.ethylenediaminetetraacetato→ represented as EDTA.ferrate (metal anion)→represented as Fe.3)Consider,[Fe(EDTA)]xoverall charge of complex ion = x ; oxidation number of Fe =+2charge of (EDTA)ligand = (-4)2 + (-4) = x-2 = xThus , the formula is [Fe(EDTA)] 2−.$

The formula is $[Fe(EDTA)] 2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $EDTA$ has a charge of $(−4)$

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Answer 3

Question

Chapter 23, Problem 23.17QP

(a)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(a)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Zn(OH)4]2−$

Explanation of Solution

Predict the formula of $tetrahydroxozincate(II).$

$1) The ligands ; 2)oxidation state of Zn is : +2 .tetrahydroxo→represented as (OH)4.Zincate→ represented as Zn3)consider,[Zn(OH)4]xoverall charge of complex ion = x ; oxidation number of Zn =+2charge of (OH)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Zn(OH)4]2−.$

The formula is $[Zn(OH)4]2−$ . The overall charge of the complex ion is $(−2)$ ,because the Ligand $hydroxo$ has a charge of $(−1)$ .

(b)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

a) The cation is named before the anion.

b) Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

c) When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

d) The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

e) If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(b)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cr(H2O)5Cl] Cl2$

Explanation of Solution

Predict the formula of $penta-aquachlorochromium(III) chloride.$

$1) The ligands ; 2)oxidation state of Cr is : +3.penta-aqua→represented as (H2O)5chloro→ represented as Cl.3)Consider,[Cr(H2O)5Cl]x Clxoverall charge of complex ion = x ; oxidation number of Cr =+3charge of (H2O)ligand = (0) ; charge of (Cl)ligand = (-1)3 + (-1) = 22 = xThus , the formula is [Cr(H2O)5Cl] Cl2.$

The formula is $[Cr(H2O)5Cl] Cl2$ . The overall charge of the complex ion is $(+2)$ ,because the Ligand $chloro$ has a charge of $(−1)$ .

(c)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(c)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cu(Br)4]2−$

Explanation of Solution

Predict the formula of $tetrabromo-cuprate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.tetra-bromo→ represented as Br4.cuprate (metal anion)→represented as Cu.3)Consider,[CuBr4]xoverall charge of complex ion = x ; oxidation number of Cu =+2charge of (Br)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Cu(Br)4] 2−.$

The formula is $[Cu(Br)4]2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $Bromo$ has a charge of $(−1)$ .

(d)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(d)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Fe(EDTA)] 2−$

Explanation of Solution

Find the formula for $ethylenediaminetetraacetatoferrate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.ethylenediaminetetraacetato→ represented as EDTA.ferrate (metal anion)→represented as Fe.3)Consider,[Fe(EDTA)]xoverall charge of complex ion = x ; oxidation number of Fe =+2charge of (EDTA)ligand = (-4)2 + (-4) = x-2 = xThus , the formula is [Fe(EDTA)] 2−.$

The formula is $[Fe(EDTA)] 2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $EDTA$ has a charge of $(−4)$

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Answer 4

Question

Chapter 23, Problem 23.17QP

(a)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(a)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Zn(OH)4]2−$

Explanation of Solution

Predict the formula of $tetrahydroxozincate(II).$

$1) The ligands ; 2)oxidation state of Zn is : +2 .tetrahydroxo→represented as (OH)4.Zincate→ represented as Zn3)consider,[Zn(OH)4]xoverall charge of complex ion = x ; oxidation number of Zn =+2charge of (OH)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Zn(OH)4]2−.$

The formula is $[Zn(OH)4]2−$ . The overall charge of the complex ion is $(−2)$ ,because the Ligand $hydroxo$ has a charge of $(−1)$ .

(b)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

a) The cation is named before the anion.

b) Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

c) When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

d) The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

e) If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(b)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cr(H2O)5Cl] Cl2$

Explanation of Solution

Predict the formula of $penta-aquachlorochromium(III) chloride.$

$1) The ligands ; 2)oxidation state of Cr is : +3.penta-aqua→represented as (H2O)5chloro→ represented as Cl.3)Consider,[Cr(H2O)5Cl]x Clxoverall charge of complex ion = x ; oxidation number of Cr =+3charge of (H2O)ligand = (0) ; charge of (Cl)ligand = (-1)3 + (-1) = 22 = xThus , the formula is [Cr(H2O)5Cl] Cl2.$

The formula is $[Cr(H2O)5Cl] Cl2$ . The overall charge of the complex ion is $(+2)$ ,because the Ligand $chloro$ has a charge of $(−1)$ .

(c)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(c)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cu(Br)4]2−$

Explanation of Solution

Predict the formula of $tetrabromo-cuprate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.tetra-bromo→ represented as Br4.cuprate (metal anion)→represented as Cu.3)Consider,[CuBr4]xoverall charge of complex ion = x ; oxidation number of Cu =+2charge of (Br)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Cu(Br)4] 2−.$

The formula is $[Cu(Br)4]2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $Bromo$ has a charge of $(−1)$ .

(d)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(d)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Fe(EDTA)] 2−$

Explanation of Solution

Find the formula for $ethylenediaminetetraacetatoferrate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.ethylenediaminetetraacetato→ represented as EDTA.ferrate (metal anion)→represented as Fe.3)Consider,[Fe(EDTA)]xoverall charge of complex ion = x ; oxidation number of Fe =+2charge of (EDTA)ligand = (-4)2 + (-4) = x-2 = xThus , the formula is [Fe(EDTA)] 2−.$

The formula is $[Fe(EDTA)] 2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $EDTA$ has a charge of $(−4)$

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Answer 5

Chapter 23, Problem 23.17QP

(a)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(a)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Zn(OH)4]2−$

Explanation of Solution

Predict the formula of $tetrahydroxozincate(II).$

$1) The ligands ; 2)oxidation state of Zn is : +2 .tetrahydroxo→represented as (OH)4.Zincate→ represented as Zn3)consider,[Zn(OH)4]xoverall charge of complex ion = x ; oxidation number of Zn =+2charge of (OH)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Zn(OH)4]2−.$

The formula is $[Zn(OH)4]2−$ . The overall charge of the complex ion is $(−2)$ ,because the Ligand $hydroxo$ has a charge of $(−1)$ .

(b)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

a) The cation is named before the anion.

b) Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

c) When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

d) The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

e) If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(b)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cr(H2O)5Cl] Cl2$

Explanation of Solution

Predict the formula of $penta-aquachlorochromium(III) chloride.$

$1) The ligands ; 2)oxidation state of Cr is : +3.penta-aqua→represented as (H2O)5chloro→ represented as Cl.3)Consider,[Cr(H2O)5Cl]x Clxoverall charge of complex ion = x ; oxidation number of Cr =+3charge of (H2O)ligand = (0) ; charge of (Cl)ligand = (-1)3 + (-1) = 22 = xThus , the formula is [Cr(H2O)5Cl] Cl2.$

The formula is $[Cr(H2O)5Cl] Cl2$ . The overall charge of the complex ion is $(+2)$ ,because the Ligand $chloro$ has a charge of $(−1)$ .

(c)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(c)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cu(Br)4]2−$

Explanation of Solution

Predict the formula of $tetrabromo-cuprate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.tetra-bromo→ represented as Br4.cuprate (metal anion)→represented as Cu.3)Consider,[CuBr4]xoverall charge of complex ion = x ; oxidation number of Cu =+2charge of (Br)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Cu(Br)4] 2−.$

The formula is $[Cu(Br)4]2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $Bromo$ has a charge of $(−1)$ .

(d)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(d)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Fe(EDTA)] 2−$

Explanation of Solution

Find the formula for $ethylenediaminetetraacetatoferrate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.ethylenediaminetetraacetato→ represented as EDTA.ferrate (metal anion)→represented as Fe.3)Consider,[Fe(EDTA)]xoverall charge of complex ion = x ; oxidation number of Fe =+2charge of (EDTA)ligand = (-4)2 + (-4) = x-2 = xThus , the formula is [Fe(EDTA)] 2−.$

The formula is $[Fe(EDTA)] 2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $EDTA$ has a charge of $(−4)$

Answer 6

Chapter 23, Problem 23.17QP

(a)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(a)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Zn(OH)4]2−$

Explanation of Solution

Predict the formula of $tetrahydroxozincate(II).$

$1) The ligands ; 2)oxidation state of Zn is : +2 .tetrahydroxo→represented as (OH)4.Zincate→ represented as Zn3)consider,[Zn(OH)4]xoverall charge of complex ion = x ; oxidation number of Zn =+2charge of (OH)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Zn(OH)4]2−.$

The formula is $[Zn(OH)4]2−$ . The overall charge of the complex ion is $(−2)$ ,because the Ligand $hydroxo$ has a charge of $(−1)$ .

Answer 7

Chapter 23, Problem 23.17QP

(a)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

Answer 8

(a)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Zn(OH)4]2−$

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Predict the formula of $tetrahydroxozincate(II).$

$1) The ligands ; 2)oxidation state of Zn is : +2 .tetrahydroxo→represented as (OH)4.Zincate→ represented as Zn3)consider,[Zn(OH)4]xoverall charge of complex ion = x ; oxidation number of Zn =+2charge of (OH)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Zn(OH)4]2−.$

The formula is $[Zn(OH)4]2−$ . The overall charge of the complex ion is $(−2)$ ,because the Ligand $hydroxo$ has a charge of $(−1)$ .

Answer 13

(b)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

a) The cation is named before the anion.

b) Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

c) When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

d) The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

e) If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(b)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cr(H2O)5Cl] Cl2$

Explanation of Solution

Predict the formula of $penta-aquachlorochromium(III) chloride.$

$1) The ligands ; 2)oxidation state of Cr is : +3.penta-aqua→represented as (H2O)5chloro→ represented as Cl.3)Consider,[Cr(H2O)5Cl]x Clxoverall charge of complex ion = x ; oxidation number of Cr =+3charge of (H2O)ligand = (0) ; charge of (Cl)ligand = (-1)3 + (-1) = 22 = xThus , the formula is [Cr(H2O)5Cl] Cl2.$

The formula is $[Cr(H2O)5Cl] Cl2$ . The overall charge of the complex ion is $(+2)$ ,because the Ligand $chloro$ has a charge of $(−1)$ .

Answer 14

(b)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

a) The cation is named before the anion.

b) Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

c) When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

d) The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

e) If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

Answer 15

(b)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cr(H2O)5Cl] Cl2$

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Predict the formula of $penta-aquachlorochromium(III) chloride.$

$1) The ligands ; 2)oxidation state of Cr is : +3.penta-aqua→represented as (H2O)5chloro→ represented as Cl.3)Consider,[Cr(H2O)5Cl]x Clxoverall charge of complex ion = x ; oxidation number of Cr =+3charge of (H2O)ligand = (0) ; charge of (Cl)ligand = (-1)3 + (-1) = 22 = xThus , the formula is [Cr(H2O)5Cl] Cl2.$

The formula is $[Cr(H2O)5Cl] Cl2$ . The overall charge of the complex ion is $(+2)$ ,because the Ligand $chloro$ has a charge of $(−1)$ .

Answer 20

(c)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(c)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cu(Br)4]2−$

Explanation of Solution

Predict the formula of $tetrabromo-cuprate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.tetra-bromo→ represented as Br4.cuprate (metal anion)→represented as Cu.3)Consider,[CuBr4]xoverall charge of complex ion = x ; oxidation number of Cu =+2charge of (Br)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Cu(Br)4] 2−.$

The formula is $[Cu(Br)4]2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $Bromo$ has a charge of $(−1)$ .

Answer 21

(c)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

Answer 22

(c)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Cu(Br)4]2−$

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Predict the formula of $tetrabromo-cuprate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.tetra-bromo→ represented as Br4.cuprate (metal anion)→represented as Cu.3)Consider,[CuBr4]xoverall charge of complex ion = x ; oxidation number of Cu =+2charge of (Br)ligand = (-1)2 + (-4) = x-2 = xThus , the formula is [Cu(Br)4] 2−.$

The formula is $[Cu(Br)4]2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $Bromo$ has a charge of $(−1)$ .

Answer 27

(d)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

(d)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Fe(EDTA)] 2−$

Explanation of Solution

Find the formula for $ethylenediaminetetraacetatoferrate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.ethylenediaminetetraacetato→ represented as EDTA.ferrate (metal anion)→represented as Fe.3)Consider,[Fe(EDTA)]xoverall charge of complex ion = x ; oxidation number of Fe =+2charge of (EDTA)ligand = (-4)2 + (-4) = x-2 = xThus , the formula is [Fe(EDTA)] 2−.$

The formula is $[Fe(EDTA)] 2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $EDTA$ has a charge of $(−4)$

Answer 28

(d)

Interpretation Introduction

Interpretation: The formulae for each of the given systematic names to be predicted.

Concept Introduction:

The cation is named before the anion.

Within a complex ion, the Ligands are arranged in an alphabetical order followed by the metal ion name. The anionic Ligand should ends with a letter –o, the neutral Ligand are called by the molecules (some common name for some exception).

When more Ligands are present, Greek prefixes like di, tri, tetra, penta, and hexa to specify their number.

The oxidation number of the metal is represented in roman numerals immediately following the metal ion name.

If the complex ion is an anion, the metal name should end with –ate.

To Identify: The formulae for each of the given systematic names to be predicted.

Answer 29

(d)

Expert Solution

Answer to Problem 23.17QP

The formula is $[Fe(EDTA)] 2−$

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Find the formula for $ethylenediaminetetraacetatoferrate(II).$

$1) The ligands &metal ion ; 2)oxidation state of Cu is : +2.ethylenediaminetetraacetato→ represented as EDTA.ferrate (metal anion)→represented as Fe.3)Consider,[Fe(EDTA)]xoverall charge of complex ion = x ; oxidation number of Fe =+2charge of (EDTA)ligand = (-4)2 + (-4) = x-2 = xThus , the formula is [Fe(EDTA)] 2−.$

The formula is $[Fe(EDTA)] 2−$ . The overall charge of the complex ion is $(−2)$ , because the Ligand $EDTA$ has a charge of $(−4)$

Answer 34

Ch. 23.1 - Identify the following transition metal atoms and...Ch. 23.3 - Write the oxidation numbers of the metals in the...Ch. 23.3 - Prob. 2PE Ch. 23.3 - Prob. 3PE Ch. 23.3 - Prob. 1RCF Ch. 23.3 - What is the difference between these two...Ch. 23.3 - Prob. 3RCF Ch. 23.4 - Prob. 1RCF Ch. 23.5 - Prob. 4PE Ch. 23.5 - Prob. 1RCF

Concept explainers

Answer to Problem 23.17QP

Explanation of Solution

Answer to Problem 23.17QP

Explanation of Solution

Answer to Problem 23.17QP

Explanation of Solution

Answer to Problem 23.17QP

Explanation of Solution

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