Cutnell & Johnson Physics - Eleventh Edition
Cutnell & Johnson Physics - Eleventh Edition
11th Edition
ISBN: 9781119391869
Author: Shane Stadler David Young
Publisher: WILEY
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Chapter 23, Problem 1FC
To determine

The correct option for change in average power dissipated in the resistor when the frequency is doubled and the rms voltage is tripled.

Expert Solution & Answer
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Answer to Problem 1FC

The correct option is (d). The average power increases by a factor 32 = 9 because it proportional to the square of the rms voltage.

Explanation of Solution

Given data:

A circuit contains an ac generator and a resistor.

Frequency is doubled and the rms voltage tripled.

Formula used:

Write the expression for average power delivered.

P¯=Vrms2R (1)

Here,

Vrms is the root mean square (rms) voltage across the resistor, and

R is the resistance.

Explanation:

In general, the value of resistance is independent of frequency of AC generator. Therefore, average power of the circuit with resistance is independent of frequency.

Substitute 3Vrms for Vrms in equation (1),

P¯=(3Vrms)2R=9Vrms2R

Therefore, by doubling the frequency and tripling the rms voltage, the average power increases by a factor 9 that is option (d) is correct and remaining options (a), (b), (c) and (e) are in correct.

Conclusion:

Hence, the correct option is (d). The average power increases by a factor 32 = 9 because it proportional to the square of the rms voltage.

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Chapter 23 Solutions

Cutnell & Johnson Physics - Eleventh Edition

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