Explanation Given Info: The object distance is 3.00 cm the height of the image is 5.00 cm and the height of the object is 2.00 cm . Explanation : Formula to calculate the magnification is, M = ( − q p ) = ( h ' h ) M is the magnification p is the object distance q is the image distance h is the object height h ' is the image height Rearranging the formula gives the image distance. Formula to calculate the image distance is, q = − p ( h ' h ) Formula to calculate the focal length is, f = p ( − p ( h ' h ) ) p + ( − p ( h ' h ) ) =

10th Edition

ISBN: 9781285737027

Author: Raymond A. Serway, Chris Vuille

Publisher: Cengage Learning

See similar textbooks

Concept explainers

Refraction of Light

Refraction is a change in the direction of light rays when they travel from one medium to another. It is the bending of light when it goes through different media.

Angle of Refraction

Light is considered by many scientists to have dual nature, both particle nature and wave nature. First, Particle nature is one in which we consider a stream of packets of energy called photons. Second, Wave nature is considering light as electromagnetic…

Index of Refraction of Diamond

Diamond, the world’s hardest naturally occurring material and mineral known, is a solid form of the element carbon. The atoms are arranged in a crystal structure called diamond cubic. They exist in a huge variety of colours. Also, they are one of the bes…

Videos

Question

Chapter 23, Problem 11P

To determine

The focal length of the mirror.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 23, Problem 10P

Chapter 23, Problem 12P

Students have asked these similar questions

How can i solve this if n1 (refractive index of gas) and n2 (refractive index of plastic) is not known. And the brewsters angle isn't known

2. Consider the situation described in problem 1 where light emerges horizontally from ground level. Take k = 0.0020 m' and no = 1.0001 and find at which horizontal distance, x, the ray reaches a height of y = 1.5 m.

2-3. Consider the situation of the reflection of a pulse at the interface of two string described in the previous problem. In addition to the net disturbances being equal at the junction, the slope of the net disturbances must also be equal at the junction at all times. Given that p1 = 4.0 g/m, H2 = 9.0 g/m and Aj = 0.50 cm find 2. A, (Answer: -0.10 cm) and 3. Ay. (Answer: 0.40 cm)please I need to show all work step by step problems 2 and 3

Chapter 23 Solutions

College Physics

Ch. 23.1 - In the overhead view if Figure 23.3, the image of...Ch. 23.3 - A person spearfishing from a boat sees a fish...Ch. 23.3 - True or False: (a) The image of an object placed...Ch. 23.5 - A clear plastic sandwich bag filled with water can...Ch. 23.5 - In Figure 23.25a, the blue object arrow is...Ch. 23.5 - An object is placed to the left of a converging...Ch. 23 - Tape a picture of yourself on a bathroom mirror....Ch. 23 - Prob. 2CQ Ch. 23 - The top row of Figure CQ23.3 shows three ray...Ch. 23 - Construct ray diagrams to determine whether each...

Ch. 23 - Construct ray diagrams to determine whether each...Ch. 23 - Prob. 6CQ Ch. 23 - Suppose you want to use a converging lens to...Ch. 23 - Lenses used in eyeglasses, whether converging or...Ch. 23 - In a Jules Verne novel, a piece of ice is shaped...Ch. 23 - If a cylinder of solid glass or clear plastic is...Ch. 23 - Prob. 11CQ Ch. 23 - Prob. 12CQ Ch. 23 - Why does the focal length of a mirror not depend...Ch. 23 - A person spear fishing from a boat sees a...Ch. 23 - An object represented by a gray arrow, is placed...Ch. 23 - (a) Does your bathroom mirror show you older or...Ch. 23 - Suppose you stand in front of a flat mirror and...Ch. 23 - Prob. 3P Ch. 23 - In a church choir loft, two parallel walls are...Ch. 23 - A periscope (Fig. P23.5) is useful for viewing...Ch. 23 - A dentist uses a mirror to examine a tooth that is...Ch. 23 - A convex spherical mirror, whose focal length has...Ch. 23 - To fit a contact lens to a patient's eye, a...Ch. 23 - A virtual image is formed 20.0 cm from a concave...Ch. 23 - While looking at her image in a cosmetic minor,...Ch. 23 - Prob. 11P Ch. 23 - A dedicated sports car enthusiast polishes the...Ch. 23 - A concave makeup mirror it designed to that a...Ch. 23 - A 1.80-m-tall person stands 9.00 m in front of a...Ch. 23 - A man standing 1.52 m in front of a shaving mirror...Ch. 23 - Prob. 16P Ch. 23 - At an intersection of hospital hallways, a convex...Ch. 23 - The mirror of a solar cooker focuses the Suns rays...Ch. 23 - A spherical mirror is to be used to form an image,...Ch. 23 - Prob. 20P Ch. 23 - A cubical block of ice 50.0 cm on an edge is...Ch. 23 - A goldfish is swimming inside a spherical bowl of...Ch. 23 - A paperweight is made of a solid hemisphere with...Ch. 23 - The top of a swimming pool is at ground level. If...Ch. 23 - A transparent sphere of unknown composition is...Ch. 23 - A man inside a spherical diving bell watches a...Ch. 23 - A jellyfish is floating in a water-filled aquarium...Ch. 23 - Figure P23.28 shows a curved surface separating a...Ch. 23 - A contact lens is made of plastic with an index of...Ch. 23 - A thin plastic lens with index of refraction n =...Ch. 23 - A converging lens has a local length of 10.0 cm....Ch. 23 - Prob. 32P Ch. 23 - A diverging lens has a focal length of magnitude...Ch. 23 - A diverging lens has a focal length of 20.0 cm....Ch. 23 - Prob. 35P Ch. 23 - The nickels image in Figure P23.36 has twice the...Ch. 23 - An object of height 8.00 cm it placed 25.0 cm to...Ch. 23 - An object is located 20.0 cm to the left of a...Ch. 23 - A converging lens is placed 30.0 cm to the right...Ch. 23 - (a) Use the thin-lens equation to derive an...Ch. 23 - Two converging lenses, each of focal length 15.0...Ch. 23 - A converging lens is placed at x = 0, a distance d...Ch. 23 - A 1.00-cm-high object is placed 4.00 cm to the...Ch. 23 - Two converging lenses having focal length of f1 =...Ch. 23 - Lens L1 in figure P23.45 has a focal length of...Ch. 23 - An object is placed 15.0 cm from a first...Ch. 23 - Prob. 47AP Ch. 23 - Prob. 48AP Ch. 23 - Prob. 49AP Ch. 23 - Prob. 50AP Ch. 23 - The lens and the mirror in figure P23.51 are...Ch. 23 - The object in Figure P23.52 is mid-way between the...Ch. 23 - Prob. 53AP Ch. 23 - Two rays travelling parallel to the principal axis...Ch. 23 - To work this problem, use the fact that the image...Ch. 23 - Consider two thin lenses, one of focal length f1...Ch. 23 - An object 2.00 cm high is placed 10.0 cm to the...Ch. 23 - Prob. 58AP Ch. 23 - Figure P23.59 shows a converging lens with radii...Ch. 23 - Prob. 60AP Ch. 23 - The lens-makers equation for a lens with index n1...Ch. 23 - An observer to the right of the mirror-lens...Ch. 23 - The lens-markers equation applies to a lens...Ch. 23 - Prob. 64AP Ch. 23 - A glass sphere (n = 1.50) with a radius of 15.0 cm...Ch. 23 - An object 10.0 cm tall is placed at the zero mark...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The focal length of the mirror.

Solution Summary: The author explains that the focal length of the mirror is +5.00cm. The formula to calculate the magnification is, q=-pleft.

Concept explainers

Videos

The focal length of the mirror.

Want to see the full answer?

Chapter 23 Solutions