Free-Falling Object In Exercises 107 and 108, use the position function s ( t ) = − 4.9 t 2 + 200 , which gives the height (in meters) of an object that has fallen for t seconds from a height of 200 meters. The velocity at time t = a seconds is given by lim t → a s ( a ) − s ( t ) a − t ⋅ Find the velocity of the object when t = 3 .
Free-Falling Object In Exercises 107 and 108, use the position function s ( t ) = − 4.9 t 2 + 200 , which gives the height (in meters) of an object that has fallen for t seconds from a height of 200 meters. The velocity at time t = a seconds is given by lim t → a s ( a ) − s ( t ) a − t ⋅ Find the velocity of the object when t = 3 .
Solution Summary: The author calculates the velocity of an object at t=3 seconds. The position function gives the height (in feet) of the object.
Free-Falling Object In Exercises 107 and 108, use the position function
s
(
t
)
=
−
4.9
t
2
+
200
, which gives the height (in meters) of an object that has fallen for t seconds from a height of 200 meters. The velocity at time
t
=
a
seconds is given by
Force with 800 N and 400 N are acting on a machine part at 30° and 60°, respectively with the positive x axis
Find the accumulated amount A, if the principal P is invested at an interest rate of r per year for t years. (Round your answer to the nearest cent.)
P = $13,000, r = 6%, t = 10, compounded quarterly
A = $ 31902
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Find the accumulated amount A, if the principal P is invested at an interest rate of r per year for t years. (Round your answer to the nearest cent.)
P = $140,000, r = 8%, t = 8, compounded monthly
A = $259130.20 X
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Find the present value of $20,000 due in 3 years at the given rate of interest. (Round your answers to the nearest cent.)
(a) 2%/year compounded monthly
(b) 5%/year compounded daily
$
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Find the accumulated amount after 3 years if $4000 is invested at 3%/year compounded continuously. (Round your answer to the nearest cent.)
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