Chapter 22.8, Problem 6PE

Interpretation Introduction

Interpretation: The value of $K_{\text{f}}$ for the two individual reactions is given. The value of $K_{\text{f}}$ for a net reaction obtained by the operations of the two individual reactions is to be calculated.

Concept introduction: The value of $K_{\text{f}}$ for the two addition reaction is calculated as,

$K_{\text{c}}{}_{{}_{\text{net}}}=K_{\text{c}}{}_{{}_1}\times K_{\text{c}}{}_{{}_2}$

The value of $K_{\text{f}}$ of reverse is calculated by the formula,

$K_{\text{f}}\text{of}\text{reverse}\text{reaction}=\frac{1}{K_{\text{f}}}$

To determine: The value of $K_{\text{f}}$ for a net reaction obtained by the operations of the two individual reactions.