Study Guide for Chemistry: Structure and Properties
2nd Edition
ISBN: 9780134460680
Author: Nivaldo Tro
Publisher: PEARSON
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Chapter 22, Problem 76E
Interpretation Introduction
To determine: The difference between the values of and and the values at 298K for the complete dissociation of the two complexes.
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NMR spectrum of ethyl acetate has signals whose chemical shifts are indicated below. Which hydrogen or set of hydrogens corresponds to the signal at
4.1 ppm? Select the single best answer.
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ethyl acetate
H NMR: 1.3 ppm, 2.0 ppm, 4.1 ppm
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How many signals do you expect in the H NMR spectrum for this molecule?
Br Br
Write the answer below.
Also, in each of the drawing areas below is a copy of the molecule, with Hs shown. In each copy, one of the H atoms is colored red. Highlight in red all other H
atoms that would contribute to the same signal as the H already highlighted red
Note for advanced students: In this question, any multiplet is counted as one signal.
1
Number of signals in the 'H NMR spectrum.
For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to
the same signal as the H atom already highlighted red.
If no other H atoms will contribute, check the box at right.
Check
For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute
to the same signal as the H atom already highlighted red.
If no other H atoms will contribute, check the box at right.
O
✓
No additional Hs to color in top
molecule
ง
No additional Hs to color in bottom…
in the kinetics experiment, what were the values calculated? Select all that apply.a) equilibrium constantb) pHc) order of reactiond) rate contstant
Chapter 22 Solutions
Study Guide for Chemistry: Structure and Properties
Ch. 22 - When a transition metal atom forms an ion, which...Ch. 22 - Explain why transition metals exhibit multiple...Ch. 22 - Why is the +2 oxidation state so common for...Ch. 22 - Explain why atomic radii of elements in the third...Ch. 22 - Gold is the most electronegative transition metal....Ch. 22 - Prob. 6ECh. 22 - Prob. 7ECh. 22 - Explain the differences between each pair of...Ch. 22 - Prob. 9ECh. 22 - Prob. 10E
Ch. 22 - Prob. 11ECh. 22 - Prob. 12ECh. 22 - Prob. 13ECh. 22 - Prob. 14ECh. 22 - Prob. 15ECh. 22 - Prob. 16ECh. 22 - Prob. 17ECh. 22 - Write the ground state electron configuration for...Ch. 22 - Determine the highest possible oxidation state for...Ch. 22 - Prob. 20ECh. 22 - Prob. 21ECh. 22 - Prob. 22ECh. 22 - Prob. 23ECh. 22 - Prob. 24ECh. 22 - Prob. 25ECh. 22 - Prob. 26ECh. 22 - Prob. 27ECh. 22 - Write the formula and the name of each complex ion...Ch. 22 - Prob. 29ECh. 22 - Prob. 30ECh. 22 - Prob. 31ECh. 22 - Prob. 32ECh. 22 - Prob. 33ECh. 22 - Prob. 34ECh. 22 - Prob. 35ECh. 22 - Prob. 36ECh. 22 - Prob. 37ECh. 22 - Prob. 38ECh. 22 - Prob. 39ECh. 22 - Prob. 40ECh. 22 - Prob. 41ECh. 22 - Prob. 42ECh. 22 - Prob. 43ECh. 22 - Prob. 44ECh. 22 - Prob. 45ECh. 22 - Prob. 46ECh. 22 - Prob. 47ECh. 22 - Prob. 48ECh. 22 - Prob. 49ECh. 22 - Prob. 50ECh. 22 - Prob. 51ECh. 22 - Prob. 52ECh. 22 - Prob. 53ECh. 22 - Prob. 54ECh. 22 - Prob. 55ECh. 22 - Prob. 56ECh. 22 - Prob. 57ECh. 22 - Most of the second-row transition metals do not...Ch. 22 - Prob. 59ECh. 22 - Prob. 60ECh. 22 - Prob. 61ECh. 22 - Prob. 62ECh. 22 - Prob. 63ECh. 22 - Prob. 64ECh. 22 - Hexacyanomanganate(III) ion is a low-spin complex....Ch. 22 - Prob. 66ECh. 22 - Prob. 67ECh. 22 - Prob. 68ECh. 22 - Prob. 69ECh. 22 - Prob. 70ECh. 22 - Prob. 71ECh. 22 - Prob. 72ECh. 22 - Prob. 73ECh. 22 - Calculate the solubility of Zn(OH)2(s) in 2.0 M...Ch. 22 - Prob. 75ECh. 22 - Prob. 76ECh. 22 - Prob. 77ECh. 22 - Prob. 78ECh. 22 - Prob. 79ECh. 22 - Prob. 80ECh. 22 - Have each group member choose a row of the...Ch. 22 - Prob. 82ECh. 22 - Prob. 83ECh. 22 - Prob. 84ECh. 22 - Prob. 85ECh. 22 - Many aqueous solutions of complex ions display...Ch. 22 - What is the electron configuration of the Cu+ ion?...Ch. 22 - Prob. 2SAQCh. 22 - Prob. 3SAQCh. 22 - Prob. 4SAQCh. 22 - Prob. 5SAQCh. 22 - Prob. 6SAQCh. 22 - Prob. 7SAQCh. 22 - Estimate the crystal field splitting energy (in...Ch. 22 - Use crystal field theory to determine the number...Ch. 22 - Prob. 10SAQ
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- true or false, given that a 20.00 mL sample of NaOH took 24.15 mL of 0.141 M HCI to reach the endpoint in a titration, the concentration of the NaOH is 1.17 M.arrow_forwardin the bromothymol blue experiment, pKa was measured. A closely related compound has a Ka of 2.10 x 10-5. What is the pKa?a) 7.1b) 4.7c) 2.0arrow_forwardcalculate the equilibrium concentration of H2 given that K= 0.017 at a constant temperature for this reaction. The inital concentration of HBr is 0.050 M.2HBr(g) ↔ H2(g) + Br2(g)a) 4.48 x 10-2 M b) 5.17 x 10-3 Mc) 1.03 x 10-2 Md) 1.70 x 10-2 Marrow_forward
- true or falsegiven these two equilibria with their equilibrium constants:H2(g) + CI2(l) ↔ 2HCI(g) K= 0.006 CI2(l) ↔ CI2(g) K= 0.30The equilibrium contstant for the following reaction is 1.8H2(g) + CI2 ↔ 2HCI(g)arrow_forwardI2(g) + CI2(g) ↔ 2ICIK for this reaction is 81.9. Find the equilibrium concentration of I2 if the inital concentration of I2 and CI2 are 0.010 Marrow_forwardtrue or false,the equilibrium constant for this reaction is 0.50.PCI5(g) ↔ PCI3(g) + CI2(g)Based on the above, the equilibrium constant for the following reaction is 0.25.2PCI5(g) ↔. 2PCI3(g) + 2CI2(g)arrow_forward
- true or false, using the following equilibrium, if carbon dioxide is added the equilibrium will shift toward the productsC(s) + CO2(g) ↔ 2CO(g)arrow_forward2S2O2/3- (aq) + I2 (aq) ---> S4O2/6- (aq) +2I- (aq) Experiment I2 (M) S2O3- (M) Initital Rate (M/s) 1 0.01 0.01 0.0004 2 0.01 0.02 0.0004 3 0.02 0.01 0.0008 Calculate the overall order for this reaction using the table data a) 3b) 0c) 2d) 1arrow_forwardthe decomposition of N2O5 is the first order with a half-life of 1.98 minutes. If the inital concentration of N2O5 is 0.200 M, what is the concentration after 6 minutes?a) 0.612 Mb) 0.035 Mc) 0.024 Md) 0.100 Marrow_forward
- 20.00 mL of 0.150 M HCI is titrated with 0.075 M NaOH. What volume of NaOH is needed?a) 50 mLb) 20 mLc) 40 mLd) 26.66 mLarrow_forward20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCI. What is the molarity of the HCI?a) 0.150 Mb) 0.079 Mc) 0.025 Md) 0.050 Marrow_forwardin the following reaction, the OH- acts as which of these?NO2- (aq) + H2O (l) ⇌ OH- (aq) + HNO2 (aq)a) not a weak acidb) basec) acidarrow_forward
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