Concept explainers
The required current in the top wire in the given figure to produce a field of zero at the point equidistant from the wires, provided currents in the bottom two wires are both 10.0 A into the page.

Answer to Problem 71PE
Explanation of Solution
Given:
Current carrying wire is placed at the vertices of an equilateral triangle of side 10.0 cm=
Formula used:
Magnetic field due to a long current carrying wire at perpendicular distance
Where
Calculation:
Label the wires at the vertices of triangle as P, Q and R.The equidistant point from all the three wires is centroid of the triangle. Let call the centroid point as O.
The perpendicular distance from the three wires to centroid of the triangle is
Let the current in P wire be
(Note the value of
Direction of fields at the centroid is shown by blue arrow in the figure below.
The resultant of vector
Now the net magnetic field at the centroid is
We want zero field at centroid. So,
Or
We are getting negative sign because what we have assumed the direction of current in wire P is not right to get zero field at centroid. So the new direction of current in top wire is to be into the page and its magnitude is
Conclusion:
Current in the top wire to produce a field of zero at the point equidistant from the wires is
Want to see more full solutions like this?
Chapter 22 Solutions
COLLEGE PHYSICS
- A plank 2.00 cm thick and 15.7 cm wide is firmly attached to the railing of a ship by clamps so that the rest of the board extends 2.00 m horizontally over the sea below. A man of mass 92.9 kg is forced to stand on the very end. If the end of the board drops by 5.97 cm because of the man's weight, find the shear modulus of the wood.arrow_forwardwhen considering particle B (4,1) distances in relation to P (-4, 5), why are the y coordinates being used gto resolve the distance along the x-axis and vice-versa?arrow_forwardA 198 kg load is hung on a wire of length of 3.58 m, cross-sectional area 2.00⋅ 10-5 m2, and Young's modulus 8.00⋅10^10 Pa. What is its increase in length?arrow_forward
- I. Pushing on a File Cabinet Bob has been asked to push a heavy file cabinet down the hall to another office. It's not on rollers, so there is a lot of friction. At time t = 0 seconds, he starts pushing it from rest with increasing force until it starts to move at t = 2 seconds. He pushes the file cabinet down the hall with varying amounts of force. The velocity versus time graph of the cabinet is shown below. A. On the graphs provided below, 1. draw the net force vs. time that would produce this velocity graph; 2. draw the friction force vs. time for this motion; 3. draw the applied force (Fon Cabinet by Bob) VS. time for this motion (the first two seconds of this graph have been drawn for you). Velocity (m/s) Applied Force (N) Friction Force (N) Net Force (N) A -m B -U time (s) D time (s) time (s) time (s)arrow_forwardanswer itarrow_forwardPlease draw a sketch and a FBDarrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningAn Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill





