“Equilibrium constant value” should be identified. Concept introduction: The value of Equilibrium constant determines the rate of forward and rate of backward reaction. If the value goes more than 1 then rate of forward reaction favours else it favours backward reaction. Given: Hb+O 2 ⇌ HbO 2 , K=2 × 10 12 Hb+CO ⇌ HbO , K=1 × 10 14 HbO 2 +CO 2 ⇌ HbCO+O 2

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Answer 1

Question

Chapter 22, Problem 56E

Interpretation Introduction

Interpretation:

“Equilibrium constant value” should be identified.

Concept introduction:

The value of Equilibrium constant determines the rate of forward and rate of backward reaction.

If the value goes more than 1 then rate of forward reaction favours else it favours backward

reaction.

Given:

$\begin{matrix} {Hb+O}_{2} ⇌ {HbO}_{2}, K=2 \times 10^{12} \\ Hb+CO ⇌ HbO, K=1 \times 10^{14} \\ {HbO}_{2} {+CO}_{2} ⇌ {HbCO+O}_{2} \end{matrix}$

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Answer 2

Question

Chapter 22, Problem 56E

Interpretation Introduction

Interpretation:

“Equilibrium constant value” should be identified.

Concept introduction:

The value of Equilibrium constant determines the rate of forward and rate of backward reaction.

If the value goes more than 1 then rate of forward reaction favours else it favours backward

reaction.

Given:

$\begin{matrix} {Hb+O}_{2} ⇌ {HbO}_{2}, K=2 \times 10^{12} \\ Hb+CO ⇌ HbO, K=1 \times 10^{14} \\ {HbO}_{2} {+CO}_{2} ⇌ {HbCO+O}_{2} \end{matrix}$

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Answer 3

Question

Chapter 22, Problem 56E

Interpretation Introduction

Interpretation:

“Equilibrium constant value” should be identified.

Concept introduction:

The value of Equilibrium constant determines the rate of forward and rate of backward reaction.

If the value goes more than 1 then rate of forward reaction favours else it favours backward

reaction.

Given:

$\begin{matrix} {Hb+O}_{2} ⇌ {HbO}_{2}, K=2 \times 10^{12} \\ Hb+CO ⇌ HbO, K=1 \times 10^{14} \\ {HbO}_{2} {+CO}_{2} ⇌ {HbCO+O}_{2} \end{matrix}$

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Answer 4

Question

Chapter 22, Problem 56E

Interpretation Introduction

Interpretation:

“Equilibrium constant value” should be identified.

Concept introduction:

The value of Equilibrium constant determines the rate of forward and rate of backward reaction.

If the value goes more than 1 then rate of forward reaction favours else it favours backward

reaction.

Given:

$\begin{matrix} {Hb+O}_{2} ⇌ {HbO}_{2}, K=2 \times 10^{12} \\ Hb+CO ⇌ HbO, K=1 \times 10^{14} \\ {HbO}_{2} {+CO}_{2} ⇌ {HbCO+O}_{2} \end{matrix}$

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Answer 5

Chapter 22, Problem 56E

Interpretation Introduction

Interpretation:

“Equilibrium constant value” should be identified.

Concept introduction:

The value of Equilibrium constant determines the rate of forward and rate of backward reaction.

If the value goes more than 1 then rate of forward reaction favours else it favours backward

reaction.

Given:

$\begin{matrix} {Hb+O}_{2} ⇌ {HbO}_{2}, K=2 \times 10^{12} \\ Hb+CO ⇌ HbO, K=1 \times 10^{14} \\ {HbO}_{2} {+CO}_{2} ⇌ {HbCO+O}_{2} \end{matrix}$

Answer 6

Chapter 22, Problem 56E

Interpretation Introduction

Interpretation:

“Equilibrium constant value” should be identified.

Concept introduction:

The value of Equilibrium constant determines the rate of forward and rate of backward reaction.

If the value goes more than 1 then rate of forward reaction favours else it favours backward

reaction.

Given:

$\begin{matrix} {Hb+O}_{2} ⇌ {HbO}_{2}, K=2 \times 10^{12} \\ Hb+CO ⇌ HbO, K=1 \times 10^{14} \\ {HbO}_{2} {+CO}_{2} ⇌ {HbCO+O}_{2} \end{matrix}$

Answer 7

Chapter 22, Problem 56E

Interpretation Introduction

Interpretation:

“Equilibrium constant value” should be identified.

Concept introduction:

The value of Equilibrium constant determines the rate of forward and rate of backward reaction.

If the value goes more than 1 then rate of forward reaction favours else it favours backward

reaction.

Given:

$\begin{matrix} {Hb+O}_{2} ⇌ {HbO}_{2}, K=2 \times 10^{12} \\ Hb+CO ⇌ HbO, K=1 \times 10^{14} \\ {HbO}_{2} {+CO}_{2} ⇌ {HbCO+O}_{2} \end{matrix}$

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 22 - When a transition metal atom forms an ion, which...Ch. 22 - Explain why transition metals exhibit multiple...Ch. 22 - Why is the +2 oxidation state so common for...Ch. 22 - Explain why atomic radii of elements in the third...Ch. 22 - Gold is the most electronegative transition metal....Ch. 22 - Prob. 6E Ch. 22 - Prob. 7E Ch. 22 - Explain the differences between each pair of...Ch. 22 - Prob. 9E Ch. 22 - Prob. 10E

Solution Summary: The author explains that the Equilibrium constant determines the rate of forward and backward reaction. The equilibrium constant for HbO 2 is reverse of what is given.

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Chapter 22 Solutions