Microbiology with Diseases by Taxonomy (5th Edition)
5th Edition
ISBN: 9780134019192
Author: Robert W. Bauman Ph.D.
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 22, Problem 4TMW
Summary Introduction
To determine:
The reason why superficial mycoses such as athletes’ foot are chronic and recurring problems.
Introduction:
Fungal skin infections are classified into two categories: superficial and deep. Superficial infection is defined as the infection that is confined to the stratum conium of epidermis, hair and nails. The three common types of superficial mycoses are dermatophytosis, and hyperpigmentation caused by Malassezia and some rare type of superficial mycoses are Tinea pedis and Tinea nigra.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
influences of environment on the phenotype.
What is the difference between codominance and phenotypic plasticity?
Explain the differences between polygeny and pleiotropy,
Chapter 22 Solutions
Microbiology with Diseases by Taxonomy (5th Edition)
Ch. 22 - A fungus that can infect both healthy and...Ch. 22 - Prob. 2MCCh. 22 - Prob. 3MCCh. 22 - Prob. 4MCCh. 22 - Ringworm is caused by a _________________. a....Ch. 22 - Prob. 6MCCh. 22 - Prob. 7MCCh. 22 - Prob. 8MCCh. 22 - Prob. 9MCCh. 22 - Prob. 10MC
Ch. 22 - Prob. 11MCCh. 22 - Prob. 12MCCh. 22 - Prob. 13MCCh. 22 - Prob. 14MCCh. 22 - Prob. 15MCCh. 22 - Prob. 16MCCh. 22 - Prob. 17MCCh. 22 - Prob. 18MCCh. 22 - Prob. 19MCCh. 22 - Prob. 20MCCh. 22 - Prob. 1TFCh. 22 - Prob. 2TFCh. 22 - Prob. 3TFCh. 22 - Prob. 4TFCh. 22 - Prob. 5TFCh. 22 - Prob. 6TFCh. 22 - Prob. 7TFCh. 22 - Prob. 8TFCh. 22 - Prob. 9TFCh. 22 - Prob. 10TFCh. 22 - Prob. 1FIBCh. 22 - Prob. 2FIBCh. 22 - Prob. 3FIBCh. 22 - Prob. 4FIBCh. 22 - Prob. 5FIBCh. 22 - Prob. 6FIBCh. 22 - Prob. 7FIBCh. 22 - Thrush is caused by __________ (genus name).Ch. 22 - Prob. 9FIBCh. 22 - Prob. 10FIBCh. 22 - Prob. 1MCh. 22 - Prob. 1SACh. 22 - Prob. 2SACh. 22 - Prob. 3SACh. 22 - Prob. 4SACh. 22 - Prob. 5SACh. 22 - Prob. 1VICh. 22 - Prob. 2VICh. 22 - Prob. 1CTCh. 22 - Prob. 2CTCh. 22 - Prob. 3CTCh. 22 - Prob. 4CTCh. 22 - What factors contribute to the pathogenicity of...Ch. 22 - Prob. 6CTCh. 22 - Prob. 7CTCh. 22 - Prob. 1CMCh. 22 - Prob. 1TMWCh. 22 - Prob. 2TMWCh. 22 - Prob. 3TMWCh. 22 - Prob. 4TMWCh. 22 - Prob. 5TMWCh. 22 - Prob. 1EDCSCh. 22 - Clinical Case Study What's Ailing the Bird...Ch. 22 - Prob. 2CCS
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- If using animals in medical experiments could save human lives, is it ethical to do so? In your answer, apply at least one ethical theory in support of your position.arrow_forwardYou aim to test the hypothesis that the Tbx4 and Tbx5 genes inhibit each other's expression during limb development. With access to chicken embryos and viruses capable of overexpressing Tbx4 and Tbx5, describe an experiment to investigate whether these genes suppress each other's expression in the limb buds. What results would you expect if they do repress each other? What results would you expect if they do not repress each other?arrow_forwardYou decide to delete Fgf4 and Fgf8 specifically in the limb bud. Explain why you would not knock out these genes in the entire embryo instead.arrow_forward
- You implant an FGF10-coated bead into the anterior flank of a chicken embryo, directly below the level of the wing bud. What is the phenotype of the resulting ectopic limb? Briefly describe the expected expression domains of 1) Shh, 2) Tbx4, and 3) Tbx5 in the resulting ectopic limb bud.arrow_forwardDesign a grafting experiment to determine if limb mesoderm determines forelimb / hindlimb identity. Include the experiment, a control, and an interpretation in your answer.arrow_forwardThe Snapdragon is a popular garden flower that comes in a variety of colours, including red, yellow, and orange. The genotypes and associated phenotypes for some of these flowers are as follows: aabb: yellow AABB, AABb, AaBb, and AaBB: red AAbb and Aabb: orange aaBB: yellow aaBb: ? Based on this information, what would the phenotype of a Snapdragon with the genotype aaBb be and why? Question 21 options: orange because A is epistatic to B yellow because A is epistatic to B red because B is epistatic to A orange because B is epistatic to A red because A is epistatic to B yellow because B is epistatic to Aarrow_forward
- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardA sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
- With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Concepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College
Biology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage Learning
Microbiology for Surgical Technologists (MindTap ...BiologyISBN:9781111306663Author:Margaret Rodriguez, Paul PricePublisher:Cengage Learning
Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax
Medical Terminology for Health Professions, Spira...Health & NutritionISBN:9781305634350Author:Ann Ehrlich, Carol L. Schroeder, Laura Ehrlich, Katrina A. SchroederPublisher:Cengage Learning
Concepts of Biology
Biology
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:OpenStax College
Biology Today and Tomorrow without Physiology (Mi...
Biology
ISBN:9781305117396
Author:Cecie Starr, Christine Evers, Lisa Starr
Publisher:Cengage Learning
Microbiology for Surgical Technologists (MindTap ...
Biology
ISBN:9781111306663
Author:Margaret Rodriguez, Paul Price
Publisher:Cengage Learning
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Medical Terminology for Health Professions, Spira...
Health & Nutrition
ISBN:9781305634350
Author:Ann Ehrlich, Carol L. Schroeder, Laura Ehrlich, Katrina A. Schroeder
Publisher:Cengage Learning