Test Prep Series for AP Chemistry for Chemistry: The Central Science 14th ed AP
14th Edition
ISBN: 9780134661483
Author: Edward L Waterman
Publisher: PEARSON
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Chapter 22, Problem 4E
Interpretation Introduction
Interpretation: The method that distinguishes between glass bottle containing oxygen and that containing nitrogen is to be found.
Concept introduction: Oxygen is more reactive compared to nitrogen. The inert nature of nitrogen is due to the more stable triple bond present in the nitrogen molecule A substance can be burnt in oxygen but not in nitrogen.
To determine: The method to distinguish between the glass bottle containing oxygen and that containing nitrogen.
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Vid4Q2
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☑
Provide IUPAC name of product in the reaction
below
A 3,4-dimethylcyclohexene
B 1,2-dimethylcyclohexane
C 1,2-dimethylcyclohexene
D 3,4-dimethylcyclohexane
H₂
Pd
5.
Use the MS data to answer the questions on the next page.
14.0
1.4
15.0
8.1
100-
MS-IW-5644
26.0
2.8
27.0
6.7
28.0
1.8
29.0
80
4.4
38.0
1.0
39.0
1.5
41.0
1.2
42.0
11.2
43.0
100.0
44.0
4.3
79.0
1.9
80.0
2.6
Relative Intensity
40
81.0
1.9
82.0
2.5
93.0
8.7
20-
95.0
8.2
121.0
2.0
123.0
2.0
136.0
11.8
0
138.0
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20
40
8.
60
a.
Br
- 0
80
100
120
140
160
180
200
220
m/z
Identify the m/z of the base peak and molecular ion.
2
b.
Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0,
95.0, 136.0, and 138.0 m/z.
C.
Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to
fragment 43.0 m/z. Be sure to include all electrons and formal charges.
6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium
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None
Chapter 22 Solutions
Test Prep Series for AP Chemistry for Chemistry: The Central Science 14th ed AP
Ch. 22.1 - Prob. 21.1.1PECh. 22.1 - Prob. 21.1.2PECh. 22.1 - Prob. 21.2.1PECh. 22.1 - Prob. 21.2.2PECh. 22.3 - Prob. 21.3.1PECh. 22.3 - Prob. 21.3.2PECh. 22.4 - Prob. 21.4.1PECh. 22.4 - Prob. 21.4.2PECh. 22.7 - Prob. 21.7.1PECh. 22.7 - Prob. 21.7.2PE
Ch. 22.10 - Prob. 21.10.1PECh. 22.10 - Prob. 21.10.2PECh. 22 - Prob. 1DECh. 22 - Prob. 1ECh. 22 - Prob. 2ECh. 22 - Prob. 3ECh. 22 - Prob. 4ECh. 22 - Prob. 5ECh. 22 - Prob. 6ECh. 22 - Prob. 7ECh. 22 - Prob. 8ECh. 22 - Prob. 9ECh. 22 - Prob. 10ECh. 22 - Prob. 11ECh. 22 - Prob. 12ECh. 22 - Prob. 13ECh. 22 - Prob. 14ECh. 22 - Prob. 15ECh. 22 - Prob. 16ECh. 22 - Prob. 17ECh. 22 - Prob. 18ECh. 22 - Prob. 19ECh. 22 - Prob. 20ECh. 22 - Prob. 21ECh. 22 - Prob. 22ECh. 22 - Prob. 23ECh. 22 - Prob. 24ECh. 22 - Prob. 25ECh. 22 - Prob. 26ECh. 22 - Prob. 27ECh. 22 - Prob. 28ECh. 22 - Why does xenon form stable compounds with...Ch. 22 - Prob. 30ECh. 22 - Prob. 31ECh. 22 - Prob. 32ECh. 22 - Prob. 33ECh. 22 - Prob. 34ECh. 22 - Prob. 35ECh. 22 - Prob. 36ECh. 22 - Prob. 37ECh. 22 - Prob. 38ECh. 22 - Prob. 39ECh. 22 - Prob. 40ECh. 22 - Prob. 41ECh. 22 - Prob. 42ECh. 22 - Prob. 43ECh. 22 - Prob. 44ECh. 22 - Prob. 45ECh. 22 - Prob. 46ECh. 22 - Prob. 47ECh. 22 - Prob. 48ECh. 22 - Prob. 49ECh. 22 - Prob. 50ECh. 22 - Prob. 51ECh. 22 - Prob. 52ECh. 22 - Prob. 53ECh. 22 - Prob. 54ECh. 22 - Prob. 55ECh. 22 - Prob. 56ECh. 22 - Prob. 57ECh. 22 - Write a chemical formula for each compound or ion,...Ch. 22 - Prob. 59ECh. 22 - Prob. 60ECh. 22 - Prob. 61ECh. 22 - Prob. 62ECh. 22 - Prob. 63ECh. 22 - Prob. 64ECh. 22 - Prob. 65ECh. 22 - Prob. 66ECh. 22 - Prob. 67ECh. 22 - Prob. 68ECh. 22 - Prob. 69ECh. 22 - Write the formulas for the following compounds,...Ch. 22 - Prob. 71ECh. 22 - Prob. 72ECh. 22 - Prob. 73ECh. 22 - Prob. 74ECh. 22 - Prob. 75ECh. 22 - Prob. 76ECh. 22 - Prob. 77ECh. 22 - Prob. 78ECh. 22 - Prob. 79AECh. 22 - Prob. 80AECh. 22 - Prob. 81AECh. 22 - Prob. 82AECh. 22 - Prob. 83AECh. 22 - Prob. 84AECh. 22 - Prob. 85AECh. 22 - Prob. 86AECh. 22 - Prob. 87AECh. 22 - Prob. 88AECh. 22 - Prob. 89AECh. 22 - Prob. 90AECh. 22 - Prob. 91IECh. 22 - Prob. 92IECh. 22 - Prob. 93IECh. 22 - Prob. 94IECh. 22 - Prob. 95IECh. 22 - Prob. 96IECh. 22 - Prob. 97IECh. 22 - Prob. 98IECh. 22 - Prob. 99IECh. 22 - Prob. 100IECh. 22 - Prob. 101IECh. 22 - Prob. 102IECh. 22 - Prob. 103IECh. 22 - Prob. 104IE
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