(a) The wavelength and frequency of photon that have the energy 3.45 × 10 − 19 J ?

Question

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Answer 1

Question

Chapter 22, Problem 48QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 3.45×10−19J ?

Expert Solution

Explanation of Solution

Given info:

Formula used:

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.45×10−19=5.77×10−7m=577nm

Frequency
f=Ephotonh=3.45×10−196.63×10−34=5.20×1014Hz

Conclusion:

Wavelength =577nm

Frequency =5.20×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.80×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.8×10−19=4.14×10−7m=414nm

Frequency
f=Ephotonh=4.80×10−196.63×10−34=7.24×1014Hz

Conclusion:

Wavelength =414nm

Frequency =7.24×1014Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 1.28×10−18J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.28×10−18=1.55×10−7m=155nm

Frequency
f=Ephotonh=1.28×10−186.63×10−34=1.93×1015Hz

Conclusion:

Wavelength =155nm

Frequency =1.93×1015Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 4.33×10−20J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.33×10−20=4.59×10−7m=459nm

Frequency
f=Ephotonh=4.33×10−206.63×10−34=6.53×1013Hz

Conclusion:

Wavelength =459nm

Frequency =6.53×1013Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=931×106×1.60×10−19=1.49×10−10J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.49×10−10=1.34×10−15m

Frequency
f=Ephotonh=1.49×10−106.63×10−34=2.25×1023Hz

Conclusion:

Wavelength =1.34×10−15m

Frequency =2.25×1023Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=2.88×103×1.60×10−19=4.61×10−16J

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.61×10−16=4.32×10−10m=0.432nm

Frequency
f=Ephotonh=4.61×10−166.63×10−34=6.95×1017Hz

Conclusion:

Wavelength =0.432nm

Frequency =6.95×1017Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=7.88×1.60×10−19=1.26×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.26×10−18=1.58×10−7m=158nm

Frequency
f=Ephotonh=1.26×10−186.63×10−34=1.90×1015Hz

Conclusion:

Wavelength =158nm

Frequency =1.90×1015Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=13.6×1.60×10−19=2.18×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.18×10−18=9.14×10−8m=91.4nm

Frequency
f=Ephotonh=2.18×10−186.63×10−34=3.28×1015Hz

Conclusion:

Wavelength =91.4nm

Frequency =3.28×1015Hz

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Answer 2

Question

Chapter 22, Problem 48QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 3.45×10−19J ?

Expert Solution

Explanation of Solution

Given info:

Formula used:

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.45×10−19=5.77×10−7m=577nm

Frequency
f=Ephotonh=3.45×10−196.63×10−34=5.20×1014Hz

Conclusion:

Wavelength =577nm

Frequency =5.20×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.80×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.8×10−19=4.14×10−7m=414nm

Frequency
f=Ephotonh=4.80×10−196.63×10−34=7.24×1014Hz

Conclusion:

Wavelength =414nm

Frequency =7.24×1014Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 1.28×10−18J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.28×10−18=1.55×10−7m=155nm

Frequency
f=Ephotonh=1.28×10−186.63×10−34=1.93×1015Hz

Conclusion:

Wavelength =155nm

Frequency =1.93×1015Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 4.33×10−20J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.33×10−20=4.59×10−7m=459nm

Frequency
f=Ephotonh=4.33×10−206.63×10−34=6.53×1013Hz

Conclusion:

Wavelength =459nm

Frequency =6.53×1013Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=931×106×1.60×10−19=1.49×10−10J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.49×10−10=1.34×10−15m

Frequency
f=Ephotonh=1.49×10−106.63×10−34=2.25×1023Hz

Conclusion:

Wavelength =1.34×10−15m

Frequency =2.25×1023Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=2.88×103×1.60×10−19=4.61×10−16J

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.61×10−16=4.32×10−10m=0.432nm

Frequency
f=Ephotonh=4.61×10−166.63×10−34=6.95×1017Hz

Conclusion:

Wavelength =0.432nm

Frequency =6.95×1017Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=7.88×1.60×10−19=1.26×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.26×10−18=1.58×10−7m=158nm

Frequency
f=Ephotonh=1.26×10−186.63×10−34=1.90×1015Hz

Conclusion:

Wavelength =158nm

Frequency =1.90×1015Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=13.6×1.60×10−19=2.18×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.18×10−18=9.14×10−8m=91.4nm

Frequency
f=Ephotonh=2.18×10−186.63×10−34=3.28×1015Hz

Conclusion:

Wavelength =91.4nm

Frequency =3.28×1015Hz

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Answer 3

Question

Chapter 22, Problem 48QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 3.45×10−19J ?

Expert Solution

Explanation of Solution

Given info:

Formula used:

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.45×10−19=5.77×10−7m=577nm

Frequency
f=Ephotonh=3.45×10−196.63×10−34=5.20×1014Hz

Conclusion:

Wavelength =577nm

Frequency =5.20×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.80×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.8×10−19=4.14×10−7m=414nm

Frequency
f=Ephotonh=4.80×10−196.63×10−34=7.24×1014Hz

Conclusion:

Wavelength =414nm

Frequency =7.24×1014Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 1.28×10−18J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.28×10−18=1.55×10−7m=155nm

Frequency
f=Ephotonh=1.28×10−186.63×10−34=1.93×1015Hz

Conclusion:

Wavelength =155nm

Frequency =1.93×1015Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 4.33×10−20J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.33×10−20=4.59×10−7m=459nm

Frequency
f=Ephotonh=4.33×10−206.63×10−34=6.53×1013Hz

Conclusion:

Wavelength =459nm

Frequency =6.53×1013Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=931×106×1.60×10−19=1.49×10−10J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.49×10−10=1.34×10−15m

Frequency
f=Ephotonh=1.49×10−106.63×10−34=2.25×1023Hz

Conclusion:

Wavelength =1.34×10−15m

Frequency =2.25×1023Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=2.88×103×1.60×10−19=4.61×10−16J

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.61×10−16=4.32×10−10m=0.432nm

Frequency
f=Ephotonh=4.61×10−166.63×10−34=6.95×1017Hz

Conclusion:

Wavelength =0.432nm

Frequency =6.95×1017Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=7.88×1.60×10−19=1.26×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.26×10−18=1.58×10−7m=158nm

Frequency
f=Ephotonh=1.26×10−186.63×10−34=1.90×1015Hz

Conclusion:

Wavelength =158nm

Frequency =1.90×1015Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=13.6×1.60×10−19=2.18×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.18×10−18=9.14×10−8m=91.4nm

Frequency
f=Ephotonh=2.18×10−186.63×10−34=3.28×1015Hz

Conclusion:

Wavelength =91.4nm

Frequency =3.28×1015Hz

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Answer 4

Question

Chapter 22, Problem 48QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 3.45×10−19J ?

Expert Solution

Explanation of Solution

Given info:

Formula used:

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.45×10−19=5.77×10−7m=577nm

Frequency
f=Ephotonh=3.45×10−196.63×10−34=5.20×1014Hz

Conclusion:

Wavelength =577nm

Frequency =5.20×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.80×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.8×10−19=4.14×10−7m=414nm

Frequency
f=Ephotonh=4.80×10−196.63×10−34=7.24×1014Hz

Conclusion:

Wavelength =414nm

Frequency =7.24×1014Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 1.28×10−18J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.28×10−18=1.55×10−7m=155nm

Frequency
f=Ephotonh=1.28×10−186.63×10−34=1.93×1015Hz

Conclusion:

Wavelength =155nm

Frequency =1.93×1015Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 4.33×10−20J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.33×10−20=4.59×10−7m=459nm

Frequency
f=Ephotonh=4.33×10−206.63×10−34=6.53×1013Hz

Conclusion:

Wavelength =459nm

Frequency =6.53×1013Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=931×106×1.60×10−19=1.49×10−10J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.49×10−10=1.34×10−15m

Frequency
f=Ephotonh=1.49×10−106.63×10−34=2.25×1023Hz

Conclusion:

Wavelength =1.34×10−15m

Frequency =2.25×1023Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=2.88×103×1.60×10−19=4.61×10−16J

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.61×10−16=4.32×10−10m=0.432nm

Frequency
f=Ephotonh=4.61×10−166.63×10−34=6.95×1017Hz

Conclusion:

Wavelength =0.432nm

Frequency =6.95×1017Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=7.88×1.60×10−19=1.26×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.26×10−18=1.58×10−7m=158nm

Frequency
f=Ephotonh=1.26×10−186.63×10−34=1.90×1015Hz

Conclusion:

Wavelength =158nm

Frequency =1.90×1015Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=13.6×1.60×10−19=2.18×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.18×10−18=9.14×10−8m=91.4nm

Frequency
f=Ephotonh=2.18×10−186.63×10−34=3.28×1015Hz

Conclusion:

Wavelength =91.4nm

Frequency =3.28×1015Hz

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Answer 5

Chapter 22, Problem 48QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 3.45×10−19J ?

Expert Solution

Explanation of Solution

Given info:

Formula used:

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.45×10−19=5.77×10−7m=577nm

Frequency
f=Ephotonh=3.45×10−196.63×10−34=5.20×1014Hz

Conclusion:

Wavelength =577nm

Frequency =5.20×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.80×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.8×10−19=4.14×10−7m=414nm

Frequency
f=Ephotonh=4.80×10−196.63×10−34=7.24×1014Hz

Conclusion:

Wavelength =414nm

Frequency =7.24×1014Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 1.28×10−18J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.28×10−18=1.55×10−7m=155nm

Frequency
f=Ephotonh=1.28×10−186.63×10−34=1.93×1015Hz

Conclusion:

Wavelength =155nm

Frequency =1.93×1015Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 4.33×10−20J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.33×10−20=4.59×10−7m=459nm

Frequency
f=Ephotonh=4.33×10−206.63×10−34=6.53×1013Hz

Conclusion:

Wavelength =459nm

Frequency =6.53×1013Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=931×106×1.60×10−19=1.49×10−10J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.49×10−10=1.34×10−15m

Frequency
f=Ephotonh=1.49×10−106.63×10−34=2.25×1023Hz

Conclusion:

Wavelength =1.34×10−15m

Frequency =2.25×1023Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=2.88×103×1.60×10−19=4.61×10−16J

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.61×10−16=4.32×10−10m=0.432nm

Frequency
f=Ephotonh=4.61×10−166.63×10−34=6.95×1017Hz

Conclusion:

Wavelength =0.432nm

Frequency =6.95×1017Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=7.88×1.60×10−19=1.26×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.26×10−18=1.58×10−7m=158nm

Frequency
f=Ephotonh=1.26×10−186.63×10−34=1.90×1015Hz

Conclusion:

Wavelength =158nm

Frequency =1.90×1015Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=13.6×1.60×10−19=2.18×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.18×10−18=9.14×10−8m=91.4nm

Frequency
f=Ephotonh=2.18×10−186.63×10−34=3.28×1015Hz

Conclusion:

Wavelength =91.4nm

Frequency =3.28×1015Hz

Answer 6

Chapter 22, Problem 48QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 3.45×10−19J ?

Expert Solution

Explanation of Solution

Given info:

Formula used:

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.45×10−19=5.77×10−7m=577nm

Frequency
f=Ephotonh=3.45×10−196.63×10−34=5.20×1014Hz

Conclusion:

Wavelength =577nm

Frequency =5.20×1014Hz

Answer 7

Chapter 22, Problem 48QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 3.45×10−19J ?

Answer 8

Expert Solution

Explanation of Solution

Given info:

Formula used:

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.45×10−19=5.77×10−7m=577nm

Frequency
f=Ephotonh=3.45×10−196.63×10−34=5.20×1014Hz

Conclusion:

Wavelength =577nm

Frequency =5.20×1014Hz

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

(b)

The wavelength and frequency of photon that have the energy 4.80×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.8×10−19=4.14×10−7m=414nm

Frequency
f=Ephotonh=4.80×10−196.63×10−34=7.24×1014Hz

Conclusion:

Wavelength =414nm

Frequency =7.24×1014Hz

Answer 13

To determine

(b)

The wavelength and frequency of photon that have the energy 4.80×10−19J ?

Answer 14

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.8×10−19=4.14×10−7m=414nm

Frequency
f=Ephotonh=4.80×10−196.63×10−34=7.24×1014Hz

Conclusion:

Wavelength =414nm

Frequency =7.24×1014Hz

Answer 15

Expert Solution

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

To determine

(a)

The wavelength and frequency of photon that have the energy 1.28×10−18J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.28×10−18=1.55×10−7m=155nm

Frequency
f=Ephotonh=1.28×10−186.63×10−34=1.93×1015Hz

Conclusion:

Wavelength =155nm

Frequency =1.93×1015Hz

Answer 19

To determine

(a)

The wavelength and frequency of photon that have the energy 1.28×10−18J ?

Answer 20

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.28×10−18=1.55×10−7m=155nm

Frequency
f=Ephotonh=1.28×10−186.63×10−34=1.93×1015Hz

Conclusion:

Wavelength =155nm

Frequency =1.93×1015Hz

Answer 21

Expert Solution

Answer 22

Expert Solution

Answer 23

Expert Solution

Answer 24

To determine

(a)

The wavelength and frequency of photon that have the energy 4.33×10−20J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.33×10−20=4.59×10−7m=459nm

Frequency
f=Ephotonh=4.33×10−206.63×10−34=6.53×1013Hz

Conclusion:

Wavelength =459nm

Frequency =6.53×1013Hz

Answer 25

To determine

(a)

The wavelength and frequency of photon that have the energy 4.33×10−20J ?

Answer 26

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.33×10−20=4.59×10−7m=459nm

Frequency
f=Ephotonh=4.33×10−206.63×10−34=6.53×1013Hz

Conclusion:

Wavelength =459nm

Frequency =6.53×1013Hz

Answer 27

Expert Solution

Answer 28

Expert Solution

Answer 29

Expert Solution

Answer 30

To determine

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=931×106×1.60×10−19=1.49×10−10J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.49×10−10=1.34×10−15m

Frequency
f=Ephotonh=1.49×10−106.63×10−34=2.25×1023Hz

Conclusion:

Wavelength =1.34×10−15m

Frequency =2.25×1023Hz

Answer 31

To determine

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

Answer 32

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=931×106×1.60×10−19=1.49×10−10J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.49×10−10=1.34×10−15m

Frequency
f=Ephotonh=1.49×10−106.63×10−34=2.25×1023Hz

Conclusion:

Wavelength =1.34×10−15m

Frequency =2.25×1023Hz

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

To determine

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=2.88×103×1.60×10−19=4.61×10−16J

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.61×10−16=4.32×10−10m=0.432nm

Frequency
f=Ephotonh=4.61×10−166.63×10−34=6.95×1017Hz

Conclusion:

Wavelength =0.432nm

Frequency =6.95×1017Hz

Answer 37

To determine

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

Answer 38

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=2.88×103×1.60×10−19=4.61×10−16J

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.61×10−16=4.32×10−10m=0.432nm

Frequency
f=Ephotonh=4.61×10−166.63×10−34=6.95×1017Hz

Conclusion:

Wavelength =0.432nm

Frequency =6.95×1017Hz

Answer 39

Expert Solution

Answer 40

Expert Solution

Answer 41

Expert Solution

Answer 42

To determine

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=7.88×1.60×10−19=1.26×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.26×10−18=1.58×10−7m=158nm

Frequency
f=Ephotonh=1.26×10−186.63×10−34=1.90×1015Hz

Conclusion:

Wavelength =158nm

Frequency =1.90×1015Hz

Answer 43

To determine

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

Answer 44

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=7.88×1.60×10−19=1.26×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.26×10−18=1.58×10−7m=158nm

Frequency
f=Ephotonh=1.26×10−186.63×10−34=1.90×1015Hz

Conclusion:

Wavelength =158nm

Frequency =1.90×1015Hz

Answer 45

Expert Solution

Answer 46

Expert Solution

Answer 47

Expert Solution

Answer 48

To determine

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=13.6×1.60×10−19=2.18×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.18×10−18=9.14×10−8m=91.4nm

Frequency
f=Ephotonh=2.18×10−186.63×10−34=3.28×1015Hz

Conclusion:

Wavelength =91.4nm

Frequency =3.28×1015Hz

Answer 49

To determine

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?

Answer 50

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=13.6×1.60×10−19=2.18×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.18×10−18=9.14×10−8m=91.4nm

Frequency
f=Ephotonh=2.18×10−186.63×10−34=3.28×1015Hz

Conclusion:

Wavelength =91.4nm

Frequency =3.28×1015Hz

Answer 51

Expert Solution

Answer 52

Expert Solution

Answer 53

Expert Solution

Answer 54

Ch. 22 - Prob. 1QAP Ch. 22 - Prob. 2QAP Ch. 22 - Prob. 3QAP Ch. 22 - Prob. 4QAP Ch. 22 - Prob. 5QAP Ch. 22 - Prob. 6QAP Ch. 22 - Prob. 7QAP Ch. 22 - Prob. 8QAP Ch. 22 - Prob. 9QAP Ch. 22 - Prob. 10QAP

(a) The wavelength and frequency of photon that have the energy 3.45 × 10 − 19 J ?

Concept explainers

(a)

The wavelength and frequency of photon that have the energy 3.45×10−19J ?

Explanation of Solution

(b)

The wavelength and frequency of photon that have the energy 4.80×10−19J ?

Explanation of Solution

(a)

The wavelength and frequency of photon that have the energy 1.28×10−18J ?

Explanation of Solution

(a)

The wavelength and frequency of photon that have the energy 4.33×10−20J ?

Explanation of Solution

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

Explanation of Solution

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

Explanation of Solution

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

Explanation of Solution

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?

Explanation of Solution

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Chapter 22 Solutions

(a) The wavelength and frequency of photon that have the energy 3.45 × 10 − 19 J ?

Concept explainers

(a) The wavelength and frequency of photon that have the energy 3.45×10−19J ?

Explanation of Solution

(b) The wavelength and frequency of photon that have the energy 4.80×10−19J ?

Explanation of Solution

(a) The wavelength and frequency of photon that have the energy 1.28×10−18J ?

Explanation of Solution

(a) The wavelength and frequency of photon that have the energy 4.33×10−20J ?

Explanation of Solution

(e) The wavelength and frequency of photon that have the energy 931MeV ?

Explanation of Solution

(f) The wavelength and frequency of photon that have the energy 2.88keV ?

Explanation of Solution

(g) The wavelength and frequency of photon that have the energy 7.88eV ?

Explanation of Solution

(h) The wavelength and frequency of photon that have the energy 13.6eV ?

Explanation of Solution

Want to see more full solutions like this?

Chapter 22 Solutions

(a)

The wavelength and frequency of photon that have the energy 3.45×10−19J ?

(b)

The wavelength and frequency of photon that have the energy 4.80×10−19J ?

(a)

The wavelength and frequency of photon that have the energy 1.28×10−18J ?

(a)

The wavelength and frequency of photon that have the energy 4.33×10−20J ?

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?