COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
2nd Edition
ISBN: 9781319414597
Author: Freedman
Publisher: MAC HIGHER
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Chapter 22, Problem 48QAP
To determine

(a)

The wavelength and frequency of photon that have the energy 3.45×1019J ?

Expert Solution
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Explanation of Solution

Given info:

Formula used:

Calculation:

Wavelength
  λ=hcEphoton=6.63×1034×3×1083.45×1019=5.77×107m=577nm

Frequency
  f=Ephotonh=3.45×10196.63×1034=5.20×1014Hz

Conclusion:

Wavelength =577nm

Frequency =5.20×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.80×1019J ?

Expert Solution
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Explanation of Solution

Calculation:

Wavelength
  λ=hcEphoton=6.63×1034×3×1084.8×1019=4.14×107m=414nm

Frequency
  f=Ephotonh=4.80×10196.63×1034=7.24×1014Hz

Conclusion:

Wavelength =414nm

Frequency =7.24×1014Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 1.28×1018J ?

Expert Solution
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Explanation of Solution

Calculation:

Wavelength
  λ=hcEphoton=6.63×1034×3×1081.28×1018=1.55×107m=155nm

Frequency
  f=Ephotonh=1.28×10186.63×1034=1.93×1015Hz

Conclusion:

Wavelength =155nm

Frequency =1.93×1015Hz

To determine

(a)

The wavelength and frequency of photon that have the energy 4.33×1020J ?

Expert Solution
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Explanation of Solution

Calculation:

Wavelength
  λ=hcEphoton=6.63×1034×3×1084.33×1020=4.59×107m=459nm

Frequency
  f=Ephotonh=4.33×10206.63×1034=6.53×1013Hz

Conclusion:

Wavelength =459nm

Frequency =6.53×1013Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 931MeV ?

Expert Solution
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Explanation of Solution

Calculation:

Energy in joules,
  Ephoton=931×106×1.60×1019=1.49×1010J

Wavelength
  λ=hcEphoton=6.63×1034×3×1081.49×1010=1.34×1015m

Frequency
  f=Ephotonh=1.49×10106.63×1034=2.25×1023Hz

Conclusion:

Wavelength =1.34×1015m

Frequency =2.25×1023Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 2.88keV ?

Expert Solution
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Explanation of Solution

Calculation:

Energy in joules,
  Ephoton=2.88×103×1.60×1019=4.61×1016J

Wavelength
  λ=hcEphoton=6.63×1034×3×1084.61×1016=4.32×1010m=0.432nm

Frequency
  f=Ephotonh=4.61×10166.63×1034=6.95×1017Hz

Conclusion:

Wavelength =0.432nm

Frequency =6.95×1017Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 7.88eV ?

Expert Solution
Check Mark

Explanation of Solution

Calculation:

Energy in joules,
  Ephoton=7.88×1.60×1019=1.26×1018J

Wavelength
  λ=hcEphoton=6.63×1034×3×1081.26×1018=1.58×107m=158nm

Frequency
  f=Ephotonh=1.26×10186.63×1034=1.90×1015Hz

Conclusion:

Wavelength =158nm

Frequency =1.90×1015Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 13.6eV ?

Expert Solution
Check Mark

Explanation of Solution

Calculation:

Energy in joules,
  Ephoton=13.6×1.60×1019=2.18×1018J

Wavelength
  λ=hcEphoton=6.63×1034×3×1082.18×1018=9.14×108m=91.4nm

Frequency
  f=Ephotonh=2.18×10186.63×1034=3.28×1015Hz

Conclusion:

Wavelength =91.4nm

Frequency =3.28×1015Hz

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