Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine Concept Introduction : A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows: a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide b) Alkyl bromide in azide synthesis produces primary amine c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton e) Alkene on ozonolysis produces carbonyl compounds f) Alkyl halides with strong base gives alkene g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines . Using these concepts, we can transfer 1-hexanol into the given compounds.

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Answer 1

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

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Calculating the pH of a salt solution Calculate the pH at 25 °C of a 0.29M solution of potassium butanoate (KC3H,CO2). Note that butanoic acid (HC3H,CO2) is a weak acid with a pKa of 4.82. Round your answer to 1 decimal place. pH = -0 Х olo 18 Ar

: At a certain temperature, the equilibrium constant K for the following reaction is 1.58 × 10-12 N2(g) + O2(g) = 2 NO(g) Use this information to complete the following table. Suppose a 38. L reaction vessel is filled with 0.93 mol of N2 and 0.93 mol of O2. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little N2 and O2. There will be very little NO. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 NO(g) N2(9)+02(9) What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 3 N2(9)+302(g) 6 NO(g) Neither of the above is true. K = ☐ K = ☐ ☐ X10 Х D ? 000 18 Ar B

Answer 2

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

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See solution

Answer 3

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

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Check out a sample textbook solution

See solution

Answer 5

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 6

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 7

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 8

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 9

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 10

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 11

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 22.2 - Prob. 1LTS Ch. 22.2 - Prob. 1PTS Ch. 22.2 - Prob. 2PTS Ch. 22.3 - Prob. 4CC Ch. 22.3 - Prob. 5CC Ch. 22.3 - Prob. 6CC Ch. 22.3 - Prob. 7CC Ch. 22.3 - Prob. 8CC Ch. 22.3 - Prob. 9CC Ch. 22.4 - Prob. 10CC

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Chapter 22 Solutions