‘Crystal field splitting energys’ should be identified. Concept introduction: Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows; E = hc λ where, h is planks constant c is speed of light λ is wavelength. Given: Wavelength of 735 nm for [CrC1 6 ] 3- ion.

Question

Want to see the full answer?

Answer 1

Question

Chapter 22, Problem 43E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energys’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 735 nm for [CrC1₆]^3- ion.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Show reaction mechanism with explanation.don't give Ai generated solution

Please answer the questions and provide detailed explanations.

Show reaction mechanism. Don't give Ai generated solution

Answer 2

Question

Chapter 22, Problem 43E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energys’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 735 nm for [CrC1₆]^3- ion.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 22, Problem 43E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energys’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 735 nm for [CrC1₆]^3- ion.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22, Problem 43E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energys’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 735 nm for [CrC1₆]^3- ion.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 22, Problem 43E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energys’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 735 nm for [CrC1₆]^3- ion.

Answer 6

Chapter 22, Problem 43E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energys’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 735 nm for [CrC1₆]^3- ion.

Answer 7

Chapter 22, Problem 43E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energys’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 735 nm for [CrC1₆]^3- ion.

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 22 - When a transition metal atom forms an ion, which...Ch. 22 - Explain why transition metals exhibit multiple...Ch. 22 - Why is the +2 oxidation state so common for...Ch. 22 - Explain why atomic radii of elements in the third...Ch. 22 - Gold is the most electronegative transition metal....Ch. 22 - Prob. 6E Ch. 22 - Prob. 7E Ch. 22 - Explain the differences between each pair of...Ch. 22 - Prob. 9E Ch. 22 - Prob. 10E

Solution Summary: The author explains that crystal field splitting energy is 163.2 kJ/mol. Weak field ligand is present in the given complex.

Concept explainers

Videos

Want to see the full answer?

Chapter 22 Solutions