Chapter 22, Problem 40P

To determine

The ranking of the intensities of the light transmitted through the second polarizer from the greatest to least. The angles the transmission axes of the first and second polarizers make with the horizontal are given as (a).${\theta }_1=0°,{\theta }_{\text{2}}=30°$;(b)${\theta }_{\text{1}}=30°,{\theta }_{\text{2}}=30°$;(c)${\theta }_1=0°,{\theta }_{\text{2}}=90°$;(d)${\theta }_1=60°,{\theta }_{\text{2}}=0°$;(e) ${\theta }_{\text{1}}=30°,{\theta }_{\text{2}}=60°$ .