Explanation Given data: Length of the column of blood in the artery ( L ) is 20 cm, which is written as 0.20 m. Diameter of the artery ( d ) is 1.0 cm, which is written as 0.01 m. Formula used: Write the expression for resistance in terms of resistivity and dimensions. R = ρ L A (1) Here, ρ is the resistivity of material, L is the length of the material, and A is the cross-section area of the material. Write the expression for cross-section area of the material as follows. A = π r 2 (2) Here, r is the radius of the material, which is half of the diameter of the material. Explanation: From equation (2), substitute π r 2 for A in equation (1). R = ρ L π r 2 (3) Refer to the Table 22.1 in the textbook for resistivitites of materials. From the table, the resistivity of the blood is 1.6 Ω ⋅ m . As the diameter of the artery is 0.01 m, the radius of the artery is 0.005 m. Substitute 1.6 Ω ⋅ m for ρ , 0.20 m for L , and 0.005 m for r in equation (3), R = ( 1

Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+)

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ISBN: 9780137561520

Author: Randall Knight, Brian Jones

Publisher: PEARSON+

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Temperature Variance of Resistance

Electrical resistance or simply resistance is the property of a material that opposes the free flow of electrons through it. The total amount of resistance to the flow of charges (or current) is affected by many factors like the length of the conducting …

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Chapter 22, Problem 24P

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To find: The resistance of blood in the artery.

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Chapter 22, Problem 23P

Chapter 22, Problem 25P

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Chapter 22 Solutions

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Chapter 22 Solutions