General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 22, Problem 22.44QP
Interpretation Introduction
Interpretation:
The following observation has to be explained.
“When deoxyhemoglobin crystals are exposed to oxygen they shatter. On the other hand deoxymyoglobin crystals are unaffected by oxygen.”
Concept Introduction:
Hemoglobin is a globular protein. It consists of four sub-units. Hemoglobin binds to oxygen and transports it to various organs in our body for their proper biological functioning. When
Myoglobin is also a globular protein and it consists of only one unit. It stores oxygen in muscle cells.
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Please help with number 6 I got a negative number could that be right?
1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.
Give the product of the bimolecular elimination from each of the isomeric halogenated compounds.
Reaction A
Reaction B.
КОВ
CH₂
HotBu
+B+
ко
HOIBU
+Br+
Templates More
QQQ
Select Cv Templates More
Cras
QQQ
One of these compounds undergoes elimination 50x faster than the other. Which one and why?
Reaction A because the conformation needed for elimination places the phenyl groups and to each other
Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other.
◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other.
Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.
Chapter 22 Solutions
General Chemistry
Ch. 22.2 - Prob. 1RCCh. 22.3 - Prob. 1RCCh. 22.4 - Prob. 1RCCh. 22 - Prob. 22.1QPCh. 22 - Prob. 22.2QPCh. 22 - Prob. 22.3QPCh. 22 - Prob. 22.4QPCh. 22 - Prob. 22.6QPCh. 22 - Prob. 22.7QPCh. 22 - Prob. 22.8QP
Ch. 22 - Prob. 22.9QPCh. 22 - Prob. 22.10QPCh. 22 - Prob. 22.11QPCh. 22 - Prob. 22.12QPCh. 22 - Prob. 22.13QPCh. 22 - Prob. 22.14QPCh. 22 - Prob. 22.15QPCh. 22 - Prob. 22.16QPCh. 22 - Prob. 22.17QPCh. 22 - Prob. 22.18QPCh. 22 - Prob. 22.19QPCh. 22 - Prob. 22.20QPCh. 22 - Prob. 22.21QPCh. 22 - Prob. 22.22QPCh. 22 - Prob. 22.23QPCh. 22 - Prob. 22.24QPCh. 22 - Prob. 22.25QPCh. 22 - Prob. 22.26QPCh. 22 - Prob. 22.27QPCh. 22 - Prob. 22.28QPCh. 22 - Prob. 22.29QPCh. 22 - Prob. 22.30QPCh. 22 - Prob. 22.31QPCh. 22 - Prob. 22.32QPCh. 22 - Prob. 22.33QPCh. 22 - Prob. 22.34QPCh. 22 - Prob. 22.35QPCh. 22 - Prob. 22.36QPCh. 22 - Prob. 22.37QPCh. 22 - Prob. 22.38QPCh. 22 - Prob. 22.39QPCh. 22 - Prob. 22.40QPCh. 22 - Prob. 22.41QPCh. 22 - Prob. 22.42QPCh. 22 - Prob. 22.43QPCh. 22 - Prob. 22.44QPCh. 22 - Prob. 22.45SPCh. 22 - Prob. 22.46SPCh. 22 - Prob. 22.47SPCh. 22 - Prob. 22.48SPCh. 22 - Prob. 22.49SPCh. 22 - Prob. 22.50SPCh. 22 - Prob. 22.51SPCh. 22 - Prob. 22.52SP
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