Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Chapter 22, Problem 16E

Explanation of Solution

a)

Attribute that are candidate for partitioning:

  • In parallel systems, the data gets partitioned over different disks. The partitions are performed based on the attribute present in the relation.
  • Consider a relation with specified work load of SQL queries. The candidate attribute for the partitioning would be
  • The one which has maximum queries that holds selection condition. The condition is then evaluated using a single processor rather than performing all of them...

Explanation of Solution

b)

Choose between the alternative:

  • To choose between the alternative partitioning techniques the cost based approach would be the best approach.
  • Generate various candidates partitioning choice for each candidate too.
  • The cost of estimating all the queries including the updates in the given workload.
  • Choose the candidate that will lead to least cost.
  • The problem is that usually both the number of candidate attributes and queries can be too large...

Explanation of Solution

c)

Partitioning a relation:

Yes, it is possible to partition a relation on more than one attribute in the following ways;

  • Involving the attributes in a single compound partitioning key...

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Dijkstra's Algorithm (part 1).  Consider the network shown below, and Dijkstra’s link-state algorithm. Here, we are interested in computing the least cost path from node E (note: the start node here is E) to all other nodes using Dijkstra's algorithm. Using the algorithm statement used in the textbook and its visual representation, complete the "Step 0" row in the table below showing the link state algorithm’s execution by matching the table entries (i), (ii), (iii), and (iv) with their values.  Write down your final [correct] answer, as you‘ll need it for the next question.
4. |z + 5 - 5i| = 7
14. dz, C: |z❘ C: |z❘ = 0.6 ze² - 2iz H
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