Explanation Given Information: The fractions are as: 3 5 9 + 5 1 12 + 2 2 3 Formula used: Following steps are used to find the sum of mixed fraction: Step-1: Add the whole number parts of the mixed fraction. Step-2: Now, add the fractional parts and simplify it. Step-3: Convert improper fractions into whole number or mixed fractions. Step-4: Finally, add all the whole numbers and keep the fractional part. Calculation: Consider the fraction as: 3 5 9 + 5 1 12 + 2 2 3 First find the least common denominator of the fraction as: Write the denominator in a row 9 , 12 , 3 . Now, divide each denominator by 2 , the smallest prime factor as, 9 , 12 ÷ 2 = 6 , 3 Divide the quotients by 2 , 9 , 6 ÷ 2 = 3 , 3 Divide the quotients by 3 , 9 ÷ 3 = 3 , 3 ÷ 3 = 1 , 3 ÷ 3 = 1 Divide the quotients by 3 , 3 ÷ 3 = 1 , 1 , 1 Since, all the denominators are down to 1 , therefore the least common denominator is the product of the divisors i.e

11th Edition

ISBN: 8220103632072

Author: NOBLE

Publisher: Pearson Education (US)

See similar textbooks

Concept explainers

Angles in Circles

Angles within a circle are feasible to create with the help of different properties of the circle such as radii, tangents, and chords. The radius is the distance from the center of the circle to the circumference of the circle. A tangent is a line made p…

Arcs in Circles

A circular arc is the arc of a circle formed by two distinct points. It is a section or segment of the circumference of a circle. A straight line passing through the center connecting the two distinct ends of the arc is termed a semi-circular arc.

Videos

Question

Chapter 2.2, Problem 12SE

To determine

To calculate: The sum of the mixed fractions 359+5112+223.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 2.2, Problem 11SE

Chapter 2.2, Problem 13SE

Students have asked these similar questions

(b) Let I[y] be a functional of y(x) defined by [[y] = √(x²y' + 2xyy' + 2xy + y²) dr, subject to boundary conditions y(0) = 0, y(1) = 1. State the Euler-Lagrange equation for finding extreme values of I [y] for this prob- lem. Explain why the function y(x) = x is an extremal, and for this function, show that I = 2. Without doing further calculations, give the values of I for the functions y(x) = x² and y(x) = x³.

Please use mathematical induction to prove this

In simplest terms, Sketch the graph of the parabola. Then, determine its equation. opens downward, vertex is (- 4, 7), passes through point (0, - 39)

Chapter 2 Solutions

EBK BUSINESS MATH

Ch. 2.1 - Prob. 1-1SC Ch. 2.1 - Prob. 1-2SC Ch. 2.1 - Prob. 1-3SC Ch. 2.1 - Prob. 1-4SC Ch. 2.1 - Prob. 1-5SC Ch. 2.1 - Prob. 1-6SC Ch. 2.1 - Prob. 2-1SC Ch. 2.1 - Prob. 2-2SC Ch. 2.1 - Prob. 2-3SC Ch. 2.1 - Prob. 2-4SC

Ch. 2.1 - Prob. 2-5SC Ch. 2.1 - Prob. 3-1SC Ch. 2.1 - Prob. 3-2SC Ch. 2.1 - Prob. 3-3SC Ch. 2.1 - Prob. 3-4SC Ch. 2.1 - Prob. 3-5SC Ch. 2.1 - Prob. 4-1SC Ch. 2.1 - Prob. 4-2SC Ch. 2.1 - Prob. 4-3SC Ch. 2.1 - Prob. 4-4SC Ch. 2.1 - Prob. 4-5SC Ch. 2.1 - Prob. 4-6SC Ch. 2.1 - Prob. 4-7SC Ch. 2.1 - Prob. 4-8SC Ch. 2.1 - Prob. 5-1SC Ch. 2.1 - Prob. 5-2SC Ch. 2.1 - Prob. 5-3SC Ch. 2.1 - Prob. 5-4SC Ch. 2.1 - Prob. 5-5SC Ch. 2.1 - Prob. 5-6SC Ch. 2.1 - Prob. 1SE Ch. 2.1 - Prob. 2SE Ch. 2.1 - Prob. 3SE Ch. 2.1 - Prob. 4SE Ch. 2.1 - Prob. 5SE Ch. 2.1 - Prob. 6SE Ch. 2.1 - Prob. 7SE Ch. 2.1 - Prob. 8SE Ch. 2.1 - Prob. 9SE Ch. 2.1 - Prob. 10SE Ch. 2.1 - Prob. 11SE Ch. 2.1 - Prob. 12SE Ch. 2.1 - Prob. 13SE Ch. 2.1 - Prob. 14SE Ch. 2.1 - Prob. 15SE Ch. 2.1 - Prob. 16SE Ch. 2.1 - Prob. 17SE Ch. 2.1 - Prob. 18SE Ch. 2.1 - Prob. 19SE Ch. 2.1 - Prob. 20SE Ch. 2.1 - Prob. 21SE Ch. 2.1 - Prob. 22SE Ch. 2.1 - Prob. 23SE Ch. 2.1 - Prob. 24SE Ch. 2.1 - Prob. 25SE Ch. 2.1 - Prob. 26SE Ch. 2.1 - Prob. 27SE Ch. 2.1 - Prob. 28SE Ch. 2.1 - Prob. 29SE Ch. 2.1 - Prob. 30SE Ch. 2.1 - Prob. 31SE Ch. 2.1 - Prob. 32SE Ch. 2.1 - Prob. 33SE Ch. 2.1 - Prob. 34SE Ch. 2.1 - Prob. 35SE Ch. 2.1 - Prob. 36SE Ch. 2.1 - Prob. 37SE Ch. 2.1 - Prob. 38SE Ch. 2.2 - Prob. 1-1SC Ch. 2.2 - Prob. 1-2SC Ch. 2.2 - Prob. 1-3SC Ch. 2.2 - Prob. 1-4SC Ch. 2.2 - Prob. 1-5SC Ch. 2.2 - Prob. 2-1SC Ch. 2.2 - Prob. 2-2SC Ch. 2.2 - Prob. 2-3SC Ch. 2.2 - Prob. 2-4SC Ch. 2.2 - Prob. 2-5SC Ch. 2.2 - Prob. 3-1SC Ch. 2.2 - Prob. 3-2SC Ch. 2.2 - Prob. 3-3SC Ch. 2.2 - Prob. 3-4SC Ch. 2.2 - Prob. 3-5SC Ch. 2.2 - Prob. 3-6SC Ch. 2.2 - Prob. 4-1SC Ch. 2.2 - Prob. 4-2SC Ch. 2.2 - Prob. 4-3SC Ch. 2.2 - Prob. 4-4SC Ch. 2.2 - Prob. 4-5SC Ch. 2.2 - Prob. 4-6SC Ch. 2.2 - Prob. 4-7SC Ch. 2.2 - Prob. 4-8SC Ch. 2.2 - Prob. 4-9SC Ch. 2.2 - Prob. 4-10SC Ch. 2.2 - Prob. 1SE Ch. 2.2 - Prob. 2SE Ch. 2.2 - Prob. 3SE Ch. 2.2 - Prob. 4SE Ch. 2.2 - Prob. 5SE Ch. 2.2 - Prob. 6SE Ch. 2.2 - Prob. 7SE Ch. 2.2 - Prob. 8SE Ch. 2.2 - Prob. 9SE Ch. 2.2 - Prob. 10SE Ch. 2.2 - Prob. 11SE Ch. 2.2 - Prob. 12SE Ch. 2.2 - Prob. 13SE Ch. 2.2 - Prob. 14SE Ch. 2.2 - Prob. 15SE Ch. 2.2 - Prob. 16SE Ch. 2.2 - Prob. 17SE Ch. 2.2 - Prob. 18SE Ch. 2.2 - Prob. 19SE Ch. 2.2 - Prob. 20SE Ch. 2.2 - Prob. 21SE Ch. 2.2 - Prob. 22SE Ch. 2.2 - Prob. 23SE Ch. 2.2 - Prob. 24SE Ch. 2.2 - Prob. 25SE Ch. 2.2 - Prob. 26SE Ch. 2.2 - Prob. 27SE Ch. 2.2 - Prob. 28SE Ch. 2.2 - Prob. 29SE Ch. 2.2 - Prob. 30SE Ch. 2.3 - Prob. 1-1SC Ch. 2.3 - Prob. 1-2SC Ch. 2.3 - Prob. 1-3SC Ch. 2.3 - Prob. 1-4SC Ch. 2.3 - Prob. 1-5SC Ch. 2.3 - Prob. 1-6SC Ch. 2.3 - Prob. 1-7SC Ch. 2.3 - Prob. 2-1SC Ch. 2.3 - Prob. 2-2SC Ch. 2.3 - Prob. 2-3SC Ch. 2.3 - Prob. 2-4SC Ch. 2.3 - Prob. 2-5SC Ch. 2.3 - Prob. 2-6SC Ch. 2.3 - Prob. 2-7SC Ch. 2.3 - Prob. 1SE Ch. 2.3 - Prob. 2SE Ch. 2.3 - Prob. 3SE Ch. 2.3 - Prob. 4SE Ch. 2.3 - Prob. 5SE Ch. 2.3 - Prob. 6SE Ch. 2.3 - Prob. 7SE Ch. 2.3 - Prob. 8SE Ch. 2.3 - Prob. 9SE Ch. 2.3 - Prob. 10SE Ch. 2.3 - Prob. 11SE Ch. 2.3 - Prob. 12SE Ch. 2.3 - Prob. 13SE Ch. 2.3 - Prob. 14SE Ch. 2.3 - Prob. 15SE Ch. 2.3 - Prob. 16SE Ch. 2.3 - Prob. 17SE Ch. 2.3 - Prob. 18SE Ch. 2.3 - Prob. 19SE Ch. 2.3 - Prob. 20SE Ch. 2.3 - Prob. 21SE Ch. 2.3 - Prob. 22SE Ch. 2.3 - Prob. 23SE Ch. 2.3 - Prob. 24SE Ch. 2 - Prob. 1ES Ch. 2 - Prob. 2ES Ch. 2 - Prob. 3ES Ch. 2 - Prob. 4ES Ch. 2 - Prob. 5ES Ch. 2 - Prob. 6ES Ch. 2 - Prob. 7ES Ch. 2 - Prob. 8ES Ch. 2 - Prob. 9ES Ch. 2 - Prob. 10ES Ch. 2 - Prob. 11ES Ch. 2 - Prob. 12ES Ch. 2 - Prob. 13ES Ch. 2 - Prob. 14ES Ch. 2 - Prob. 15ES Ch. 2 - Prob. 16ES Ch. 2 - Prob. 17ES Ch. 2 - Prob. 18ES Ch. 2 - Prob. 19ES Ch. 2 - Prob. 20ES Ch. 2 - Prob. 21ES Ch. 2 - Prob. 22ES Ch. 2 - Prob. 23ES Ch. 2 - Prob. 24ES Ch. 2 - Prob. 25ES Ch. 2 - Prob. 26ES Ch. 2 - Prob. 27ES Ch. 2 - Prob. 28ES Ch. 2 - Prob. 29ES Ch. 2 - Prob. 30ES Ch. 2 - Prob. 31ES Ch. 2 - Prob. 32ES Ch. 2 - Prob. 33ES Ch. 2 - Prob. 34ES Ch. 2 - Prob. 35ES Ch. 2 - Prob. 36ES Ch. 2 - Prob. 37ES Ch. 2 - Prob. 38ES Ch. 2 - Prob. 39ES Ch. 2 - Prob. 40ES Ch. 2 - Prob. 41ES Ch. 2 - Prob. 42ES Ch. 2 - Prob. 43ES Ch. 2 - Prob. 44ES Ch. 2 - Prob. 45ES Ch. 2 - Prob. 46ES Ch. 2 - Prob. 47ES Ch. 2 - Prob. 48ES Ch. 2 - Prob. 49ES Ch. 2 - Prob. 50ES Ch. 2 - Prob. 51ES Ch. 2 - Prob. 52ES Ch. 2 - Prob. 53ES Ch. 2 - Prob. 54ES Ch. 2 - Prob. 55ES Ch. 2 - Prob. 56ES Ch. 2 - Prob. 57ES Ch. 2 - Prob. 58ES Ch. 2 - Prob. 59ES Ch. 2 - Prob. 60ES Ch. 2 - Prob. 61ES Ch. 2 - Prob. 62ES Ch. 2 - Prob. 63ES Ch. 2 - Prob. 64ES Ch. 2 - Prob. 65ES Ch. 2 - Prob. 66ES Ch. 2 - Prob. 67ES Ch. 2 - Prob. 68ES Ch. 2 - Prob. 69ES Ch. 2 - Prob. 70ES Ch. 2 - Prob. 71ES Ch. 2 - Prob. 72ES Ch. 2 - Prob. 73ES Ch. 2 - Prob. 74ES Ch. 2 - Prob. 75ES Ch. 2 - Prob. 76ES Ch. 2 - Prob. 78ES Ch. 2 - Prob. 79ES Ch. 2 - Prob. 80ES Ch. 2 - Prob. 81ES Ch. 2 - Prob. 82ES Ch. 2 - Prob. 83ES Ch. 2 - Prob. 84ES Ch. 2 - Prob. 1PT Ch. 2 - Prob. 2PT Ch. 2 - Prob. 3PT Ch. 2 - Prob. 4PT Ch. 2 - Prob. 5PT Ch. 2 - Prob. 6PT Ch. 2 - Prob. 7PT Ch. 2 - Prob. 8PT Ch. 2 - Prob. 9PT Ch. 2 - Prob. 10PT Ch. 2 - Prob. 11PT Ch. 2 - Prob. 12PT Ch. 2 - Prob. 13PT Ch. 2 - Prob. 14PT Ch. 2 - Prob. 15PT Ch. 2 - Prob. 16PT Ch. 2 - Prob. 17PT Ch. 2 - Prob. 18PT Ch. 2 - Prob. 19PT Ch. 2 - Prob. 20PT Ch. 2 - Prob. 21PT Ch. 2 - Prob. 22PT Ch. 2 - Prob. 23PT Ch. 2 - Prob. 24PT Ch. 2 - Prob. 1CT Ch. 2 - Prob. 2CT Ch. 2 - Prob. 3CT Ch. 2 - Prob. 4CT Ch. 2 - Prob. 5CT Ch. 2 - Prob. 6CT Ch. 2 - Prob. 7CT Ch. 2 - Prob. 8CT Ch. 2 - Prob. 9CT Ch. 2 - Prob. 10CT Ch. 2 - Prob. 11CT Ch. 2 - Prob. 12CT Ch. 2 - Prob. 1CP Ch. 2 - Prob. 2CP Ch. 2 - Prob. 1CS1 Ch. 2 - Prob. 2CS1 Ch. 2 - Prob. 3CS1 Ch. 2 - Prob. 1CS2 Ch. 2 - Prob. 2CS2 Ch. 2 - Prob. 3CS2 Ch. 2 - Prob. 4CS2

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.

The sum of the mixed fractions 3 5 9 + 5 1 12 + 2 2 3 .

Concept explainers

Videos

To calculate: The sum of the mixed fractions 359+5112+223.

Want to see the full answer?

Chapter 2 Solutions