Chapter 2.2, Problem 11E

To determine

To draw: The graph of parabola, Label the vertex and axis of symmetry.

Explanation of Solution

Given information: In the question, $y=-\frac{1}{4}{(x+2)}^2+1$ is given, after looking to this function, we can say that vertex is $V(-2,1)$ .

Graph: In graph gap between two vertical lines is 2 unit and two horizontal lines is 2 unit.

  

Axis of symmetry $x=-2$

Interpretation: Observe the graph carefully, Vertex is $V(-2,1)$ , and axis of symmetry is $x=-2$ , we know the parabola equation in vertex form $y=a{(x-h)}^2+k$ , $(h,k)$ is vertex of parabola. Here $(h,k)=(-2,1)$ and $x=h$ is axis of symmetry. If I use this coordinate of vertex, and axis of symmetry, then we can complete the parabola.