EBK ORGANIC CHEMISTRY AS A SECOND LANGU
EBK ORGANIC CHEMISTRY AS A SECOND LANGU
4th Edition
ISBN: 9781119234715
Author: Klein
Publisher: VST
Question
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Chapter 21.7, Problem 42PTS

(a)

Interpretation Introduction

Interpretation:

Using cyclopentanone as a starting material, synthesis of given compounds need to be proposed.

Concept introduction:

The addition of an enamine to α,β -unsaturated carbonyl acceptor (Michael acceptor) to form dicarbonyl compound is known as Stork enamine synthesis.  The difference between Michael addition and stork enamine is that for Michael addition to take place the enolate formed should be doubly stabilized.  The product is then hydrolyzed by an aqueous acid to produce 1,5-dicarbonyl compound.  Steps involved in Stork enamine synthesis are,

  • Formation of an enamine
  • Michael addition
  • Hydrolysis

(b)

Interpretation Introduction

Interpretation:

Using cyclopentanone as a starting material, synthesis of given compounds need to be proposed.

Concept introduction:

If the product is 1,3-difunctionalized means either it has to prepared via Aldol addition or Claisen condensation reaction.

Williamson ether synthesis is the synthesis of ether when alkoxide reacts with an alkyl halide.

(c)

Interpretation Introduction

Interpretation:

Using cyclopentanone as a starting material, synthesis of given compounds need to be proposed.

Concept introduction:

The addition of an enamine to α,β -unsaturated carbonyl acceptor (Michael acceptor) to form dicarbonyl compound is known as Stork enamine synthesis.  The difference between Michael addition and stork enamine is that for Michael addition to take place the enolate formed should be doubly stabilized.  The product is then hydrolyzed by an aqueous acid to produce 1,5-dicarbonyl compound.  Steps involved in Stork enamine synthesis are,

  • Formation of an enamine
  • Michael addition
  • Hydrolysis

The formed 1,5-dicarbonyl compound undergoes reduction when treated with LAH to give 1,5-dihydroxy compound.

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Chapter 21 Solutions

EBK ORGANIC CHEMISTRY AS A SECOND LANGU

Ch. 21.2 - Prob. 10CCCh. 21.2 - Prob. 11CCCh. 21.2 - Prob. 12CCCh. 21.2 - Prob. 13CCCh. 21.3 - Prob. 2LTSCh. 21.3 - Prob. 14PTSCh. 21.3 - Prob. 15PTSCh. 21.3 - Prob. 3LTSCh. 21.3 - Prob. 4LTSCh. 21.3 - Prob. 19PTSCh. 21.3 - Prob. 21CCCh. 21.3 - Prob. 22CCCh. 21.3 - Prob. 23CCCh. 21.4 - Prob. 24CCCh. 21.4 - Prob. 25CCCh. 21.4 - Prob. 26CCCh. 21.4 - Prob. 27CCCh. 21.4 - Prob. 28CCCh. 21.5 - Prob. 29CCCh. 21.5 - Prob. 30CCCh. 21.5 - Prob. 5LTSCh. 21.5 - Prob. 31PTSCh. 21.5 - Prob. 6LTSCh. 21.5 - Prob. 33PTSCh. 21.5 - Prob. 34ATSCh. 21.6 - Prob. 35CCCh. 21.6 - Prob. 36CCCh. 21.6 - Prob. 37CCCh. 21.6 - Prob. 7LTSCh. 21.6 - Prob. 38PTSCh. 21.7 - Prob. 8LTSCh. 21.7 - Prob. 42PTSCh. 21.7 - Prob. 43PTSCh. 21 - Prob. 47PPCh. 21 - Prob. 48PPCh. 21 - Prob. 49PPCh. 21 - Prob. 50PPCh. 21 - Prob. 51PPCh. 21 - Prob. 52PPCh. 21 - Prob. 53PPCh. 21 - Prob. 54PPCh. 21 - Prob. 55PPCh. 21 - Prob. 56PPCh. 21 - Prob. 57PPCh. 21 - Prob. 58PPCh. 21 - Prob. 59PPCh. 21 - Prob. 60PPCh. 21 - Prob. 61PPCh. 21 - Prob. 62PPCh. 21 - Prob. 63PPCh. 21 - Prob. 64PPCh. 21 - Prob. 65PPCh. 21 - Prob. 66PPCh. 21 - Prob. 67PPCh. 21 - Prob. 68PPCh. 21 - Prob. 69PPCh. 21 - Prob. 70PPCh. 21 - Prob. 71PPCh. 21 - Prob. 72PPCh. 21 - Prob. 73PPCh. 21 - Prob. 74PPCh. 21 - Prob. 75PPCh. 21 - Prob. 76PPCh. 21 - Prob. 77PPCh. 21 - Prob. 78PPCh. 21 - Prob. 79PPCh. 21 - Prob. 80PPCh. 21 - Prob. 81PPCh. 21 - Prob. 82PPCh. 21 - Prob. 83PPCh. 21 - Prob. 84PPCh. 21 - Prob. 85PPCh. 21 - Prob. 86PPCh. 21 - Prob. 87PPCh. 21 - Prob. 88PPCh. 21 - Prob. 97IPCh. 21 - Prob. 98IPCh. 21 - Prob. 99IPCh. 21 - Prob. 100IPCh. 21 - Prob. 101IPCh. 21 - Prob. 107IPCh. 21 - Prob. 108IPCh. 21 - Prob. 109IP
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