Chemistry: The Central Science (14th Edition)
14th Edition
ISBN: 9780134414232
Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus
Publisher: PEARSON
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Question
Chapter 21.4, Problem 21.5.2PE
Interpretation Introduction
Interpretation: The information regarding the process of medical imaging using carbon
Concept introduction: The half life of a nuclear reaction is the time required by a radioactive element to decay to half of its initial concentration.
To determine: The percentage of the original carbon
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4. C6H100
5
I peak
3
2
PPM
Integration values: 1.79ppm (2), 4.43ppm (1.33)
Ipeak
None
3. Consider the compounds below and determine if they are aromatic, antiaromatic, or
non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I
electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly
drawn and you should be able to tell that the bonding electrons and lone pair electrons
should reside in which hybridized atomic orbital 2. You should consider ring strain-
flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti-
aromaticity)
H H
N
N:
NH2
N
Aromaticity
(Circle)
Aromatic Aromatic Aromatic Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic TT
electrons
Me
H
Me
Aromaticity
(Circle)
Aromatic Aromatic Aromatic
Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic πT
electrons
H
HH…
Chapter 21 Solutions
Chemistry: The Central Science (14th Edition)
Ch. 21.1 - Prob. 21.1.1PECh. 21.1 - Prob. 21.1.2PECh. 21.1 - Prob. 21.2.1PECh. 21.1 - Prob. 21.2.2PECh. 21.2 - Prob. 21.3.1PECh. 21.2 - Prob. 21.3.2PECh. 21.3 - Prob. 21.4.1PECh. 21.3 - Prob. 21.4.2PECh. 21.4 - Prob. 21.5.1PECh. 21.4 - Prob. 21.5.2PE
Ch. 21.4 - Prob. 21.6.1PECh. 21.4 - Prob. 21.6.2PECh. 21.4 - Prob. 21.7.1PECh. 21.4 - Prob. 21.7.2PECh. 21.6 - Prob. 21.8.1PECh. 21.6 - Prob. 21.8.2PECh. 21 - Prob. 1DECh. 21 - Prob. 1ECh. 21 - Prob. 2ECh. 21 - Prob. 3ECh. 21 - Prob. 4ECh. 21 - Prob. 5ECh. 21 - Prob. 6ECh. 21 - Prob. 7ECh. 21 - Prob. 8ECh. 21 - Prob. 9ECh. 21 - Prob. 10ECh. 21 - Prob. 11ECh. 21 - Prob. 12ECh. 21 - Prob. 13ECh. 21 - Prob. 14ECh. 21 - Prob. 15ECh. 21 - Prob. 16ECh. 21 - Prob. 17ECh. 21 - Prob. 18ECh. 21 - Prob. 19ECh. 21 - Prob. 20ECh. 21 - Prob. 21ECh. 21 - Prob. 22ECh. 21 - Prob. 23ECh. 21 - Prob. 24ECh. 21 - Prob. 25ECh. 21 - Prob. 26ECh. 21 - Prob. 27ECh. 21 - Prob. 28ECh. 21 - Prob. 29ECh. 21 - Prob. 30ECh. 21 - Prob. 31ECh. 21 - Prob. 32ECh. 21 - Prob. 33ECh. 21 - Prob. 34ECh. 21 - Prob. 35ECh. 21 - Prob. 36ECh. 21 - Prob. 37ECh. 21 - Prob. 38ECh. 21 - Prob. 39ECh. 21 - Prob. 40ECh. 21 - Prob. 41ECh. 21 - Prob. 42ECh. 21 - Prob. 43ECh. 21 - Prob. 44ECh. 21 - Prob. 45ECh. 21 - Prob. 46ECh. 21 - Prob. 47ECh. 21 - Prob. 48ECh. 21 - The atomic masses of hydrogen-2 (deuterium),...Ch. 21 - Prob. 50ECh. 21 - Prob. 51ECh. 21 - Prob. 52ECh. 21 - Prob. 53ECh. 21 - Prob. 54ECh. 21 - Prob. 55ECh. 21 - Prob. 56ECh. 21 - Prob. 57ECh. 21 - Prob. 58ECh. 21 - Prob. 59ECh. 21 - Prob. 60ECh. 21 - Prob. 61ECh. 21 - Prob. 62ECh. 21 - Prob. 63ECh. 21 - Prob. 64ECh. 21 - Prob. 65ECh. 21 - Prob. 66ECh. 21 - Prob. 67ECh. 21 - Prob. 68ECh. 21 - Prob. 69ECh. 21 - Prob. 70ECh. 21 - Prob. 71AECh. 21 - Prob. 72AECh. 21 - Prob. 73AECh. 21 - Prob. 74AECh. 21 - Prob. 75AECh. 21 - Prob. 76AECh. 21 - Prob. 77AECh. 21 - Prob. 78AECh. 21 - Prob. 79AECh. 21 - Prob. 80AECh. 21 - Prob. 81AECh. 21 - Prob. 82AECh. 21 - Prob. 83AECh. 21 - Prob. 84AECh. 21 - Prob. 85AECh. 21 - Prob. 86AECh. 21 - Prob. 87IECh. 21 - Prob. 88IECh. 21 - Prob. 89IECh. 21 - Prob. 90IECh. 21 - Prob. 91IECh. 21 - Prob. 92IE
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- A chemistry graduate student is studying the rate of this reaction: 2 HI (g) →H2(g) +12(g) She fills a reaction vessel with HI and measures its concentration as the reaction proceeds: time (minutes) [IH] 0 0.800M 1.0 0.301 M 2.0 0.185 M 3.0 0.134M 4.0 0.105 M Use this data to answer the following questions. Write the rate law for this reaction. rate = 0 Calculate the value of the rate constant k. k = Round your answer to 2 significant digits. Also be sure your answer has the correct unit symbol.arrow_forwardNonearrow_forwardNonearrow_forward
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