EBK ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG
4th Edition
ISBN: 9781119659525
Author: Klein
Publisher: WILEY CONS
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Question
Chapter 21.2, Problem 8CC
(a)
Interpretation Introduction
Interpretation:
To identify which compound is more acidic in a given set of compounds.
Concept introduction:
Keto-enol isomerization is possible when a keto group present in the compound has a movable hydrogen atom in the next carbon attached to the carbonyl group. This occurs generally in almost all keto compounds where a chemical equilibria is present between the keto and enol form of the compound. Conversion of keto to its enol form is known as keto-enol tautomerisation. If the formed enolate (conjugate base) is stabilized by delocalization of the charge and if the hydrogen that is going to be removed are surrounded by more electron withdrawing groups then that compound is said to be more acidic.
To Find : To find which compound is more acidic
(b)
Interpretation Introduction
Interpretation:
To identify which compound is more acidic in a given set of compounds.
Concept introduction:
Keto-enol isomerization is possible when a keto group present in the compound has a movable hydrogen atom in the next carbon attached to the carbonyl group. This occurs generally in almost all keto compounds where a chemical equilibria is present between the keto and enol form of the compound. Conversion of keto to its enol form is known as keto-enol tautomerisation. If the formed enolate (conjugate base) is stabilized by delocalization of the charge and if the hydrogen that is going to be removed are surrounded by more electron withdrawing groups then that compound is said to be more acidic.
To Find : To find which compound is more acidic
(c)
Interpretation Introduction
Interpretation:
To identify which compound is more acidic in a given set of compounds.
Concept introduction:
Keto-enol isomerization is possible when a keto group present in the compound has a movable hydrogen atom in the next carbon attached to the carbonyl group. This occurs generally in almost all keto compounds where a chemical equilibria is present between the keto and enol form of the compound. Conversion of keto to its enol form is known as keto-enol tautomerisation. If the formed enolate (conjugate base) is stabilized by delocalization of the charge and if the hydrogen that is going to be removed are surrounded by more electron withdrawing groups then that compound is said to be more acidic.
To Find : To find which compound is more acidic
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Please explain your steps and thought process. Thank you!
Using the general properties of equilibrium constants
At a certain temperature, the equilibrium constant K for the following reaction is 1.3 × 10 4:
Cl2(g) + CHCl3(g) HCl(g) + CC₁(g)
Use this information to complete the following table.
Suppose a 16. L reaction vessel is filled with 1.6 mol of HCI and
1.6 mol of CCl4. What can you say about the composition of the
mixture in the vessel at equilibrium?
There will be very little Cl2 and CHCl3.
☐ x10
There will be very little HCI and CCl4.
Neither of the above is true.
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
HCl(g)+CC14(g)
12
Cl2(9)+CHCl3(9)
K = 0 ☐
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
2 Cl₂(9)+2CHCl3(9)
2 HCl(9)+2CC₁₁(9)
K =
✓
00.
18
Ar
Chapter 21 Solutions
EBK ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG
Ch. 21.1 - Prob. 1CCCh. 21.1 - Prob. 2CCCh. 21.1 - Prob. 3CCCh. 21.1 - Prob. 1LTSCh. 21.1 - Prob. 4PTSCh. 21.1 - Prob. 5ATSCh. 21.1 - Prob. 6CCCh. 21.1 - Prob. 7CCCh. 21.2 - Prob. 8CCCh. 21.2 - Prob. 9CC
Ch. 21.2 - Prob. 10CCCh. 21.2 - Prob. 11CCCh. 21.2 - Prob. 12CCCh. 21.2 - Prob. 13CCCh. 21.3 - Prob. 2LTSCh. 21.3 - Prob. 14PTSCh. 21.3 - Prob. 15PTSCh. 21.3 - Prob. 3LTSCh. 21.3 - Prob. 4LTSCh. 21.3 - Prob. 19PTSCh. 21.3 - Prob. 21CCCh. 21.3 - Prob. 22CCCh. 21.3 - Prob. 23CCCh. 21.4 - Prob. 24CCCh. 21.4 - Prob. 25CCCh. 21.4 - Prob. 26CCCh. 21.4 - Prob. 27CCCh. 21.4 - Prob. 28CCCh. 21.5 - Prob. 29CCCh. 21.5 - Prob. 30CCCh. 21.5 - Prob. 5LTSCh. 21.5 - Prob. 31PTSCh. 21.5 - Prob. 6LTSCh. 21.5 - Prob. 33PTSCh. 21.5 - Prob. 34ATSCh. 21.6 - Prob. 35CCCh. 21.6 - Prob. 36CCCh. 21.6 - Prob. 37CCCh. 21.6 - Prob. 7LTSCh. 21.6 - Prob. 38PTSCh. 21.7 - Prob. 8LTSCh. 21.7 - Prob. 42PTSCh. 21.7 - Prob. 43PTSCh. 21 - Prob. 47PPCh. 21 - Prob. 48PPCh. 21 - Prob. 49PPCh. 21 - Prob. 50PPCh. 21 - Prob. 51PPCh. 21 - Prob. 52PPCh. 21 - Prob. 53PPCh. 21 - Prob. 54PPCh. 21 - Prob. 55PPCh. 21 - Prob. 56PPCh. 21 - Prob. 57PPCh. 21 - Prob. 58PPCh. 21 - Prob. 59PPCh. 21 - Prob. 60PPCh. 21 - Prob. 61PPCh. 21 - Prob. 62PPCh. 21 - Prob. 63PPCh. 21 - Prob. 64PPCh. 21 - Prob. 65PPCh. 21 - Prob. 66PPCh. 21 - Prob. 67PPCh. 21 - Prob. 68PPCh. 21 - Prob. 69PPCh. 21 - Prob. 70PPCh. 21 - Prob. 71PPCh. 21 - Prob. 72PPCh. 21 - Prob. 73PPCh. 21 - Prob. 74PPCh. 21 - Prob. 75PPCh. 21 - Prob. 76PPCh. 21 - Prob. 77PPCh. 21 - Prob. 78PPCh. 21 - Prob. 79PPCh. 21 - Prob. 80PPCh. 21 - Prob. 81PPCh. 21 - Prob. 82PPCh. 21 - Prob. 83PPCh. 21 - Prob. 84PPCh. 21 - Prob. 85PPCh. 21 - Prob. 86PPCh. 21 - Prob. 87PPCh. 21 - Prob. 88PPCh. 21 - Prob. 97IPCh. 21 - Prob. 98IPCh. 21 - Prob. 99IPCh. 21 - Prob. 100IPCh. 21 - Prob. 101IPCh. 21 - Prob. 107IPCh. 21 - Prob. 108IPCh. 21 - Prob. 109IP
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