Explanation Write the expression of acceleration due to gravity at A ( g ) . g = g o ( R R + H + y ) 2 (I) Here, acceleration due to gravity is g , mean radius of earth is R and altitude is H . Write the expression of acceleration ( a ) . a = v d v d y v d v = a d y (II) Here, velocity is v and displacement is y . Conclusion: Substitute ( − g o ( R R + H + y ) 2 d y ) for a in Equation (II) and then integrate. ∫ v o 0 v d v = ∫ 0 h − g o ( R R + H + y ) 2 d y ( v 2 2 ) v o 0 = g o R 2 ( 1 R + H + y ) 0 h ( 0 2 2 − v o 2 2 ) = g o R 2 ( 1 R + H + h − 1 R + H + 0 ) ( − v o 2 2 ) = g o R 2 ( 1 R + H + h − 1 R + H ) ( − v o 2 2 ) = g o R 2 ( R + H − ( R + H + h ) ( R + H + h ) ( R + H ) ) ( − v o 2 2 ) = − g o R 2 ( h ( R + H + h ) ( R + H ) ) v o 2 = 2 g o R 2 ( h ( R + H + h ) ( R + H ) ) (III) Substitute 27000 km / hr for v 0 , 9

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ISBN: 9781119047315

Author: Bolton

Publisher: VST

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be create…

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Chapter 2.10, Problem 246RP

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The additional vertical height reached by the rocket before it starts its descent back to the earth.

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Chapter 2.10, Problem 245RP

Chapter 2.10, Problem 247RP

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