Electronics Fundamentals: Circuits, Devices & Applications
8th Edition
ISBN: 9780135072950
Author: Thomas L. Floyd, David Buchla
Publisher: Prentice Hall
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Chapter 21, Problem 8ST
To determine
To identify: Among the given options, the effect of increase in the given parameter of a strain gauge
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Question 3 AC Motor Drives [15]Calculate the instantaneous currents delivered by the inverter if the direct axiscurrent required at a particular instant is 8.66A and the quadrature current is5A. Derive all equations for the three currents.
A certain signal f(t) has the following PSD (assume 12 load):
Sp (w) = new + 8(w) - 1.5) + (w + 1.5)]
(a) What is the mean power in the bandwidth w≤2 rad/see?
(b) What is the mean power in the bandwidth -1.9 to 0.99 rad/sec?
Paress(w) dw
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Chapter 21 Solutions
Electronics Fundamentals: Circuits, Devices & Applications
Ch. 21 - A thermocouple can measure higher temperatures...Ch. 21 - Thermocouples are commonly used to measure body...Ch. 21 - An advantage of an RTD over a thermistor is that...Ch. 21 - Prob. 4TFQCh. 21 - A thermocouple signal conditioner must have high...Ch. 21 - Signal conditioning for temperature sensors...Ch. 21 - Prob. 7TFQCh. 21 - Absolute pressure is measured relative to the...Ch. 21 - In a sample-and-hold circuit, an analog value is...Ch. 21 - Prob. 10TFQ
Ch. 21 - A thermocouple a change in resistance for a change...Ch. 21 - In a thermocouple circuit, where each of the...Ch. 21 - A thermocouple signal conditioner is designed to...Ch. 21 - Prob. 4STCh. 21 - Prob. 5STCh. 21 - Prob. 6STCh. 21 - Prob. 7STCh. 21 - Prob. 8STCh. 21 - Prob. 9STCh. 21 - Prob. 10STCh. 21 - Prob. 11STCh. 21 - Prob. 12STCh. 21 - Prob. 13STCh. 21 - Prob. 14STCh. 21 - In an analog switch, the aperture time is the time...Ch. 21 - Prob. 16STCh. 21 - An analog signal must be sampled at a minimum rate...Ch. 21 - Prob. 18STCh. 21 - Prob. 19STCh. 21 - Prob. 20STCh. 21 - Prob. 21STCh. 21 - Three identical thermocouples are each exposed to...Ch. 21 - You have two thermocouples. One is a K type and...Ch. 21 - Determine the output voltage of the op-amp in...Ch. 21 - What should be the output voltage in Problem 3 if...Ch. 21 - Prob. 5PCh. 21 - Prob. 6PCh. 21 - Explain the difference in the results of Problems...Ch. 21 - Prob. 8PCh. 21 - A certain material being measured undergoes a...Ch. 21 - Explain how a strain gauge can be used to measure...Ch. 21 - Identify and compare the three symbols in Figure...Ch. 21 - Determine the output voltage waveform for the...Ch. 21 - Repeat Problem 12 for the waveforms in Figure...Ch. 21 - Name two ways an SCR can be placed in the...Ch. 21 - Sketch the VR waveform for the circuit in Figure...Ch. 21 - For the circuit in Figure 21-53, describe the...Ch. 21 - What change to the circuit in Figure 21-53 would...
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- (75 Marks) JA signal (t) is bond 7)(t)(t) and f(t), are band-limited to 1.2 kHz each. These signals are to be limited to 9.6 kHz, and three other signals transmitted by means of time-division multiplexing. Set up scheme for accomplishing this multiplexing requirement, with each signal sampled at its Nyquist rate. What must be the speed of the commutator (the output but ram-k bit/sec)? the minimum band width? (25 Marks)arrow_forwardDraw the digital modulation outputs, ASK Amplitude Shift Keying) FSK (Frequency Shift Keying) and PSK (Phase Shift Keying). For baseband and carriet frequency as shown 101 wwwwwwwwwwww 010 BASESAND basband CARRIER Carralarrow_forwardplease show full working. I've included the solutionarrow_forward
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- Can you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forwardCan you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forward
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