‘ Number of beta emission and amount of radiation in Ci ’ should be identified. Concept introduction: Disintegration of bismuth taking place and emission of alpha particles take place. Therefore, the mass which gets disintegrated can be calculated by deducting the mass left of Bi from initial mass of Bi as following. m 0 −m And thus, by multiplying the disintegrated mass with the Avogadro’s number of 210 g of Bi, the number of emission can be determined. Given: T 1 / 2 t = 13.5 d Mass of Bi = 1.2 g

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Answer 1

Question

Chapter 21, Problem 81E

Interpretation Introduction

Interpretation:

‘ Number of beta emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Disintegration of bismuth taking place and emission of alpha particles take place. Therefore, the mass which gets disintegrated can be calculated by deducting the mass left of Bi from initial mass of Bi as following.

m₀−m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 210 g of Bi, the number of emission can be determined.

Given:

$T_{1 / 2}$

t = 13.5 d

Mass of Bi = 1.2 g

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Answer 2

Question

Chapter 21, Problem 81E

Interpretation Introduction

Interpretation:

‘ Number of beta emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Disintegration of bismuth taking place and emission of alpha particles take place. Therefore, the mass which gets disintegrated can be calculated by deducting the mass left of Bi from initial mass of Bi as following.

m₀−m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 210 g of Bi, the number of emission can be determined.

Given:

$T_{1 / 2}$

t = 13.5 d

Mass of Bi = 1.2 g

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 21, Problem 81E

Interpretation Introduction

Interpretation:

‘ Number of beta emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Disintegration of bismuth taking place and emission of alpha particles take place. Therefore, the mass which gets disintegrated can be calculated by deducting the mass left of Bi from initial mass of Bi as following.

m₀−m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 210 g of Bi, the number of emission can be determined.

Given:

$T_{1 / 2}$

t = 13.5 d

Mass of Bi = 1.2 g

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 21, Problem 81E

Interpretation Introduction

Interpretation:

‘ Number of beta emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Disintegration of bismuth taking place and emission of alpha particles take place. Therefore, the mass which gets disintegrated can be calculated by deducting the mass left of Bi from initial mass of Bi as following.

m₀−m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 210 g of Bi, the number of emission can be determined.

Given:

$T_{1 / 2}$

t = 13.5 d

Mass of Bi = 1.2 g

Expert Solution & Answer

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Answer 5

Chapter 21, Problem 81E

Interpretation Introduction

Interpretation:

‘ Number of beta emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Disintegration of bismuth taking place and emission of alpha particles take place. Therefore, the mass which gets disintegrated can be calculated by deducting the mass left of Bi from initial mass of Bi as following.

m₀−m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 210 g of Bi, the number of emission can be determined.

Given:

$T_{1 / 2}$

t = 13.5 d

Mass of Bi = 1.2 g

Answer 6

Chapter 21, Problem 81E

Interpretation Introduction

Interpretation:

‘ Number of beta emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Disintegration of bismuth taking place and emission of alpha particles take place. Therefore, the mass which gets disintegrated can be calculated by deducting the mass left of Bi from initial mass of Bi as following.

m₀−m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 210 g of Bi, the number of emission can be determined.

Given:

$T_{1 / 2}$

t = 13.5 d

Mass of Bi = 1.2 g

Answer 7

Chapter 21, Problem 81E

Interpretation Introduction

Interpretation:

‘ Number of beta emission and amount of radiation in Ci’ should be identified.

Concept introduction:

Disintegration of bismuth taking place and emission of alpha particles take place. Therefore, the mass which gets disintegrated can be calculated by deducting the mass left of Bi from initial mass of Bi as following.

m₀−m

And thus, by multiplying the disintegrated mass with the Avogadro’s number of 210 g of Bi, the number of emission can be determined.

Given:

$T_{1 / 2}$

t = 13.5 d

Mass of Bi = 1.2 g

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 21 - Prob. 1SAQ Ch. 21 - Prob. 2SAQ Ch. 21 - Prob. 3SAQ Ch. 21 - Prob. 4SAQ Ch. 21 - Prob. 5SAQ Ch. 21 - Prob. 6SAQ Ch. 21 - Prob. 7SAQ Ch. 21 - Prob. 8SAQ Ch. 21 - Prob. 9SAQ Ch. 21 - Prob. 10SAQ

Solution Summary: The author explains that the number of beta emission and amount of radiation in Ci should be identified.

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Chapter 21 Solutions