The halogen which has the highest bond dissociation enthalpy is to be stated. Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in gaseous state) to give the separate atoms in gaseous state. As number of bond increase, length gets shorter and bond energy increases. Therefore, H − H bonds are fairly easy to break and makes hydrogen gas reactive. Nitrogen has a triple bond, which takes a lot of energy to break and is pretty much inert.

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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10 Consider the following reaction: CH3OH(g) CO(g) + 2H2(g) (Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.) Part A Calculate AG for this reaction at 25 °C under the following conditions: PCH₂OH Pco PH2 0.815 atm = 0.140 atm 0.170 atm Express your answer in kilojoules to three significant figures. Ο ΑΣΦ AG = -150 Submit Previous Answers Request Answer □? kJ × Incorrect; Try Again; 2 attempts remaining Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship: AGrxn = AGrxn + RTInQ, AGxn+RTInQ, where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a is the reaction quotient. Provide Feedback Next >

Answer 1

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Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 21, Problem 75PS

Interpretation Introduction

Interpretation: The halogen which has the highest bond dissociation enthalpy is to be stated.

Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in gaseous state) to give the separate atoms in gaseous state.

As number of bond increase, length gets shorter and bond energy increases.

Therefore,

H−H bonds are fairly easy to break and makes hydrogen gas reactive.

Nitrogen has a triple bond, which takes a lot of energy to break and is pretty much inert.

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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10 Consider the following reaction: CH3OH(g) CO(g) + 2H2(g) (Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.) Part A Calculate AG for this reaction at 25 °C under the following conditions: PCH₂OH Pco PH2 0.815 atm = 0.140 atm 0.170 atm Express your answer in kilojoules to three significant figures. Ο ΑΣΦ AG = -150 Submit Previous Answers Request Answer □? kJ × Incorrect; Try Again; 2 attempts remaining Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship: AGrxn = AGrxn + RTInQ, AGxn+RTInQ, where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a is the reaction quotient. Provide Feedback Next >

Identify and provide a brief explanation of Gas Chromatography (GC) within the context of chemical analysis of food. Incorporate the specific application name, provide a concise overview of sample preparation methods, outline instrumental parameters and conditions ultilized, and summarise the outcomes and findings achieved through this analytical approach.

Identify and provide a concise explanation of the concept of signal-to-noise ratio (SNR) in the context of chemical analysis. Provide specific examples.

Answer 2

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Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 21, Problem 75PS

Interpretation Introduction

Interpretation: The halogen which has the highest bond dissociation enthalpy is to be stated.

Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in gaseous state) to give the separate atoms in gaseous state.

As number of bond increase, length gets shorter and bond energy increases.

Therefore,

H−H bonds are fairly easy to break and makes hydrogen gas reactive.

Nitrogen has a triple bond, which takes a lot of energy to break and is pretty much inert.

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Answer 3

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 21, Problem 75PS

Interpretation Introduction

Interpretation: The halogen which has the highest bond dissociation enthalpy is to be stated.

Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in gaseous state) to give the separate atoms in gaseous state.

As number of bond increase, length gets shorter and bond energy increases.

Therefore,

H−H bonds are fairly easy to break and makes hydrogen gas reactive.

Nitrogen has a triple bond, which takes a lot of energy to break and is pretty much inert.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 4

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 21, Problem 75PS

Interpretation Introduction