Operation of the pulse oximeter (see previous problem ). The transmission of light energy as it passes through a solution of light-absorbing molecules is described by the Beer-Lambert law I = I 0 10 − ∈ C L or log 10 ( I I 0 ) = − ∈ C L which gives the decrease in intensity I in terms of the distance L the light has traveled through a fluid with a concentration C of the light-absorbing molecule. The quantity ∈ is called the extinction coefficient, and its value depends on the frequency of the light. (It has units of m 2 /mol.) Assume the extinction coefficient for 660-nm light passing through a solution of oxygenated hemoglobin is identical to the coefficient for 940-nm light passing through deoxygenated hemoglobin. Also assume 940-nm light has zero absorption ( ∈ = 0) in oxygenated hemoglobin and 660-nm light has zero absorption in deoxygenated hemoglobin. If 33% of the energy of the red source and 76% of the infrared energy is transmitted through the blood, what is the fraction of hemoglobin that is oxygenated?
Operation of the pulse oximeter (see previous problem ). The transmission of light energy as it passes through a solution of light-absorbing molecules is described by the Beer-Lambert law I = I 0 10 − ∈ C L or log 10 ( I I 0 ) = − ∈ C L which gives the decrease in intensity I in terms of the distance L the light has traveled through a fluid with a concentration C of the light-absorbing molecule. The quantity ∈ is called the extinction coefficient, and its value depends on the frequency of the light. (It has units of m 2 /mol.) Assume the extinction coefficient for 660-nm light passing through a solution of oxygenated hemoglobin is identical to the coefficient for 940-nm light passing through deoxygenated hemoglobin. Also assume 940-nm light has zero absorption ( ∈ = 0) in oxygenated hemoglobin and 660-nm light has zero absorption in deoxygenated hemoglobin. If 33% of the energy of the red source and 76% of the infrared energy is transmitted through the blood, what is the fraction of hemoglobin that is oxygenated?
Solution Summary: The author explains the formula to calculate the percentage of radiation transmitted, the extinction co-efficient, and the length of the solution.
Operation of the pulse oximeter (see previous problem). The transmission of light energy as it passes through a solution of light-absorbing molecules is described by the Beer-Lambert law
I
=
I
0
10
−
∈
C
L
or
log
10
(
I
I
0
)
=
−
∈
C
L
which gives the decrease in intensity I in terms of the distance L the light has traveled through a fluid with a concentration C of the light-absorbing molecule. The quantity ∈ is called the extinction coefficient, and its value depends on the frequency of the light. (It has units of m2/mol.) Assume the extinction coefficient for 660-nm light passing through a solution of oxygenated hemoglobin is identical to the coefficient for 940-nm light passing through deoxygenated hemoglobin. Also assume 940-nm light has zero absorption (∈ = 0) in oxygenated hemoglobin and 660-nm light has zero absorption in deoxygenated hemoglobin. If 33% of the energy of the red source and 76% of the infrared energy is transmitted through the blood, what is the fraction of hemoglobin that is oxygenated?
Look at the answer and please show all work step by step
3. As a woman, who's eyes are h = 1.5 m above the ground, looks down the road sees a tree with height
H = 9.0 m. Below the tree is what appears to be a reflection of the tree. The observation of this apparent
reflection gives the illusion of water on the roadway. This effect is commonly called a mirage. Use the results of questions 1 and 2 and the principle of ray reversibility to analyze the diagram below. Assume that light leaving the top of the tree bends toward the horizontal until it just grazes ground level. After that, the ray bends upward eventually reaching the woman's eyes. The woman interprets this incoming light as if it came from an image of the tree. Determine the size, H', of the image. (Answer 8.8 m)
please show all work step by step
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