(a)
Interpretation:
The peptides obtained from the cleavage of given peptide chain by carboxypeptidase A has to be given.
Concept introduction:
Amino acids are linked each other by peptide bonds is called protein (one or more peptide bonds). Peptide bonds are amide bonds, in which carbonyl group of one amino acid bonded to amino group of other amino acid. The chain of the protein is drawn in such a way that left end is occupied by free amino group (say N-terminal) and right side of the chain is occupied by carbonyl group (say C-terminal).
Exopeptidases cleave peptide bonds that are not at the end.
Carboxypeptidase A is an exopeptidase, which cleave the peptide bond of C-terminal amino acid except arginine and lysine.
(b)
Interpretation:
The peptides obtained from the cleavage of given peptide chain by cyanogen bromide has to be given
Concept introduction:
Amino acids are linked each other by peptide bonds is called protein (one or more peptide bonds). Peptide bonds are amide bonds, in which carbonyl group of one amino acid bonded to amino group of other amino acid. The chain of the protein is drawn in such a way that left end is occupied by free amino group (say N-terminal) and right side of the chain is occupied by carbonyl group (say C-terminal).
Cyanogen bromide cleaves the C-terminal peptide of Methionine in a peptide chain.
(c)
Interpretation:
The peptides obtained from the cleavage of given peptide chain by trypsin has to be given.
Concept introduction:
Amino acids are linked each other by peptide bonds is called protein (one or more peptide bonds). Peptide bonds are amide bonds, in which carbonyl group of one amino acid bonded to amino group of other amino acid. The chain of the protein is drawn in such a way that left end is occupied by free amino group (say N-terminal) and right side of the chain is occupied by carbonyl group (say C-terminal).
Endopeptidases cleave peptide bonds that are not at the end.
Trypsin is an endopeptidase, which cleave the C-side peptide bond of positively charged side chains such as arginine and lysine.
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Chapter 21 Solutions
CHEM 262 ORG CHEM EBOOK DIGITAL DELIVERY
- These are synthesis questions. You need to show how the starting material can be converted into the product(s) shown. You may use any reactions we have learned. Show all the reagents you need. Show each molecule synthesized along the way and be sure to pay attention to the regiochemistry and stereochemistry preferences for each reaction. If a racemic molecule is made along the way, you need to draw both enantiomers and label the mixture as "racemic". All of the carbon atoms of the products must come from the starting material! ? H Harrow_forwardQ5: Draw every stereoisomer for 1-bromo-2-chloro-1,2-difluorocyclopentane. Clearly show stereochemistry by drawing the wedge-and-dashed bonds. Describe the relationship between each pair of the stereoisomers you have drawn.arrow_forwardClassify each pair of molecules according to whether or not they can participate in hydrogen bonding with one another. Participate in hydrogen bonding CH3COCH3 and CH3COCH2CH3 H2O and (CH3CH2)2CO CH3COCH3 and CH₂ CHO Answer Bank Do not participate in hydrogen bonding CH3CH2OH and HCHO CH3COCH2CH3 and CH3OHarrow_forward
- Nonearrow_forwardGiven the standard enthalpies of formation for the following substances, determine the reaction enthalpy for the following reaction. 4A (g) + 2B (g) → 2C (g) + 7D (g) AHrxn =?kJ Substance AH in kJ/mol A (g) - 20.42 B (g) + 32.18 C (g) - 72.51 D (g) - 17.87arrow_forwardDetermine ASran for Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(aq) given the following information: Standard Entropy Values of Various Substance Substance So (J/mol • K) 60.9 Zn(s) HCl(aq) 56.5 130.58 H2(g) Zn2+(aq) -106.5 55.10 CI (aq)arrow_forward
- 3) Catalytic hydrogenation of the compound below produced the expected product. However, a byproduct with molecular formula C10H12O is also formed in small quantities. What is the by product?arrow_forwardWhat is the ΔHorxn of the reaction? NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq) ΔHorxn 1= ________ kJ/molarrow_forward= +92kJ ΔΗ = +170kJ Use the following reactions: 2NH3(9) N2(g) + 3H2(g) → 11/N2(g) + 2H2O (1) → NO2(g) + 2H2(g) Determine the DH° of this reaction: NO2(g) + H2(g) → 2(g) → 2H2O(l) + NH3(9) ΔΗarrow_forward
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