A long jumper leaves the ground at an angle of 20 o above the horizontal at a speed of11 m/sec. The height of the jumper can be modeled by h x = − 0.046 x 2 + 0.364 x , where h is the jumper’s height in meters and x is the horizontal distance from the point of launch. a. At what horizontal distance from the point of launch does the maximum height occur? Round to 2 decimal places. b. What is the maximum height of the long jumper? Round to 2 decimal places. c. What is the length of the jump? Round to 1 decimal place.
A long jumper leaves the ground at an angle of 20 o above the horizontal at a speed of11 m/sec. The height of the jumper can be modeled by h x = − 0.046 x 2 + 0.364 x , where h is the jumper’s height in meters and x is the horizontal distance from the point of launch. a. At what horizontal distance from the point of launch does the maximum height occur? Round to 2 decimal places. b. What is the maximum height of the long jumper? Round to 2 decimal places. c. What is the length of the jump? Round to 1 decimal place.
Solution Summary: The author calculates the horizontal distance from the point of launch at which the maximum height of the jumper occurs using f(x)=-0.046x2+0.364x.
A long jumper leaves the ground at an angle of
20
o
above the horizontal at a speed of11 m/sec. The height of the jumper can be modeled by
h
x
=
−
0.046
x
2
+
0.364
x
,
where h is the jumper’s height in meters and x is the horizontal distance from the point of launch.
a. At what horizontal distance from the point of launch does the maximum height occur? Round to 2 decimal places.
b. What is the maximum height of the long jumper? Round to 2 decimal places.
c. What is the length of the jump? Round to 1 decimal place.
=
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