(a) Interpretation: The given carboxylic acids is to be prepared by using malonic ester synthesis. Concept introduction: The malonic ester synthesis is a method which is used to convert diethyl malonate into a carboxylic acid . NaOEt is a strong base. It abstracts a proton from the alpha carbon of an ester molecule to forms an enolate.

Question

1. Calculate the accurate monoisotopic mass (using all 1H, 12C, 14N, 160 and 35CI) for your product using the table in your lab manual. Don't include the Cl, since you should only have [M+H]*. Compare this to the value you see on the LC-MS printout. How much different are they? 2. There are four isotopic peaks for the [M+H]* ion at m/z 240, 241, 242 and 243. For one point of extra credit, explain what each of these is and why they are present. 3. There is a fragment ion at m/z 184. For one point of extra credit, identify this fragment and confirm by calculating the accurate monoisotopic mass. 4. The UV spectrum is also at the bottom of your printout. For one point of extra credit, look up the UV spectrum of bupropion on Google Images and compare to your spectrum. Do they match? Cite your source. 5. For most of you, there will be a second chromatographic peak whose m/z is 74 (to a round number). For one point of extra credit, see if you can identify this molecule as well and confirm by…

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Chapter 21, Problem 43P

Interpretation Introduction

(a)

Interpretation: The given carboxylic acids is to be prepared by using malonic ester synthesis.

Concept introduction: The malonic ester synthesis is a method which is used to convert diethyl malonate into a carboxylic acid. NaOEt is a strong base. It abstracts a proton from the alpha carbon of an ester molecule to forms an enolate.

Interpretation Introduction

(b)

Interpretation: The given carboxylic acids are to be prepared by using malonic ester synthesis.

Concept introduction: The malonic ester synthesis is a method which is used to convert diethyl malonate into a carboxylic acid. NaOEt is a strong base. It abstracts a proton from the alpha carbon of an ester molecule to forms an enolate.

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1. Calculate the accurate monoisotopic mass (using all 1H, 12C, 14N, 160 and 35CI) for your product using the table in your lab manual. Don't include the Cl, since you should only have [M+H]*. Compare this to the value you see on the LC-MS printout. How much different are they? 2. There are four isotopic peaks for the [M+H]* ion at m/z 240, 241, 242 and 243. For one point of extra credit, explain what each of these is and why they are present. 3. There is a fragment ion at m/z 184. For one point of extra credit, identify this fragment and confirm by calculating the accurate monoisotopic mass. 4. The UV spectrum is also at the bottom of your printout. For one point of extra credit, look up the UV spectrum of bupropion on Google Images and compare to your spectrum. Do they match? Cite your source. 5. For most of you, there will be a second chromatographic peak whose m/z is 74 (to a round number). For one point of extra credit, see if you can identify this molecule as well and confirm by…

Please draw, not just describe!

can you draw each step on a piece of a paper please this is very confusing to me