Explanation Given data: Gravitational acceleration constant ( g ) is 9.80 m s 2 . Mass ( m ) is 0.20 kg . Angle ( θ ) is 30 ° . Length of the rod ( L ) is 1.6 m . Magnitude of the magnetic field ( B ) is 0.050 T . Formula used: Write the expression for the magnitude of the magnetic force ( F ) . F = I L B sin θ (1) Here, I is the current, θ is the angle of the wire with respect to the field, B is magnitude of the magnetic field, and L is the length of the rod. Write the expression for the magnitude of the net force by Newton’s second law. − F cos θ + m g sin θ = 0 (2) Here, g is the gravitational acceleration constant, which is known as 9.80 m s 2 , and m is the mass. Explanation: Here, the charge moves perpendicular to the magnetic field, so the angle ( θ ) is 90.0 ° . Substitute 90.0 ° for θ in equation (1), F = I L B sin 90

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ISBN: 9781119326342

Author: CUTNELL

Publisher: WILEY

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Chapter 21, Problem 41P

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Chapter 21, Problem 40P

Chapter 21, Problem 42P

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Ch. 21.5 - Prob. 11CYU Ch. 21.7 - Prob. 13CYU Ch. 21.7 - Prob. 14CYU Ch. 21.7 - Prob. 15CYU Ch. 21.7 - Prob. 16CYU Ch. 21.7 - Prob. 17CYU Ch. 21.7 - Prob. 18CYU Ch. 21 - Prob. 2FC Ch. 21 - Prob. 3FC Ch. 21 - Prob. 6FC Ch. 21 - Prob. 8FC Ch. 21 - Prob. 12FC Ch. 21 - Prob. 13FC Ch. 21 - Prob. 16FC Ch. 21 - Prob. 17FC Ch. 21 - Prob. 1P Ch. 21 - Prob. 2P Ch. 21 - Prob. 3P Ch. 21 - Prob. 4P Ch. 21 - Prob. 5P Ch. 21 - Prob. 6P Ch. 21 - 7. A magnetic field has a magnitude of 1.2 × 10?3...Ch. 21 - Prob. 8P Ch. 21 - Prob. 9P Ch. 21 - Prob. 10P Ch. 21 - Prob. 11P Ch. 21 - Prob. 12P Ch. 21 - Prob. 13P Ch. 21 - 14. A charged particle with a charge-to-mass ratio...Ch. 21 - Prob. 15P Ch. 21 - Prob. 16P Ch. 21 - Prob. 17P Ch. 21 - Prob. 18P Ch. 21 - Prob. 19P Ch. 21 - Prob. 20P Ch. 21 - Prob. 21P Ch. 21 - Prob. 22P Ch. 21 - Prob. 23P Ch. 21 - Prob. 24P Ch. 21 - Prob. 25P Ch. 21 - Prob. 26P Ch. 21 - Prob. 27P Ch. 21 - *28. Review Conceptual Example 2 as background for...Ch. 21 - Prob. 30P Ch. 21 - Prob. 31P Ch. 21 - Prob. 32P Ch. 21 - 33. A horizontal wire of length 0.53 m, carrying a...Ch. 21 - Prob. 34P Ch. 21 - Prob. 35P Ch. 21 - Prob. 37P Ch. 21 - Prob. 38P Ch. 21 - Prob. 39P Ch. 21 - Prob. 40P Ch. 21 - Prob. 41P Ch. 21 - Prob. 42P Ch. 21 - Prob. 43P Ch. 21 - Prob. 44P Ch. 21 - Prob. 45P Ch. 21 - Prob. 46P Ch. 21 - Prob. 48P Ch. 21 - Prob. 49P Ch. 21 - Prob. 50P Ch. 21 - Prob. 53P Ch. 21 - Prob. 54P Ch. 21 - Prob. 55P Ch. 21 - Prob. 56P Ch. 21 - Prob. 57P Ch. 21 - Prob. 58P Ch. 21 - Prob. 59P Ch. 21 - Prob. 60P Ch. 21 - Prob. 61P Ch. 21 - Prob. 63P Ch. 21 - Prob. 64P Ch. 21 - Prob. 65P Ch. 21 - Prob. 66P Ch. 21 - Prob. 67P Ch. 21 - Prob. 68P Ch. 21 - Prob. 69P Ch. 21 - Prob. 72AP Ch. 21 - Prob. 73AP Ch. 21 - Prob. 74AP Ch. 21 - Prob. 75AP Ch. 21 - Prob. 76AP Ch. 21 - Prob. 77AP Ch. 21 - Prob. 78AP Ch. 21 - Prob. 79AP Ch. 21 - Prob. 80AP Ch. 21 - Prob. 89TP Ch. 21 - Prob. 90TP

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