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Chemistry: Atoms First V1
1st Edition
ISBN: 9781259383120
Author: Burdge
Publisher: McGraw Hill Custom
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Question
Chapter 21, Problem 21.79QP
Interpretation Introduction
Interpretation:
The percent composition of the given mixture has to be calculated.
Concept introduction:
Percent composition: Percent composition is nothing but the percent by mass of each element in a compound.
Use the following formula to calculate percent composition of a given mixture.
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Students have asked these similar questions
You have now performed a liquid-liquid extraction protocol in Experiment 4. In doing so, you
manipulated and exploited the acid-base chemistry of one or more of the compounds in your
mixture to facilitate their separation into different phases. The key to understanding how liquid-
liquid extractions work is by knowing which layer a compound is in, and in what protonation state.
The following liquid-liquid extraction is different from the one you performed in Experiment
4, but it uses the same type of logic. Your task is to show how to separate apart Compound
A and Compound B.
. Complete the following flowchart of a liquid-liquid extraction. Handwritten work is
encouraged.
•
Draw by hand (neatly) only the appropriate organic compound(s) in the boxes.
.
Specify the reagent(s)/chemicals (name is fine) and concentration as required in Boxes 4
and 5.
•
Box 7a requires the solvent (name is fine).
•
Box 7b requires one inorganic compound.
• You can neatly complete this assignment by hand and…
b) Elucidate compound D w) mt at 170 nd shows c-1 stretch at 550cm;'
The compound has the ff electronic transitions: 0%o* and no a*
1H NMR Spectrum
(CDCl3, 400 MHz)
3.5
3.0
2.5
2.0
1.5
1.0
0.5 ppm
13C{H} NMR Spectrum
(CDCl3, 100 MHz)
Solvent
80
70
60
50
40
30
20
10
0 ppm
ppm
¹H-13C me-HSQC Spectrum
ppm
(CDCl3, 400 MHz)
5
¹H-¹H COSY Spectrum
(CDCl3, 400 MHz)
0.5
10
3.5
3.0
2.5
2.0
1.5 1.0
10
15
20
20
25
30
30
-35
-1.0
1.5
-2.0
-2.5
3.0
-3.5
0.5
ppm
3.5
3.0
2.5
2.0
1.5
1.0
0.5
ppm
Show work with explanation. don't give Ai generated solution
Chapter 21 Solutions
Chemistry: Atoms First V1
Ch. 21 - Prob. 21.1QPCh. 21 - Prob. 21.2QPCh. 21 - Prob. 21.3QPCh. 21 - Prob. 21.4QPCh. 21 - Prob. 21.5QPCh. 21 - Prob. 21.6QPCh. 21 - Prob. 21.7QPCh. 21 - Describe with examples the chemical and...Ch. 21 - Prob. 21.9QPCh. 21 - Prob. 21.10QP
Ch. 21 - Prob. 21.11QPCh. 21 - Prob. 21.12QPCh. 21 - Prob. 21.13QPCh. 21 - Prob. 21.14QPCh. 21 - Prob. 21.15QPCh. 21 - Prob. 21.16QPCh. 21 - Prob. 21.17QPCh. 21 - Prob. 21.18QPCh. 21 - Which of the following compounds would require...Ch. 21 - Prob. 21.20QPCh. 21 - Prob. 21.21QPCh. 21 - Prob. 21.22QPCh. 21 - Prob. 21.23QPCh. 21 - Prob. 21.24QPCh. 21 - Prob. 21.25QPCh. 21 - Prob. 21.26QPCh. 21 - Prob. 21.27QPCh. 21 - Prob. 21.28QPCh. 21 - Prob. 21.29QPCh. 21 - Prob. 21.30QPCh. 21 - Prob. 21.31QPCh. 21 - Prob. 21.32QPCh. 21 - Prob. 21.33QPCh. 21 - Prob. 21.34QPCh. 21 - Prob. 21.35QPCh. 21 - Prob. 21.36QPCh. 21 - Prob. 21.37QPCh. 21 - Prob. 21.38QPCh. 21 - Prob. 21.39QPCh. 21 - Prob. 21.40QPCh. 21 - Prob. 21.41QPCh. 21 - Prob. 21.42QPCh. 21 - Prob. 21.43QPCh. 21 - Prob. 21.44QPCh. 21 - Prob. 21.45QPCh. 21 - Prob. 21.46QPCh. 21 - Prob. 21.47QPCh. 21 - With the Hall process, how many hours will it take...Ch. 21 - The overall reaction for the electrolytic...Ch. 21 - Prob. 21.50QPCh. 21 - Prob. 21.51QPCh. 21 - In basic solution, aluminum metal is a strong...Ch. 21 - Prob. 21.53QPCh. 21 - Prob. 21.54QPCh. 21 - Prob. 21.55QPCh. 21 - Prob. 21.56QPCh. 21 - Prob. 21.57QPCh. 21 - Prob. 21.58QPCh. 21 - Prob. 21.59QPCh. 21 - Prob. 21.60QPCh. 21 - Prob. 21.61QPCh. 21 - Prob. 21.62QPCh. 21 - Prob. 21.63QPCh. 21 - Prob. 21.64QPCh. 21 - Prob. 21.65QPCh. 21 - Prob. 21.66QPCh. 21 - Prob. 21.67QPCh. 21 - Prob. 21.68QPCh. 21 - Prob. 21.69QPCh. 21 - Prob. 21.70QPCh. 21 - Prob. 21.71QPCh. 21 - Prob. 21.72QPCh. 21 - Prob. 21.73QPCh. 21 - The following are two reaction schemes involving...Ch. 21 - Prob. 21.75QPCh. 21 - Prob. 21.76QPCh. 21 - Prob. 21.77QPCh. 21 - Prob. 21.78QPCh. 21 - Prob. 21.79QPCh. 21 - Prob. 21.80QPCh. 21 - Prob. 21.81QPCh. 21 - Chemical tests of four metals A, B, C, and D show...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Redraw the flowchartarrow_forwardredraw the flowchart with boxes and molecules written in themarrow_forwardPart I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400arrow_forward
- • Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peakarrow_forwardCould you redraw these and also explain how to solve them for me pleasarrow_forwardNonearrow_forward
- Draw the curved-arrow mechanism with the drawings of the molecules, not just abbreviations. -NO₂ Sn, HCl (aq) E D H (CH3CO)₂O -NH2 CH3arrow_forwardWhat is/are the product(s) of the following reaction? Select all that apply. * HI A B C OD OH A B OH D Carrow_forwardIn the image, the light blue sphere represents a mole of hydrogen atoms, the purple or teal spheres represent a mole of a conjugate base. A light blue sphere by itself is H+. Assuming there is 2.00 L of solution, answer the following: The Ka of the left & right solution is? The pH of the left & right solution is? The acid on the left & right is what kind of acid?arrow_forward
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