Chapter 21, Problem 21.6QP

(a)

Interpretation Introduction

Interpretation: It should be identified the value of X in the given following nuclear equation.

Concept Introduction:

In balancing any nuclear equation, we must balance the total of all atomic numbers and the total of all mass. If we know the atomic numbers and mass numbers of all but one of the species in a nuclear equation

The alpha (${}_{\text{2}}^{\text{4}}\text{α}$) –particle has two protons and two neutrons. So its atomic number is 2 and its mass number is 4.

For a beta- particle ($\text{β}{}^{\text{0}}$) is the negative unit charge, which atomic number is decreased by one unit and no change in atomic mass.

For neutron particle (${}_{\text{0}}^{\text{1}}\text{n}$) no change in the atomic number only the atomic mass increased by one unit.

To Determine: Identify the value of X.

(b)

Interpretation Introduction

Interpretation: It should be identified the value of X in the given following nuclear equation.

Concept Introduction:

In balancing any nuclear equation, we must balance the total of all atomic numbers and the total of all mass. If we know the atomic numbers and mass numbers of all but one of the species in a nuclear equation

The alpha (${}_{\text{2}}^{\text{4}}\text{α}$) –particle has two protons and two neutrons. So its atomic number is 2 and its mass number is 4.

For a beta- particle ($\text{β}{}^{\text{0}}$) is the negative unit charge, which atomic number is decreased by one unit and no change in atomic mass.

For neutron particle (${}_{\text{0}}^{\text{1}}\text{n}$) no change in the atomic number only the atomic mass increased by one unit.

To Determine: Identify the value of X.

(c)

Interpretation Introduction

Interpretation: It should be identified the value of X in the given following nuclear equation.

Concept Introduction:

In balancing any nuclear equation, we must balance the total of all atomic numbers and the total of all mass. If we know the atomic numbers and mass numbers of all but one of the species in a nuclear equation

The alpha (${}_{\text{2}}^{\text{4}}\text{α}$) –particle has two protons and two neutrons. So its atomic number is 2 and its mass number is 4.

For a beta- particle ($\text{β}{}^{\text{0}}$) is the negative unit charge, which atomic number is decreased by one unit and no change in atomic mass.

For neutron particle (${}_{\text{0}}^{\text{1}}\text{n}$) no change in the atomic number only the atomic mass increased by one unit.

(d)

Interpretation Introduction

Interpretation: It should be identified the value of X in the given following nuclear equation.

Concept Introduction:

In balancing any nuclear equation, we must balance the total of all atomic numbers and the total of all mass. If we know the atomic numbers and mass numbers of all but one of the species in a nuclear equation

The alpha (${}_{\text{2}}^{\text{4}}\text{α}$) –particle has two protons and two neutrons. So its atomic number is 2 and its mass number is 4.

For a beta- particle ($\text{β}{}^{\text{0}}$) is the negative unit charge, which atomic number is decreased by one unit and no change in atomic mass.

For neutron particle (${}_{\text{0}}^{\text{1}}\text{n}$) no change in the atomic number only the atomic mass increased by one unit.

To Determine: Identify the value of X.

Species in a nuclear equation

To identify:  the value of X in each nuclear equation