Chapter 21, Problem 21.68QP

(a)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction has to be written.

Concept introduction:

• There is a law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
• The concept of writing a balanced chemical equation is depends on conversion of reactants into products.
• First write the reaction from the given information.
• Then count the number of atoms of each element in reactants as well as products.
• Finally obtained values could place it as coefficients of reactants as well as products.

Answer to Problem 21.68QP

The balanced equation for the given reaction was ${\text{Al}}_{\text{2}}{{\text{(CO}}_{\text{3}}\text{)}}_{\text{3(s) }}\to {\text{Al}}_{\text{2}}{\text{O}}_{\text{3(s) }}{\text{+ 3CO}}_{\text{2(g)}}$

Explanation of Solution

To write the balanced equation for heating of ${\text{Al}}_{\text{2}}{{\text{(CO}}_{\text{3}}\text{)}}_{\text{3}}$

By heating of heating of aluminum carbonate it will produce aluminum oxide and carbon dioxides as follows.

${\text{Al}}_{\text{2}}{{\text{(CO}}_{\text{3}}\text{)}}_{\text{3(s) }}\to {\text{Al}}_{\text{2}}{\text{O}}_{\text{3(s) }}{\text{+ CO}}_{\text{2(g)}}$

Here, the reaction is unbalanced. So we need to balance it.  To balance the reaction, calculate the number of atoms present in left side and right side.  Finally, obtained values could place it as coefficients of reactants as well as products.  The balanced equation is

${\text{Al}}_{\text{2}}{{\text{(CO}}_{\text{3}}\text{)}}_{\text{3(s) }}\to {\text{Al}}_{\text{2}}{\text{O}}_{\text{3(s) }}{\text{+ 3CO}}_{\text{2(g)}}$

(b)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction has to be written.

Concept introduction:

• There is a law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
• The concept of writing a balanced chemical equation is depends on conversion of reactants into products.
• First write the reaction from the given information.
• Then count the number of atoms of each element in reactants as well as products.
• Finally obtained values could place it as coefficients of reactants as well as products.

Answer to Problem 21.68QP

The balanced equation for the given reaction was ${\text{AlCl}}_{\text{3}}{}_{\text{(s)}}{\text{ + 3K}}_{\text{(s)}}\to {\text{Al}}_{\text{(s)}}{\text{ + 3KCl}}_{\text{(s)}}$

Explanation of Solution

To write the balanced equation for the reaction between ${\text{AlCl}}_{\text{3}}$ and $\text{K}$

Aluminum chloride reacts with potassium to form metallic aluminum and potassium chloride.

${\text{AlCl}}_{\text{3}}{}_{\text{(s)}}{\text{ + 3K}}_{\text{(s)}}\to {\text{Al}}_{\text{(s)}}{\text{ + 3KCl}}_{\text{(s)}}$

Here, the reaction is unbalanced.  So we need to balance it.  To balance the reaction, calculate the number of atoms present in left side and right side.  Finally, obtained values could place it as coefficients of reactants as well as products.  The balanced equation is

${\text{AlCl}}_{\text{3}}{}_{\text{(s)}}{\text{ + 3K}}_{\text{(s)}}\to {\text{Al}}_{\text{(s)}}{\text{ + 3KCl}}_{\text{(s)}}$

(c)

Interpretation Introduction

Interpretation:

The balanced equation for the given reaction has to be written.

Concept introduction:

• There is a law for conversion of mass in a chemical reaction i.e., the mass of total amount of the product should be equal to the total mass of the reactants.
• The concept of writing a balanced chemical equation is depends on conversion of reactants into products.
• First write the reaction from the given information.
• Then count the number of atoms of each element in reactants as well as products.
• Finally obtained values could place it as coefficients of reactants as well as products.

Answer to Problem 21.68QP

The balanced equation for the given reaction was ${\text{Ca(OH)}}_{\text{2(aq) }}{\text{+ Na}}_{\text{2}}{\text{CO}}_{\text{3(aq)}}\to {\text{ CaCO}}_{\text{3(s)}}{\text{ + 2NaOH}}_{\text{(aq)}}$

Explanation of Solution

To write the balanced equation for the reaction between ${\text{Na}}_{\text{2}}{\text{CO}}_{\text{3}}{\text{ and Ca(OH)}}_{\text{2}}$

Sodium carbonate reacts with calcium carbonate to produce calcium carbonate and sodium hydroxide.

${\text{Ca(OH)}}_{\text{2(aq) }}{\text{+ Na}}_{\text{2}}{\text{CO}}_{\text{3(aq)}}\to {\text{ CaCO}}_{\text{3(s)}}{\text{ + NaOH}}_{\text{(aq)}}$

Here, the reaction is unbalanced. So we need to balance it.  To balance the reaction, calculate the number of atoms present in left side and right side.  Finally, obtained values could place it as coefficients of reactants as well as products.  The balanced equation is

${\text{Ca(OH)}}_{\text{2(aq) }}{\text{+ Na}}_{\text{2}}{\text{CO}}_{\text{3(aq)}}\to {\text{ CaCO}}_{\text{3(s)}}{\text{ + 2NaOH}}_{\text{(aq)}}$