
Concept explainers
A 0.450-g sample of steel contains manganese as an impurity. The sample is dissolved in acidic solution and the manganese is oxidized to the permanganate ion

Interpretation:
The mass percent of manganese in the given sample has to be calculated.
Concept introduction:
Mass percent: To express the concentration of a component in a mixture we can use mass percent. Dividing the grams of solute by grams of solution and then multiply with 100 to obtain percentage.
The formula to calculate mass percent is
Answer to Problem 21.57QP
The mass percent of manganese in the given sample is
Explanation of Solution
The reaction between iron ion and permanagate and its balanced equation is represented as follows.
To determine percent by mass of manganese
From the above equation we can say that 1 mole of permanganate is equalent to 5 moles of iron (II) ion.
From this we can calculate the original amount of ion (II) is
Now, determine the excess amount of iron (II) with the help of balanced equation.
From the above equation we can say that 1 mole of dicromate is equalent to 6 moles of iron (II) ion. The excess amount of iron (II) is calculated as follows
The consumed amount of iron is
From the above values, find the mass of manganese
Therefore, the percent by mass of manganese is
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Chapter 21 Solutions
Chemistry
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