Chapter 21, Problem 21.22QP

(a)

Interpretation Introduction

To determine: A balanced nuclear equation that describes $\text{α}$ decay of $\text{boron}-12$.

Interpretation: A balanced nuclear equation which describes $\text{α}$ decay of $\text{boron}-12$ is to be given.

Concept introduction: The decay with $\text{α}$ particle results in formation of helium atom. It possesses two protons and two neutrons. So, isotope that is formed during reaction has mass number decreased by four, whereas its atomic number is decreased by two.

(b)

Interpretation Introduction

To determine: a balanced nuclear equation that describes $\text{β}$ decay of $\text{boron}-12$.

Interpretation: A balanced nuclear equation which describes $\text{β}$ decay of $\text{boron}-12$ is to be given.

Concept introduction: The decay with $\text{β}$ particle results in the formation of isotope that has one extra atomic number

(c)

Interpretation Introduction

To determine: a balanced nuclear equation that describes positron emission of $\text{manganese-50}$.

Interpretation: A balanced nuclear equation which describes positron emission of $\text{manganese-50}$. to be given.

Concept introduction: The positron emission results in formation of isotope that consist one less atomic number than parent atom.

(d)

Interpretation Introduction

To determine: a balanced nuclear equation that describes electron captured by $\text{cadmium-}104$.

Interpretation: A balanced nuclear equation which describes electron captured by $\text{cadmium-}104$ is to be given.

Concept introduction: Electron capture results in the formation of isotope that has one less electron but number of protons and neutrons remain same in daughter isotope.