Engineering Your Future: Comprehensive
Engineering Your Future: Comprehensive
8th Edition
ISBN: 9780199348015
Author: William C. Oakes, Les L. Leone
Publisher: Oxford University Press
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Chapter 21, Problem 21.1EAA
To determine

To study the role of non- engineering courses in an engineering career.

Expert Solution & Answer
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Explanation of Solution

There are a number of non- engineering courses like literature, music, social sciences, art, history, philosophy, management.

It is very important for a student who is pursuing engineering to study various non-engineering courses along with engineering courses. Reasons why one should study non-engineering courses along with engineering courses are as follows:

  1. It helps to improve your broadness.
  2. It helps to improve your perspective
  3. It enriches our personal lives with new knowledge, insights, and a keener appreciation of beauty.
  4. It helps to improve your skills.
  5. It improves your sense of duty and responsibility.

So, it is very important to study non- engineering courses along with engineering courses it develops a sense of discipline, time management, leadership skills, managerial skills, other technical knowledge’s.

Conclusion:

In short it makes a student an all-rounder. Such a student will be able to rise to the pinnacles of success.

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Given answers to be: i) 14.65 kN; 6.16 kN; 8.46 kN ii) 8.63 kN; 9.88 kN iii) Bearing 6315 for B1 & B2, or Bearing 6215 for B1
(b) A steel 'hot rolled structural hollow section' column of length 5.75 m, has the cross-section shown in Figure Q.5(b) and supports a load of 750 kN. During service, it is subjected to axial compression loading where one end of the column is effectively restrained in position and direction (fixed) and the other is effectively held in position but not in direction (pinned). i) Given that the steel has a design strength of 275 MN/m², determine the load factor for the structural member based upon the BS5950 design approach using Datasheet Q.5(b). [11] ii) Determine the axial load that can be supported by the column using the Rankine-Gordon formula, given that the yield strength of the material is 280 MN/m² and the constant *a* is 1/30000. [6] 300 600 2-300 mm wide x 5 mm thick plates. Figure Q.5(b) L=5.75m Pinned Fixed
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Engineering Your Future: Comprehensive

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