Student Solutions Manual for Ebbing/Gammon's General Chemistry, 11th
Student Solutions Manual for Ebbing/Gammon's General Chemistry, 11th
11th Edition
ISBN: 9781305673472
Author: Darrell Ebbing, Steven D. Gammon
Publisher: Cengage Learning
Question
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Chapter 21, Problem 21.148QP

(a)

Interpretation Introduction

Interpretation:

The chemical equation for the given reaction has to be written

Concept Introduction:

Balanced Chemical equation:

A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.

To Write: The chemical equation for the given reaction

(a)

Expert Solution
Check Mark

Answer to Problem 21.148QP

The chemical equation for the given reaction is: 2Ca(s) + O2(g)2CaO(s)

Explanation of Solution

Given data:

Burning of calcium metal in oxygen.

Chemical Equation:

The chemical equation for the reaction of burning of calcium metal in oxygen can be written as follows,

2Ca(s) + O2(g)2CaO(s)

Conclusion

The chemical equation for the given reaction is written as: 2Ca(s) + O2(g)2CaO(s)

(b)

Interpretation Introduction

Interpretation:

The chemical equation for the given reaction has to be written

Concept Introduction:

Balanced Chemical equation:

A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.

To Write: The chemical equation for the given reaction

(b)

Expert Solution
Check Mark

Answer to Problem 21.148QP

The chemical equation for the given reaction is: 4PH3(g) + 8O2(g)P4O10(S) + 6H2O(g)

Explanation of Solution

Given data:

Phosphine, PH3 burns in excess oxygen

Chemical Equation:

The chemical equation for the reaction of burning of phosphine in excess of oxygen can be written as follows,

4PH3(g) + 8O2(g)P4O10(S) + 6H2O(g)

Conclusion

The chemical equation for the given reaction is written as: 4PH3(g) + 8O2(g)P4O10(S) + 6H2O(g)

(c)

Interpretation Introduction

Interpretation:

The chemical equation for the given reaction has to be written

Concept Introduction:

Balanced Chemical equation:

A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.

To Write: The chemical equation for the given reaction

(c)

Expert Solution
Check Mark

Answer to Problem 21.148QP

The chemical equation for the given reaction is: 4HOCH2CH2NH2(l) + 13O2(g)8CO2(g) + 14H2O(g) + 2N2(g)

Explanation of Solution

Given data:

Ethanolamine, HOCH2CH2NH2 burns in excess of oxygen.

The N atom of ethanolamine ends up as N2

Chemical Equation:

The chemical equation for the reaction of burning of ethanolamine in excess oxygen by giving out nitrogen gas as one of the product can be written as follows,

4HOCH2CH2NH2(l) + 13O2(g)8CO2(g) + 14H2O(g) + 2N2(g)

Conclusion

The chemical equation for the given reaction is written as: 4HOCH2CH2NH2(l) + 13O2(g)8CO2(g) + 14H2O(g) + 2N2(g)

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Chapter 21 Solutions

Student Solutions Manual for Ebbing/Gammon's General Chemistry, 11th

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