Chapter 21, Problem 1SAQ

Interpretation Introduction

Interpretation:

To find out daughter nuclide forms when polonium-214 undergoes alpha decay.

Concept Introduction: In alpha decay, the mass number gets reduced by 4 units whereas the atomic number reduces by 2 units.

The alpha particle is helium, ${}_{\text{2}}^{\text{4}}\text{He}$ .

Explanation of Solution

Therefore, options (a) are correct

Reasons for the correct statement:Option (a): $$

$\begin{array}{l}\text{P}\text{o}\to ?+\text{H}\text{e}\\ \text{P}\text{o}\to ?+\text{H}\text{e}\\ \text{P}\text{o}\to \text{P}\text{b+}\text{H}\text{e}\end{array}$

Thus, the correct answer is Option (a) $\text{P}\text{b}$ .

Reasons for the incorrect statement:

In alpha decay mass number reduces by 4 but mass number is same in b and c options.

Hence, option (b), (c) and (d) are wrong answers.