The wavelength of the periodic wave with high frequency.

Question

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Answer 1

Question

Chapter 21, Problem 1RQ

To determine

The wavelength of the periodic wave with high frequency.

Expert Solution & Answer

Answer to Problem 1RQ

Shorter.

Explanation of Solution

Wavelength is the distance of one completed wave (crest to crest) and frequency is the inverse of the period, $(f=1T)$ .

Wavelength is inversely proportional to the frequency of the periodic wave. In other words, if wavelength is high then the frequency is low and vice versa.

Writing mathematically,

$λ∝1f$

Therefore, the higher frequency periodic waves will have a shorter wavelength.

Conclusion:

For a given type of wave, periodic waves with higher frequency will have shorter wavelengths than those with lower frequencies.

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Answer 2

Question

Chapter 21, Problem 1RQ

To determine

The wavelength of the periodic wave with high frequency.

Expert Solution & Answer

Answer to Problem 1RQ

Shorter.

Explanation of Solution

Wavelength is the distance of one completed wave (crest to crest) and frequency is the inverse of the period, $(f=1T)$ .

Wavelength is inversely proportional to the frequency of the periodic wave. In other words, if wavelength is high then the frequency is low and vice versa.

Writing mathematically,

$λ∝1f$

Therefore, the higher frequency periodic waves will have a shorter wavelength.

Conclusion:

For a given type of wave, periodic waves with higher frequency will have shorter wavelengths than those with lower frequencies.

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Answer 3

Question

Chapter 21, Problem 1RQ

To determine

The wavelength of the periodic wave with high frequency.

Expert Solution & Answer

Answer to Problem 1RQ

Shorter.

Explanation of Solution

Wavelength is the distance of one completed wave (crest to crest) and frequency is the inverse of the period, $(f=1T)$ .

Wavelength is inversely proportional to the frequency of the periodic wave. In other words, if wavelength is high then the frequency is low and vice versa.

Writing mathematically,

$λ∝1f$

Therefore, the higher frequency periodic waves will have a shorter wavelength.

Conclusion:

For a given type of wave, periodic waves with higher frequency will have shorter wavelengths than those with lower frequencies.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 21, Problem 1RQ

To determine

The wavelength of the periodic wave with high frequency.

Expert Solution & Answer

Answer to Problem 1RQ

Shorter.

Explanation of Solution

Wavelength is the distance of one completed wave (crest to crest) and frequency is the inverse of the period, $(f=1T)$ .

Wavelength is inversely proportional to the frequency of the periodic wave. In other words, if wavelength is high then the frequency is low and vice versa.

Writing mathematically,

$λ∝1f$

Therefore, the higher frequency periodic waves will have a shorter wavelength.

Conclusion:

For a given type of wave, periodic waves with higher frequency will have shorter wavelengths than those with lower frequencies.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 21, Problem 1RQ

To determine

The wavelength of the periodic wave with high frequency.

Expert Solution & Answer

Answer to Problem 1RQ

Shorter.

Explanation of Solution

Wavelength is the distance of one completed wave (crest to crest) and frequency is the inverse of the period, $(f=1T)$ .

Wavelength is inversely proportional to the frequency of the periodic wave. In other words, if wavelength is high then the frequency is low and vice versa.

Writing mathematically,

$λ∝1f$

Therefore, the higher frequency periodic waves will have a shorter wavelength.

Conclusion:

For a given type of wave, periodic waves with higher frequency will have shorter wavelengths than those with lower frequencies.

Answer 6

Chapter 21, Problem 1RQ

To determine

The wavelength of the periodic wave with high frequency.

Expert Solution & Answer

Answer to Problem 1RQ

Shorter.

Explanation of Solution

Wavelength is the distance of one completed wave (crest to crest) and frequency is the inverse of the period, $(f=1T)$ .

Wavelength is inversely proportional to the frequency of the periodic wave. In other words, if wavelength is high then the frequency is low and vice versa.

Writing mathematically,

$λ∝1f$

Therefore, the higher frequency periodic waves will have a shorter wavelength.

Conclusion:

For a given type of wave, periodic waves with higher frequency will have shorter wavelengths than those with lower frequencies.

Answer 7

Chapter 21, Problem 1RQ

To determine

The wavelength of the periodic wave with high frequency.

Answer 8

Expert Solution & Answer

Answer to Problem 1RQ

Shorter.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Wavelength is the distance of one completed wave (crest to crest) and frequency is the inverse of the period, $(f=1T)$ .

Wavelength is inversely proportional to the frequency of the periodic wave. In other words, if wavelength is high then the frequency is low and vice versa.

Writing mathematically,

$λ∝1f$

Therefore, the higher frequency periodic waves will have a shorter wavelength.

Conclusion:

For a given type of wave, periodic waves with higher frequency will have shorter wavelengths than those with lower frequencies.