The reason why ac voltage is often described using the root mean square value rather than average voltage
Answer to Problem 1QAP
Because many AC voltages are sinusoidal, average voltage is often zero. So root mean square value is used to not to cancel off negative values from positive values.
Explanation of Solution
Introduction:
The graph of an AC voltage versus time
Many AC voltages are sinusoidal. Therefore the average voltage is zero because equal amounts of voltages lie above and below the x axis. Therefore negative and positive values will cancel off when calculating the average value. If we take the square of each and every voltage before averaging, all the square voltages will be positive. So the negative values do not cancel out the positive values. Therefore ac voltage is often described using the root mean square value rather than average voltage.
Conclusion:
Because many AC voltages are sinusoidal, average voltage is often zero. So root mean square value is used to not to cancel off negative values from positive values.
Want to see more full solutions like this?
Chapter 21 Solutions
COLLEGE PHYSICS,VOLUME 1
- 6. 6. There are 1000 turns on the primary side of a transformer and 200 turns on thesecondary side. If 440 V are supplied to the primary winding, what is the voltageinduced in the secondary winding? Is this a step-up or step-down transformer? 7. 80 V are supplied to the primary winding of a transformer that has 50 turns. If thesecondary side has 50,000 turns, what is the voltage induced on the secondary side?Is this a step-up or step-down transformer? 8. There are 50 turns on the primary side of a transformer and 500 turns on thesecondary side. The current through the primary winding is 6 A. What is the turnsratio of this transformer? What is the current, in milliamps, through the secondarywinding?9. The current through the primary winding on a transformer is 5 A. There are 1000turns on the primary winding and 20 turns on the secondary winding. What is theturns ratio of this transformer? What is the current, in amps, through the secondarywinding?arrow_forwardNo chatgpt plsarrow_forwardWhat is the current, in amps, across a conductor that has a resistance of10 Ω and a voltage of 20 V? 2. A conductor draws a current of 100 A and a resistance of 5 Ω. What is thevoltageacross the conductor? 3. What is the resistance, in ohm’s, of a conductor that has a voltage of 80 kVand acurrent of 200 mA? 4. An x-ray imaging system that draws a current of 90 A is supplied with 220V. What is the power consumed? 5. An x-ray is produced using 800 mA and 100 kV. What is the powerconsumed in kilowatts?arrow_forward
- ՍՈՈՒ XVirginia Western Community Coll x P Course Home X + astering.pearson.com/?courseld=13289599#/ Figure y (mm) x=0x = 0.0900 m All ✓ Correct For either the time for one full cycle is 0.040 s; this is the period. Part C - ON You are told that the two points x = 0 and x = 0.0900 m are within one wavelength of each other. If the wave is moving in the +x-direction, determine the wavelength. Express your answer to two significant figures and include the appropriate units. 0 t(s) λ = Value m 0.01 0.03 0.05 0.07 Copyright © 2025 Pearson Education Inc. All rights reserved. 日 F3 F4 F5 1775 % F6 F7 B F8 Submit Previous Answers Request Answer ? × Incorrect; Try Again; 3 attempts remaining | Terms of Use | Privacy Policy | Permissions | Contact Us | Cookie Settings 28°F Clear 4 9:23 PM 1/20/2025 F9 prt sc F10 home F11 end F12 insert delete 6 7 29 & * ( 8 9 0 t = back Οarrow_forwardPart C Find the height yi from which the rock was launched. Express your answer in meters to three significant figures. Learning Goal: To practice Problem-Solving Strategy 4.1 for projectile motion problems. A rock thrown with speed 12.0 m/s and launch angle 30.0 ∘ (above the horizontal) travels a horizontal distance of d = 19.0 m before hitting the ground. From what height was the rock thrown? Use the value g = 9.800 m/s2 for the free-fall acceleration. PROBLEM-SOLVING STRATEGY 4.1 Projectile motion problems MODEL: Is it reasonable to ignore air resistance? If so, use the projectile motion model. VISUALIZE: Establish a coordinate system with the x-axis horizontal and the y-axis vertical. Define symbols and identify what the problem is trying to find. For a launch at angle θ, the initial velocity components are vix=v0cosθ and viy=v0sinθ. SOLVE: The acceleration is known: ax=0 and ay=−g. Thus, the problem becomes one of…arrow_forwardPhys 25arrow_forward
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegeCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning