Explanation Given: A particle moves with varying velocity along a straight line and at time t, the particle is at f ( t ) distance. Calculation: Let the particle moves in the curve of function f ( t ) be defined as f ( t ) = sin ( 2 π t 5 ) The given condition to be satisfied is the average velocity is equal to the instantaneous velocity at exactly two points, Average velocity = Instantaneous velocity f ( 5 ) − f ( 0 ) 5 − 0 = d sin ( 2 π t 5 ) d t sin 2 π − sin 0 5 = cos ( 2 π t 5 ) ( 2 π 5 ) 0 = cos ( 2 π t 5

Applied Calculus, 6e WileyPLUS + Loose-leaf

6th Edition

ISBN: 9781119408901

Author: Deborah Hughes-Hallett, Andrew M. Gleason, Patti Frazer Lock, Daniel E. Flath

Publisher: Wiley (WileyPLUS Products)

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Chapter 2.1, Problem 15P

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To draw the time-distance graph in which the average velocity of the particle is same as the instantaneous velocity at exactly two times between t=0 and t=5.

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Chapter 2.1, Problem 14P

Chapter 2.1, Problem 16P

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Chapter 2 Solutions

Applied Calculus, 6e WileyPLUS + Loose-leaf

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To draw the time-distance graph in which the average velocity of the particle is same as the instantaneous velocity at exactly two times between t = 0 and t = 5 .

Solution Summary: The author explains how to draw a time-distance graph in which the average velocity of the particle is equal to the instantaneous velocity at exactly two times between t=0 and

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To draw the time-distance graph in which the average velocity of the particle is same as the instantaneous velocity at exactly two times between t=0 and t=5.

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Chapter 2 Solutions