Describe the behavior of the bulb in the two situations below. i. The switch is first moved to position 1 . Describe the behavior of the bulb from just after the switch is closed until a long time later . Explain. ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later . Explain your reasoning.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

01:11

Students have asked these similar questions

Sketch a sine wave depicting 3 seconds of wave activity for a 5 Hz tone. Sketch the resulting complex wave form that results from the combination of the following two waves. Is this wave periodic or aperiodic? USE GRAPH PAPER!

Required information A bungee jumper leaps from a bridge and undergoes a series of oscillations. Assume g = 9.78 m/s². If a 60.0-kg jumper uses a bungee cord that has an unstretched length of 30.1 m and she jumps from a height of 45.2 m above a river, coming to rest just a few centimeters above the water surface on the first downward descent, what is the period of the oscillations? Assume the bungee cord follows Hooke's law.

Required information The leg bone (femur) breaks under a compressive force of about 6.50 × 104 N for a human and 12.3 × 104 N for a horse. The human femur has a compressive strength of 160 MPa, whereas the horse femur has a compressive strength of 140 MPa. What is the effective cross-sectional area of the femur in a horse? (Note: Since the center of the femur contains bone marrow, which has essentially no compressive strength, the effective cross-sectional area is about 80% of the total cross-sectional area.) cm2

Answer 2

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

01:11

Answer 3

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

01:11

Answer 4

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

01:11

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 8

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 9

(i)

Expert Solution

Answer 10

(i)

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Answer 13

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 14

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 15

(ii)

Expert Solution

Answer 16

(ii)

Expert Solution

Answer 17

Expert Solution

Answer 18

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Answer 19

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.